通过

Tuple<T1,T2,T3,T4,T5,T6>.Item5 属性

  • 参考

定义

命名空间:
System
程序集:
System.Runtime.dll
程序集:
mscorlib.dll
程序集:
netstandard.dll

获取当前 Tuple<T1,T2,T3,T4,T5,T6> 对象的第五个分量的值。

public:
 property T5 Item5 { T5 get(); };
public T5 Item5 { get; }
member this.Item5 : 'T5
Public ReadOnly Property Item5 As T5

属性值

T5

当前 Tuple<T1,T2,T3,T4,T5,T6> 对象的第五个组件的值。

示例

以下示例定义了一组 Tuple<T1,T2,T3,T4,T5,T6> 对象，其组件包含从 1960 年到 2000 年 (纽约、芝加哥和) 洛杉矶三个城市的人口数据。 然后，它会显示一个列出数据的表。 若要在 1990 年显示总体，它将检索 Item5 每个 Tuple<T1,T2,T3,T4,T5,T6> 对象的属性值。

using System;
using System.Text.RegularExpressions;

public class Class1
{
   public static void Main()
   {
      // Create tuples containing population data for New York, Chicago, 
      // and Los Angeles, 1960-2000.
      Tuple<string, int, int, int, int, int>[] cities =
           { Tuple.Create("New York", 7781984, 7894862, 7071639, 7322564, 8008278),
             Tuple.Create("Los Angeles", 2479015, 2816061, 2966850, 3485398, 3694820),
             Tuple.Create("Chicago", 3550904, 3366957, 3005072, 2783726, 2896016) };

      // Display tuple data in table.
      string header = "Population in";
      Console.WriteLine("{0,-12} {1,60}", 
                        "City", new String('-',(60-header.Length)/2) + header + 
                                new String('-', (60-header.Length)/2));
      Console.WriteLine("{0,25}{1,12}{2,12}{3,12}{4,12}\n", 
                        "1960", "1970", "1980", "1990", "2000");         

      foreach (var city in cities)                      
         Console.WriteLine("{0,-12} {1,12:N0}{2,12:N0}{3,12:N0}{4,12:N0}{5,12:N0}", 
                           city.Item1, city.Item2, city.Item3, city.Item4, 
                           city.Item5, city.Item6);
   }
}
// The example displays the following output:
//    City          -----------------------Population in-----------------------
//                         1960        1970        1980        1990        2000
//    
//    New York        7,781,984   7,894,862   7,071,639   7,322,564   8,008,278
//    Los Angeles     2,479,015   2,816,061   2,966,850   3,485,398   3,694,820
//    Chicago         3,550,904   3,366,957   3,005,072   2,783,726   2,896,016

open System

// Create tuples containing population data for New York, Chicago, 
// and Los Angeles, 1960-2000.
let cities =
    [| Tuple.Create("New York", 7781984, 7894862, 7071639, 7322564, 8008278)
       Tuple.Create("Los Angeles", 2479015, 2816061, 2966850, 3485398, 3694820)
       Tuple.Create("Chicago", 3550904, 3366957, 3005072, 2783726, 2896016) |]

// Display tuple data in table.
let header = "Population in"
printfn $"""{"City",-12} {String('-',(60 - header.Length) / 2) + header + String('-', (60 - header.Length) / 2),60}"""
printfn "%25s%12s%12s%12s%12s\n" "1960" "1970" "1980" "1990" "2000"         

for city in cities do
    printfn $"{city.Item1,-12} {city.Item2,12:N0}{city.Item3,12:N0}{city.Item4,12:N0}{city.Item5,12:N0}{city.Item6,12:N0}"
// The example displays the following output:
//    City          -----------------------Population in-----------------------
//                         1960        1970        1980        1990        2000
//    
//    New York        7,781,984   7,894,862   7,071,639   7,322,564   8,008,278
//    Los Angeles     2,479,015   2,816,061   2,966,850   3,485,398   3,694,820
//    Chicago         3,550,904   3,366,957   3,005,072   2,783,726   2,896,016

Module Example
   Public Sub Main()
      ' Create tuples containing population data for New York, Chicago, 
      ' and Los Angeles, 1960-2000.
      Dim cities() =
           { Tuple.Create("New York", 7781984, 7894862, 
                          7071639, 7322564, 8008278),
             Tuple.Create("Los Angeles", 2479015, 2816061, 
                          2966850, 3485398, 3694820),
             Tuple.Create("Chicago", 3550904, 3366957, 
                          3005072, 2783726, 2896016) }

      ' Display tuple data in table.
      Dim header As String = "Population in"
      Console.WriteLine("{0,-12} {1,60}", 
                        "City", New String("-"c,(60-header.Length)\2) + header + _
                                New String("-"c, (60-header.Length)\2))
      Console.WriteLine("{0,25}{1,12}{2,12}{3,12}{4,12}", 
                        "1960", "1970", "1980", "1990", "2000")                  
      Console.WriteLine()
      For Each city In cities                      
         Console.WriteLine("{0,-12} {1,12:N0}{2,12:N0}{3,12:N0}{4,12:N0}{5,12:N0}", 
                           city.Item1, city.Item2, city.Item3, city.Item4, 
                           city.Item5, city.Item6)
      Next
   End Sub
End Module
' The example displays the following output:
'    City          -----------------------Population in-----------------------
'                         1960        1970        1980        1990        2000
'    
'    New York        7,781,984   7,894,862   7,071,639   7,322,564   8,008,278
'    Los Angeles     2,479,015   2,816,061   2,966,850   3,485,398   3,694,820
'    Chicago         3,550,904   3,366,957   3,005,072   2,783,726   2,896,016

注解

可以通过以下两种方式之一动态确定组件的类型 Item5 ：

适用于