Tuple<T1,T2,T3,T4>(T1, T2, T3, T4) 构造函数
定义
重要
一些信息与预发行产品相关,相应产品在发行之前可能会进行重大修改。 对于此处提供的信息,Microsoft 不作任何明示或暗示的担保。
初始化 Tuple<T1,T2,T3,T4> 类的新实例。
public:
Tuple(T1 item1, T2 item2, T3 item3, T4 item4);
public Tuple (T1 item1, T2 item2, T3 item3, T4 item4);
new Tuple<'T1, 'T2, 'T3, 'T4> : 'T1 * 'T2 * 'T3 * 'T4 -> Tuple<'T1, 'T2, 'T3, 'T4>
Public Sub New (item1 As T1, item2 As T2, item3 As T3, item4 As T4)
参数
- item1
- T1
此元组的第一个组件的值。
- item2
- T2
此元组的第二个组件的值。
- item3
- T3
此元组的第三个组件的值。
- item4
- T4
元组的第四个组件的值。
注解
还可以使用静态 Tuple.Create<T1,T2,T3,T4>(T1, T2, T3, T4) 方法实例化 4 元组对象,而无需显式指定其组件的类型。 下面的示例使用Tuple.Create<T1,T2,T3,T4>(T1, T2, T3, T4)此方法实例化其组件的类型DoubleStringDouble为 4 元组,以及。Double
var tuple4 = Tuple.Create("New York", 32.68, 51.87, 76.3);
Console.WriteLine("{0}: Hi {1}, Lo {2}, Ave {3}",
tuple4.Item1, tuple4.Item4, tuple4.Item2,
tuple4.Item3);
// Displays New York: Hi 76.3, Lo 32.68, Ave 51.87
let tuple4 =
Tuple.Create("New York", 32.68, 51.87, 76.3)
printfn $"{tuple4.Item1}: Hi {tuple4.Item4}, Lo {tuple4.Item2}, Ave {tuple4.Item3}"
// Displays New York: Hi 76.3, Lo 32.68, Ave 51.87
Dim tuple4 = Tuple.Create("New York", 32.68, 51.87, 76.3)
Console.WriteLine("{0}: Hi {1}, Lo {2}, Ave {3}",
tuple4.Item1, tuple4.Item4, tuple4.Item2,
tuple4.Item3)
' Displays New York: Hi 76.3, Lo 32.68, Ave 51.87
这相当于对类构造函数的 Tuple<T1,T2,T3,T4> 以下调用。
var tuple4 = new Tuple<string, double, double, double>
("New York", 32.68, 51.87, 76.3);
Console.WriteLine("{0}: Hi {1}, Lo {2}, Ave {3}",
tuple4.Item1, tuple4.Item4, tuple4.Item2,
tuple4.Item3);
// Displays New York: Hi 76.3, Lo 32.68, Ave 51.87
let tuple4 =
Tuple<string, double, double, double>("New York", 32.68, 51.87, 76.3)
printfn $"{tuple4.Item1}: Hi {tuple4.Item4}, Lo {tuple4.Item2}, Ave {tuple4.Item3}"
// Displays New York: Hi 76.3, Lo 32.68, Ave 51.87
Dim tuple4 = New Tuple(Of String, Double, Double, Double) _
("New York", 32.68, 51.87, 76.3)
Console.WriteLine("{0}: Hi {1}, Lo {2}, Ave {3}",
tuple4.Item1, tuple4.Item4, tuple4.Item2,
tuple4.Item3)
' Displays New York: Hi 76.3, Lo 32.68, Ave 51.87