Queryable.Concat<TSource> 方法
定義
重要
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串連兩個序列。
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static System::Linq::IQueryable<TSource> ^ Concat(System::Linq::IQueryable<TSource> ^ source1, System::Collections::Generic::IEnumerable<TSource> ^ source2);
public static System.Linq.IQueryable<TSource> Concat<TSource> (this System.Linq.IQueryable<TSource> source1, System.Collections.Generic.IEnumerable<TSource> source2);
static member Concat : System.Linq.IQueryable<'Source> * seq<'Source> -> System.Linq.IQueryable<'Source>
<Extension()>
Public Function Concat(Of TSource) (source1 As IQueryable(Of TSource), source2 As IEnumerable(Of TSource)) As IQueryable(Of TSource)
類型參數
- TSource
輸入序列之項目的類型。
參數
- source1
- IQueryable<TSource>
要串連的第一個序列。
- source2
- IEnumerable<TSource>
要串連到第一個序列的序列。
傳回
IQueryable<TSource>
IQueryable<T>,其中包含兩個輸入序列的串連項目。
例外狀況
source1
或 source2
為 null
。
範例
下列程式代碼範例示範如何使用 Concat<TSource>(IQueryable<TSource>, IEnumerable<TSource>) 來串連兩個序列。
class Pet
{
public string Name { get; set; }
public int Age { get; set; }
}
// This method creates and returns an array of Pet objects.
static Pet[] GetCats()
{
Pet[] cats = { new Pet { Name="Barley", Age=8 },
new Pet { Name="Boots", Age=4 },
new Pet { Name="Whiskers", Age=1 } };
return cats;
}
// This method creates and returns an array of Pet objects.
static Pet[] GetDogs()
{
Pet[] dogs = { new Pet { Name="Bounder", Age=3 },
new Pet { Name="Snoopy", Age=14 },
new Pet { Name="Fido", Age=9 } };
return dogs;
}
public static void ConcatEx1()
{
Pet[] cats = GetCats();
Pet[] dogs = GetDogs();
// Concatenate a collection of cat names to a
// collection of dog names by using Concat().
IEnumerable<string> query =
cats.AsQueryable()
.Select(cat => cat.Name)
.Concat(dogs.Select(dog => dog.Name));
foreach (string name in query)
Console.WriteLine(name);
}
// This code produces the following output:
//
// Barley
// Boots
// Whiskers
// Bounder
// Snoopy
// Fido
' This method creates and returns an array of Pet objects.
Shared Function GetCats() As Pet()
Dim cats() As Pet = _
{New Pet With {.Name = "Barley", .Age = 8}, _
New Pet With {.Name = "Boots", .Age = 4}, _
New Pet With {.Name = "Whiskers", .Age = 1}}
Return cats
End Function
' This method creates and returns an array of Pet objects.
Shared Function GetDogs() As Pet()
Dim dogs() As Pet = _
{New Pet With {.Name = "Bounder", .Age = 3}, _
New Pet With {.Name = "Snoopy", .Age = 14}, _
New Pet With {.Name = "Fido", .Age = 9}}
Return dogs
End Function
Shared Sub ConcatEx1()
Dim cats() As Pet = GetCats()
Dim dogs() As Pet = GetDogs()
' Concatenate a collection of cat names to a
' collection of dog names by using Concat().
Dim query As IEnumerable(Of String) = _
cats.AsQueryable() _
.Select(Function(cat) cat.Name) _
.Concat(dogs.Select(Function(dog) dog.Name))
For Each name As String In query
MsgBox(name)
Next
End Sub
Structure Pet
Dim Name As String
Dim Age As Integer
End Structure
' This code produces the following output:
'
' Barley
' Boots
' Whiskers
' Bounder
' Snoopy
' Fido
備註
方法 Concat<TSource>(IQueryable<TSource>, IEnumerable<TSource>) 會產生 , MethodCallExpression 表示呼叫 Concat<TSource>(IQueryable<TSource>, IEnumerable<TSource>) 本身為建構的泛型方法。 然後,它會將 傳遞給 MethodCallExpressionCreateQuery<TElement>(Expression) 參數之 屬性所Provider表示的方法IQueryProvidersource1
。
執行表示呼叫 Concat<TSource>(IQueryable<TSource>, IEnumerable<TSource>) 的表達式樹狀結構所產生的查詢行為,取決於參數類型的實作 source1
。 預期的行為是 中的 source2
專案會串連至 的 source1
元素,以建立新的序列。