Object.ReferenceEquals(Object, Object) 方法
定義
重要
部分資訊涉及發行前產品,在發行之前可能會有大幅修改。 Microsoft 對此處提供的資訊,不做任何明確或隱含的瑕疵擔保。
判斷指定的 Object 執行個體是否為相同的執行個體。
public:
static bool ReferenceEquals(System::Object ^ objA, System::Object ^ objB);
public static bool ReferenceEquals (object objA, object objB);
public static bool ReferenceEquals (object? objA, object? objB);
static member ReferenceEquals : obj * obj -> bool
Public Shared Function ReferenceEquals (objA As Object, objB As Object) As Boolean
參數
- objA
- Object
要比較的第一個物件。
- objB
- Object
要比較的第二個物件。
傳回
如果 objA
與 objB
為相同的執行個體或兩者皆為 null,則為 true
,否則為 false
。
範例
下列範例會使用 ReferenceEquals 來判斷兩個物件是否為相同的實例。
using namespace System;
int main()
{
Object^ o = nullptr;
Object^ p = nullptr;
Object^ q = gcnew Object;
Console::WriteLine( Object::ReferenceEquals( o, p ) );
p = q;
Console::WriteLine( Object::ReferenceEquals( p, q ) );
Console::WriteLine( Object::ReferenceEquals( o, p ) );
}
/*
This code produces the following output.
True
True
False
*/
object o = null;
object p = null;
object q = new Object();
Console.WriteLine(Object.ReferenceEquals(o, p));
p = q;
Console.WriteLine(Object.ReferenceEquals(p, q));
Console.WriteLine(Object.ReferenceEquals(o, p));
// This code produces the following output:
// True
// True
// False
let o: obj = null
let mutable p: obj = null
let q = obj ()
printfn $"{Object.ReferenceEquals(o, p)}"
p <- q
printfn $"{Object.ReferenceEquals(p, q)}"
printfn $"{Object.ReferenceEquals(o, p)}"
// This code produces the following output:
// True
// True
// False
Public Class App
Public Shared Sub Main()
Dim o As Object = Nothing
Dim p As Object = Nothing
Dim q As New Object
Console.WriteLine(Object.ReferenceEquals(o, p))
p = q
Console.WriteLine(Object.ReferenceEquals(p, q))
Console.WriteLine(Object.ReferenceEquals(o, p))
End Sub
End Class
' This code produces the following output:
'
' True
' True
' False
'
備註
Equals不同于 方法和等號比較運算子, ReferenceEquals 無法覆寫 方法。 因此,如果您想要測試兩個物件參考是否相等,而且不確定方法的實作 Equals
,您可以呼叫 ReferenceEquals 方法。
不過,在下列兩個案例中,方法的 ReferenceEquals 傳回值可能會異常:
比較實值型別時。 如果
objA
和objB
是實值型別,則會先進行 Box 處理,再將它們傳遞至 ReferenceEquals 方法。 這表示,如果 和objB
都objA
代表實值型別的相同實例, ReferenceEquals 方法仍會傳false
回 ,如下列範例所示。int int1 = 3; Console.WriteLine(Object.ReferenceEquals(int1, int1)); Console.WriteLine(int1.GetType().IsValueType); // The example displays the following output: // False // True
let int1 = 3 printfn $"{Object.ReferenceEquals(int1, int1)}" printfn $"{int1.GetType().IsValueType}" // The example displays the following output: // False // True
Public Module Example Public Sub Main Dim int1 As Integer = 3 Console.WriteLine(Object.ReferenceEquals(int1, int1)) Console.WriteLine(int1.GetType().IsValueType) End Sub End Module ' The example displays the following output: ' False ' True
如需 Boxing 實值型別的資訊,請參閱 Boxing 和 Unboxing。
比較字串時。 如果
objA
和objB
是字串,則如果字串為terned,則 ReferenceEquals 方法會傳回true
。 它不會針對值相等執行測試。 在下列範例中,s1
和s2
相等,因為它們是單一三元字串的兩個實例。 不過,s3
和s4
不相等,因為雖然它們具有相同的字串值,但該字串不是三元。String s1 = "String1"; String s2 = "String1"; Console.WriteLine("s1 = s2: {0}", Object.ReferenceEquals(s1, s2)); Console.WriteLine("{0} interned: {1}", s1, String.IsNullOrEmpty(String.IsInterned(s1)) ? "No" : "Yes"); String suffix = "A"; String s3 = "String" + suffix; String s4 = "String" + suffix; Console.WriteLine("s3 = s4: {0}", Object.ReferenceEquals(s3, s4)); Console.WriteLine("{0} interned: {1}", s3, String.IsNullOrEmpty(String.IsInterned(s3)) ? "No" : "Yes"); // The example displays the following output: // s1 = s2: True // String1 interned: Yes // s3 = s4: False // StringA interned: No
open System let s1 = "String1" let s2 = "String1" printfn $"s1 = s2: {Object.ReferenceEquals(s1, s2)}" printfn $"""{s1} interned: {if String.IsNullOrEmpty(String.IsInterned s1) then "No" else "Yes"}""" let suffix = "A" let s3 = "String" + suffix let s4 = "String" + suffix printfn $"s3 = s4: {Object.ReferenceEquals(s3, s4)}" printfn $"""{s3} interned: {if String.IsNullOrEmpty(String.IsInterned s3) then "No" else "Yes"}""" // The example displays the following output: // s1 = s2: True // String1 interned: Yes // s3 = s4: False // StringA interned: No
Module Example Public Sub Main() Dim s1 As String = "String1" Dim s2 As String = "String1" Console.WriteLine("s1 = s2: {0}", Object.ReferenceEquals(s1, s2)) Console.WriteLine("{0} interned: {1}", s1, If(String.IsNullOrEmpty(String.IsInterned(s1)), "No", "Yes")) Dim suffix As String = "A" Dim s3 = "String" + suffix Dim s4 = "String" + suffix Console.WriteLine("s3 = s4: {0}", Object.ReferenceEquals(s3, s4)) Console.WriteLine("{0} interned: {1}", s3, If(String.IsNullOrEmpty(String.IsInterned(s3)), "No", "Yes")) End Sub End Module ' The example displays the following output: ' s1 = s2: True ' String1 interned: Yes ' s3 = s4: False ' StringA interned: No
如需字串插播的詳細資訊,請參閱 String.IsInterned 。