Uri.GetLeftPart(UriPartial) 方法
定义
重要
一些信息与预发行产品相关,相应产品在发行之前可能会进行重大修改。 对于此处提供的信息,Microsoft 不作任何明示或暗示的担保。
获取 Uri 实例的指定部分。
public:
System::String ^ GetLeftPart(UriPartial part);
public string GetLeftPart (UriPartial part);
member this.GetLeftPart : UriPartial -> string
Public Function GetLeftPart (part As UriPartial) As String
参数
- part
- UriPartial
指定要返回的 URI 部分末尾的枚举值之一。
返回
Uri 实例的指定部分。
例外
当前 Uri 实例不是绝对实例。
指定的 part
无效。
示例
以下示例创建 一个 Uri 实例,并将路径写入控制台。
// Create Uri
Uri^ uriAddress = gcnew Uri( "http://www.contoso.com/index.htm#search" );
Console::WriteLine( uriAddress->Fragment );
Console::WriteLine( "Uri {0} the default port ", uriAddress->IsDefaultPort ? (String^)"uses" : "does not use" );
Console::WriteLine( "The path of this Uri is {0}", uriAddress->GetLeftPart( UriPartial::Path ) );
Console::WriteLine( "Hash code {0}", uriAddress->GetHashCode() );
// The example displays output similar to the following:
// #search
// Uri uses the default port
// The path of this Uri is http://www.contoso.com/index.htm
// Hash code -988419291
// Create Uri
Uri uriAddress = new Uri("http://www.contoso.com/index.htm#search");
Console.WriteLine(uriAddress.Fragment);
Console.WriteLine("Uri {0} the default port ", uriAddress.IsDefaultPort ? "uses" : "does not use");
Console.WriteLine("The path of this Uri is {0}", uriAddress.GetLeftPart(UriPartial.Path));
Console.WriteLine("Hash code {0}", uriAddress.GetHashCode());
// The example displays output similar to the following:
// #search
// Uri uses the default port
// The path of this Uri is http://www.contoso.com/index.htm
// Hash code -988419291
// Create Uri
let uriAddress = Uri "http://www.contoso.com/index.htm#search"
printfn $"{uriAddress.Fragment}"
printfn $"""Uri {if uriAddress.IsDefaultPort then "uses" else "does not use"} the default port """
printfn $"The path of this Uri is {uriAddress.GetLeftPart UriPartial.Path}"
printfn $"Hash code {uriAddress.GetHashCode()}"
// The example displays output similar to the following:
// #search
// Uri uses the default port
// The path of this Uri is http://www.contoso.com/index.htm
// Hash code -988419291
' Create Uri
Dim uriAddress As New Uri("http://www.contoso.com/index.htm#search")
Console.WriteLine(uriAddress.Fragment)
Console.WriteLine("Uri {0} the default port ", If(uriAddress.IsDefaultPort, "uses", "does not use"))
Console.WriteLine("The path of this Uri is {0}", uriAddress.GetLeftPart(UriPartial.Path))
Console.WriteLine("Hash code {0}", uriAddress.GetHashCode())
' The example displays output similar to the following:
' #search
' Uri uses the default port
' The path of this Uri is http://www.contoso.com/index.htm
' Hash code -988419291
注解
方法 GetLeftPart 返回一个字符串,其中包含 URI 字符串的最左侧部分,以 指定的 part
部分结尾。
GetLeftPart 在以下情况下包括分隔符:
- Scheme 包括方案分隔符。
- Authority 不包括路径分隔符。
- Path 包括路径分隔符以及原始 URI 中到查询或片段分隔符的任何分隔符。
- Query 包括 , Path以及查询及其分隔符。
以下示例演示 URI 以及使用 Scheme、Authority、 Path或 Query调用 GetLeftPart 的结果。
URI | Scheme | 颁发机构 | 路径 | 查询 |
---|---|---|---|---|
http://www.contoso.com/index.htm?date=today |
http:// |
http://www.contoso.com |
http://www.contoso.com/index.htm |
http://www.contoso.com/index.htm?date=today |
http://www.contoso.com/index.htm#main |
http:// |
http://www.contoso.com |
http://www.contoso.com/index.htm |
http://www.contoso.com/index.htm |
mailto:user@contoso.com?subject=uri |
mailto: |
<none> |
mailto:user@contoso.com |
mailto:user@contoso.com?subject=uri |
nntp://news.contoso.com/123456@contoso.com |
nntp:// |
nntp://news.contoso.com |
nntp://news.contoso.com/123456@contoso.com |
nntp://news.contoso.com/123456@contoso.com |
news:123456@contoso.com |
news: |
<none> |
news:123456@contoso.com |
news:123456@contoso.com |
file://server/filename.ext |
file:// |
file://server |
file://server/filename.ext |
file://server/filename.ext |