DataGridViewColumnStateChangedEventArgs.StateChanged 属性

定义

获取新列的状态。

public:
 property System::Windows::Forms::DataGridViewElementStates StateChanged { System::Windows::Forms::DataGridViewElementStates get(); };
public System.Windows.Forms.DataGridViewElementStates StateChanged { get; }
member this.StateChanged : System.Windows.Forms.DataGridViewElementStates
Public ReadOnly Property StateChanged As DataGridViewElementStates

属性值

DataGridViewElementStates 值之一。

示例

下面的代码示例演示了此成员的用法。 在此示例中,事件处理程序报告事件的发生情况 DataGridView.ColumnStateChanged 。 此报表可帮助你了解事件发生的时间,并可以帮助你进行调试。 若要报告多个事件或频繁发生的事件,请考虑将 MessageBox.Show 替换为 Console.WriteLine 或将消息追加到多行 TextBox

若要运行示例代码,请将其粘贴到包含名为 DataGridView1的 类型的DataGridView实例的项目中。 然后,确保事件处理程序与 DataGridView.ColumnStateChanged 事件相关联。

private void DataGridView1_ColumnStateChanged(Object sender, DataGridViewColumnStateChangedEventArgs e) {

System.Text.StringBuilder messageBoxCS = new System.Text.StringBuilder();
messageBoxCS.AppendFormat("{0} = {1}", "Column", e.Column );
messageBoxCS.AppendLine();
messageBoxCS.AppendFormat("{0} = {1}", "StateChanged", e.StateChanged );
messageBoxCS.AppendLine();
MessageBox.Show(messageBoxCS.ToString(), "ColumnStateChanged Event" );
}
Private Sub DataGridView1_ColumnStateChanged(sender as Object, e as DataGridViewColumnStateChangedEventArgs) _ 
     Handles DataGridView1.ColumnStateChanged

    Dim messageBoxVB as New System.Text.StringBuilder()
    messageBoxVB.AppendFormat("{0} = {1}", "Column", e.Column)
    messageBoxVB.AppendLine()
    messageBoxVB.AppendFormat("{0} = {1}", "StateChanged", e.StateChanged)
    messageBoxVB.AppendLine()
    MessageBox.Show(messageBoxVB.ToString(),"ColumnStateChanged Event")

End Sub

适用于

另请参阅