SyntaxToken.WithLeadingTrivia 方法

定義

命名空間:

Microsoft.CodeAnalysis

組件:

Microsoft.CodeAnalysis.dll

套件:

Microsoft.CodeAnalysis.Common v4.9.2

多載

WithLeadingTrivia(SyntaxTrivia[])	使用指定的前置 Trivia，從這個權杖建立新的權杖。
WithLeadingTrivia(SyntaxTriviaList)	從這個權杖建立新的權杖，並指定前置 Trivia。
WithLeadingTrivia(IEnumerable<SyntaxTrivia>)	從這個權杖建立新的權杖，並指定前置 Trivia。

WithLeadingTrivia(SyntaxTrivia[])

Source:

SyntaxToken.cs

使用指定的前置 Trivia，從這個權杖建立新的權杖。

public:
 Microsoft::CodeAnalysis::SyntaxToken WithLeadingTrivia(... cli::array <Microsoft::CodeAnalysis::SyntaxTrivia> ^ trivia);

public Microsoft.CodeAnalysis.SyntaxToken WithLeadingTrivia (params Microsoft.CodeAnalysis.SyntaxTrivia[]? trivia);

member this.WithLeadingTrivia : Microsoft.CodeAnalysis.SyntaxTrivia[] -> Microsoft.CodeAnalysis.SyntaxToken

Public Function WithLeadingTrivia (ParamArray trivia As SyntaxTrivia()) As SyntaxToken

參數

trivia

SyntaxTrivia[]

傳回

SyntaxToken

WithLeadingTrivia(SyntaxTriviaList)

Source:

SyntaxToken.cs

從這個權杖建立新的權杖，並指定前置 Trivia。

public:
 Microsoft::CodeAnalysis::SyntaxToken WithLeadingTrivia(Microsoft::CodeAnalysis::SyntaxTriviaList trivia);

public Microsoft.CodeAnalysis.SyntaxToken WithLeadingTrivia (Microsoft.CodeAnalysis.SyntaxTriviaList trivia);

member this.WithLeadingTrivia : Microsoft.CodeAnalysis.SyntaxTriviaList -> Microsoft.CodeAnalysis.SyntaxToken

Public Function WithLeadingTrivia (trivia As SyntaxTriviaList) As SyntaxToken

參數

trivia

SyntaxTriviaList

傳回

SyntaxToken

WithLeadingTrivia(IEnumerable<SyntaxTrivia>)

Source:

SyntaxToken.cs

從這個權杖建立新的權杖，並指定前置 Trivia。

public:
 Microsoft::CodeAnalysis::SyntaxToken WithLeadingTrivia(System::Collections::Generic::IEnumerable<Microsoft::CodeAnalysis::SyntaxTrivia> ^ trivia);

public Microsoft.CodeAnalysis.SyntaxToken WithLeadingTrivia (System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxTrivia>? trivia);

member this.WithLeadingTrivia : seq<Microsoft.CodeAnalysis.SyntaxTrivia> -> Microsoft.CodeAnalysis.SyntaxToken

Public Function WithLeadingTrivia (trivia As IEnumerable(Of SyntaxTrivia)) As SyntaxToken

參數

trivia

IEnumerable<SyntaxTrivia>

傳回

SyntaxToken