VCALinkTool.OutputBaseFileName Property
Definition
Important
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Gets the name (but not the location) of the generated satellite resource DLL or DLL.
public:
property System::String ^ OutputBaseFileName { System::String ^ get(); };
public:
property Platform::String ^ OutputBaseFileName { Platform::String ^ get(); };
[System.Runtime.InteropServices.DispId(4)]
public string OutputBaseFileName { [System.Runtime.InteropServices.DispId(4)] get; }
[<System.Runtime.InteropServices.DispId(4)>]
[<get: System.Runtime.InteropServices.DispId(4)>]
member this.OutputBaseFileName : string
Public ReadOnly Property OutputBaseFileName As String
Property Value
The name of the generated satellite resource DLL.
- Attributes
Examples
' Add a reference to Microsoft.VisualStudio.VCProjectEngine and have a
' Visual C++ project loaded before running this example.
Imports EnvDTE
Imports Microsoft.VisualStudio.VCProjectEngine
Public Module Module1
Sub Test()
Dim prj As VCProject
Dim cfgs, tools As IVCCollection
Dim cfg As VCConfiguration
Dim tool As VCALinkTool
prj = DTE.Solution.Projects.Item(1).Object
cfgs = prj.Configurations
cfg = cfgs.Item(1)
tool = cfg.Tools("VCALinkTool")
MsgBox("Output base file name: " & tool.OutputBaseFileName)
End Sub
End Module
Remarks
The common language runtime, which requires that satellite resources have the same name, are distinguished by their directories. For example, French resources would have the name specified here and be in a subdirectory named "fr" under the directory in which the primary output resides. As a result, the name returned by OutputBaseFileName is always a single name, even when there are multiple satellite DLLs being generated.
See How to: Compile Example Code for Project Model Extensibility for information about how to compile and run this sample.