Double.MaxValue 欄位
定義
重要
部分資訊涉及發行前產品,在發行之前可能會有大幅修改。 Microsoft 對此處提供的資訊,不做任何明確或隱含的瑕疵擔保。
表示 Double 最大的可能值。 這個欄位為常數。
public: double MaxValue = 1.7976931348623157E+308;
public const double MaxValue = 1.7976931348623157E+308;
val mutable MaxValue : double
Public Const MaxValue As Double = 1.7976931348623157E+308
欄位值
Value = 1.7976931348623157E+308範例
下列程式碼範例說明 如何使用 Double.MaxValue :
public ref class Temperature
{
public:
static property double MinValue
{
double get()
{
return Double::MinValue;
}
}
static property double MaxValue
{
double get()
{
return Double::MaxValue;
}
}
protected:
// The value holder
double m_value;
public:
property double Value
{
double get()
{
return m_value;
}
void set( double value )
{
m_value = value;
}
}
property double Celsius
{
double get()
{
return (m_value - 32.0) / 1.8;
}
void set( double value )
{
m_value = 1.8 * value + 32.0;
}
}
};
public class Temperature {
public static double MinValue {
get {
return Double.MinValue;
}
}
public static double MaxValue {
get {
return Double.MaxValue;
}
}
// The value holder
protected double m_value;
public double Value {
get {
return m_value;
}
set {
m_value = value;
}
}
public double Celsius {
get {
return (m_value-32.0)/1.8;
}
set {
m_value = 1.8*value+32.0;
}
}
}
type Temperature() =
static member MinValue =
Double.MinValue
static member MaxValue =
Double.MaxValue
member val Value = 0. with get, set
member this.Celsius
with get () =
(this.Value - 32.) / 1.8
and set (value) =
this.Value <- 1.8 * value + 32.
Public Class Temperature
Public Shared ReadOnly Property MinValue() As Double
Get
Return Double.MinValue
End Get
End Property
Public Shared ReadOnly Property MaxValue() As Double
Get
Return Double.MaxValue
End Get
End Property
' The value holder
Protected m_value As Double
Public Property Value() As Double
Get
Return m_value
End Get
Set(ByVal Value As Double)
m_value = Value
End Set
End Property
Public Property Celsius() As Double
Get
Return (m_value - 32) / 1.8
End Get
Set(ByVal Value As Double)
m_value = Value * 1.8 + 32
End Set
End Property
End Class
備註
這個常數的值是正 1.7976931348623157E+308。
超過 Double.MaxValue 的作業結果為 Double.PositiveInfinity 。 在下列範例中,當結果超過 Double.MaxValue 時, Double.PositiveInfinity 加法、乘法和指數運算的結果。
using System;
public class Example
{
public static void Main()
{
double result1 = 7.997e307 + 9.985e307;
Console.WriteLine("{0} (Positive Infinity: {1})",
result1, Double.IsPositiveInfinity(result1));
double result2 = 1.5935e250 * 7.948e110;
Console.WriteLine("{0} (Positive Infinity: {1})",
result2, Double.IsPositiveInfinity(result2));
double result3 = Math.Pow(1.256e100, 1.34e20);
Console.WriteLine("{0} (Positive Infinity: {1})",
result3, Double.IsPositiveInfinity(result3));
}
}
// The example displays the following output:
// Infinity (Positive Infinity: True)
// Infinity (Positive Infinity: True)
// Infinity (Positive Infinity: True)
open System
let result1 = 7.997e307 + 9.985e307
printfn $"{result1} (Positive Infinity: {Double.IsPositiveInfinity result1})"
let result2 = 1.5935e250 * 7.948e110
printfn $"{result2} (Positive Infinity: {Double.IsPositiveInfinity result2})"
let result3 = Math.Pow(1.256e100, 1.34e20)
printfn $"{result3} (Positive Infinity: {Double.IsPositiveInfinity result3})"
// The example displays the following output:
// Infinity (Positive Infinity: True)
// Infinity (Positive Infinity: True)
// Infinity (Positive Infinity: True)
Module Example
Public Sub Main()
Dim result1 As Double = 7.997e307 + 9.985e307
Console.WriteLine("{0} (Positive Infinity: {1})",
result1, Double.IsPositiveInfinity(result1))
Dim result2 As Double = 1.5935e250 * 7.948e110
Console.WriteLine("{0} (Positive Infinity: {1})",
result2, Double.IsPositiveInfinity(result2))
Dim result3 As Double = Math.Pow(1.256e100, 1.34e20)
Console.WriteLine("{0} (Positive Infinity: {1})",
result3, Double.IsPositiveInfinity(result3))
End Sub
End Module
' The example displays the following output:
' Infinity (Positive Infinity: True)
' Infinity (Positive Infinity: True)
' Infinity (Positive Infinity: True)