String.LastIndexOfAny 方法
重要
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報告 Unicode 陣列中的一或多個指定的字元，在這個執行個體中最後一次出現時的所在索引 (以零為起始)。 如果在此執行個體中找不到陣列中的字元，此方法會傳回 -1。
| LastIndexOfAny(Char[]) |
報告 Unicode 陣列中的一或多個指定的字元，在這個執行個體中最後一次出現時的所在索引 (以零為起始)。 |
| LastIndexOfAny(Char[], Int32) |
報告 Unicode 陣列中的一或多個指定的字元，在這個執行個體中最後一次出現時的所在索引 (以零為起始)。 搜尋會從指定的字元位置開始，然後反向朝字串的開頭進行。 |
| LastIndexOfAny(Char[], Int32, Int32) |
報告 Unicode 陣列中的一或多個指定的字元，在這個執行個體中最後一次出現時的所在索引 (以零為起始)。 搜尋會從指定的字元位置開始，然後反向朝字串開頭指定數目的字元位置進行。 |
報告 Unicode 陣列中的一或多個指定的字元，在這個執行個體中最後一次出現時的所在索引 (以零為起始)。
public:
int LastIndexOfAny(cli::array <char> ^ anyOf);C#
public int LastIndexOfAny (char[] anyOf);member this.LastIndexOfAny : char[] -> intPublic Function LastIndexOfAny (anyOf As Char()) As Integer參數
- anyOf
- Char[]
Unicode 字元陣列，含有一或多個要搜尋的字元。
傳回
這個執行個體中最後項目的索引位置，其中找到了 anyOf 中的任何字元，如果 anyOf 中沒有找到任何字元，則為 -1。
例外狀況
anyOf 為 null。
範例
下列範例會在另一個字串內尋找字串 「is」 中最後一個出現任何字元的索引。
// Sample for String::LastIndexOfAny(Char[])
using namespace System;
int main()
{
String^ br1 = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-";
String^ br2 = "0123456789012345678901234567890123456789012345678901234567890123456";
String^ str = "Now is the time for all good men to come to the aid of their party.";
int start;
int at;
String^ target = "is";
array<Char>^anyOf = target->ToCharArray();
start = str->Length - 1;
Console::WriteLine( "The last character occurrence from position {0} to 0.", start );
Console::WriteLine( "{1}{0}{2}{0}{3}{0}", Environment::NewLine, br1, br2, str );
Console::Write( "A character in '{0}' occurs at position: ", target );
at = str->LastIndexOfAny( anyOf );
if ( at > -1 )
Console::Write( at );
else
Console::Write( "(not found)" );
Console::Write( "{0}{0}{0}", Environment::NewLine );
}
/*
This example produces the following results:
The last character occurrence from position 66 to 0.
0----+----1----+----2----+----3----+----4----+----5----+----6----+-
0123456789012345678901234567890123456789012345678901234567890123456
Now is the time for all good men to come to the aid of their party.
A character in 'is' occurs at position: 58
*/
C#
// Sample for String.LastIndexOfAny(Char[])
using System;
class Sample {
public static void Main() {
string br1 = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-";
string br2 = "0123456789012345678901234567890123456789012345678901234567890123456";
string str = "Now is the time for all good men to come to the aid of their party.";
int start;
int at;
string target = "is";
char[] anyOf = target.ToCharArray();
start = str.Length-1;
Console.WriteLine("The last character occurrence from position {0} to 0.", start);
Console.WriteLine("{1}{0}{2}{0}{3}{0}", Environment.NewLine, br1, br2, str);
Console.Write("A character in '{0}' occurs at position: ", target);
at = str.LastIndexOfAny(anyOf);
if (at > -1)
Console.Write(at);
else
Console.Write("(not found)");
Console.Write("{0}{0}{0}", Environment.NewLine);
}
}
/*
This example produces the following results:
The last character occurrence from position 66 to 0.
0----+----1----+----2----+----3----+----4----+----5----+----6----+-
0123456789012345678901234567890123456789012345678901234567890123456
Now is the time for all good men to come to the aid of their party.
A character in 'is' occurs at position: 58
*/
// Sample for String.LastIndexOfAny(Char[])
open System
let br1 = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-"
let br2 = "0123456789012345678901234567890123456789012345678901234567890123456"
let str = "Now is the time for all good men to come to the aid of their party."
let target = "is"
let anyOf = target.ToCharArray()
let start = str.Length - 1
printfn $"The last character occurrence from position {start} to 0."
printfn $"{br1}{Environment.NewLine}{br2}{Environment.NewLine}{str}{Environment.NewLine}"
printf $"A character in '{target}' occurs at position: "
let at = str.LastIndexOfAny anyOf
if at > -1 then
printf $"{at}"
else
printf "(not found)"
printf $"{Environment.NewLine}{Environment.NewLine}{Environment.NewLine}"
(*
This example produces the following results:
The last character occurrence from position 66 to 0.
0----+----1----+----2----+----3----+----4----+----5----+----6----+-
0123456789012345678901234567890123456789012345678901234567890123456
Now is the time for all good men to come to the aid of their party.
A character in 'is' occurs at position: 58
*)
' Sample for String.LastIndexOfAny(Char[])
_
Class Sample
Public Shared Sub Main()
Dim br1 As String = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-"
Dim br2 As String = "0123456789012345678901234567890123456789012345678901234567890123456"
Dim str As String = "Now is the time for all good men to come to the aid of their party."
Dim start As Integer
Dim at As Integer
Dim target As String = "is"
Dim anyOf As Char() = target.ToCharArray()
start = str.Length - 1
Console.WriteLine("The last character occurrence from position {0} to 0.", start)
Console.WriteLine("{1}{0}{2}{0}{3}{0}", Environment.NewLine, br1, br2, str)
Console.Write("A character in '{0}' occurs at position: ", target)
at = str.LastIndexOfAny(anyOf)
If at > - 1 Then
Console.Write(at)
Else
Console.Write("(not found)")
End If
Console.Write("{0}{0}{0}", Environment.NewLine)
End Sub
End Class
'
'This example produces the following results:
'The last character occurrence from position 66 to 0.
'0----+----1----+----2----+----3----+----4----+----5----+----6----+-
'0123456789012345678901234567890123456789012345678901234567890123456
'Now is the time for all good men to come to the aid of their party.
'
'A character in 'is' occurs at position: 58
'
'
'
備註
索引編號從零開始。
這個方法會開始搜尋這個實例的最後一個字元位置，並往後往回移至開頭，直到找到 中的 anyOf 字元或檢查第一個字元位置為止。 搜尋會區分大小寫。
這個方法會執行不區分文化特性的序數 (不區分文化特性) 搜尋，其中字元只有在 Unicode 純量值相同時，才會被視為相當於另一個字元。 若要執行區分文化特性的搜尋，請使用 CompareInfo.LastIndexOf 方法，其中代表預先編譯字元的 Unicode 純量值，例如 ligature 「Æ」 (U+00C6) ，可能會視為相當於正確序列中任何出現的字元元件，例如 「AE」 (U+0041、U+0045) ，視文化特性而定。
另請參閱
適用於
.NET 9 及其他版本
| 產品 | 版本 |
|---|---|
| .NET | Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9 |
| .NET Framework | 1.1, 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1 |
| .NET Standard | 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 2.0, 2.1 |
| UWP | 10.0 |
報告 Unicode 陣列中的一或多個指定的字元，在這個執行個體中最後一次出現時的所在索引 (以零為起始)。 搜尋會從指定的字元位置開始，然後反向朝字串的開頭進行。
public:
int LastIndexOfAny(cli::array <char> ^ anyOf, int startIndex);C#
public int LastIndexOfAny (char[] anyOf, int startIndex);member this.LastIndexOfAny : char[] * int -> intPublic Function LastIndexOfAny (anyOf As Char(), startIndex As Integer) As Integer參數
- anyOf
- Char[]
Unicode 字元陣列，含有一或多個要搜尋的字元。
- startIndex
- Int32
搜尋開始位置。 搜尋會從 startIndex 朝這個執行個體的開頭進行。
傳回
所找到之 anyOf 的任何字元，在這個執行個體中最後一次出現的索引位置；如果找不到 anyOf 中的字元，或目前的執行個體等於 Empty，則為 -1。
例外狀況
anyOf 為 null。
目前的執行個體不等於 Empty，且 startIndex 指定的位置不在這個執行個體之內。
範例
下列範例會在另一個字串的子字串中，尋找字串 「is」 中最後一個出現之任何字元的索引。
// Sample for String::LastIndexOfAny(Char, Int32)
using namespace System;
int main()
{
String^ br1 = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-";
String^ br2 = "0123456789012345678901234567890123456789012345678901234567890123456";
String^ str = "Now is the time for all good men to come to the aid of their party.";
int start;
int at;
String^ target = "is";
array<Char>^anyOf = target->ToCharArray();
start = (str->Length - 1) / 2;
Console::WriteLine( "The last character occurrence from position {0} to 0.", start );
Console::WriteLine( "{1}{0}{2}{0}{3}{0}", Environment::NewLine, br1, br2, str );
Console::Write( "A character in '{0}' occurs at position: ", target );
at = str->LastIndexOfAny( anyOf, start );
if ( at > -1 )
Console::Write( at );
else
Console::Write( "(not found)" );
Console::Write( "{0}{0}{0}", Environment::NewLine );
}
/*
This example produces the following results:
The last character occurrence from position 33 to 0.
0----+----1----+----2----+----3----+----4----+----5----+----6----+-
0123456789012345678901234567890123456789012345678901234567890123456
Now is the time for all good men to come to the aid of their party.
A character in 'is' occurs at position: 12
*/
C#
// Sample for String.LastIndexOfAny(Char[], Int32)
using System;
class Sample {
public static void Main() {
string br1 = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-";
string br2 = "0123456789012345678901234567890123456789012345678901234567890123456";
string str = "Now is the time for all good men to come to the aid of their party.";
int start;
int at;
string target = "is";
char[] anyOf = target.ToCharArray();
start = (str.Length-1)/2;
Console.WriteLine("The last character occurrence from position {0} to 0.", start);
Console.WriteLine("{1}{0}{2}{0}{3}{0}", Environment.NewLine, br1, br2, str);
Console.Write("A character in '{0}' occurs at position: ", target);
at = str.LastIndexOfAny(anyOf, start);
if (at > -1)
Console.Write(at);
else
Console.Write("(not found)");
Console.Write("{0}{0}{0}", Environment.NewLine);
}
}
/*
This example produces the following results:
The last character occurrence from position 33 to 0.
0----+----1----+----2----+----3----+----4----+----5----+----6----+-
0123456789012345678901234567890123456789012345678901234567890123456
Now is the time for all good men to come to the aid of their party.
A character in 'is' occurs at position: 12
*/
// Sample for String.LastIndexOfAny(Char[], Int32)
open System
let br1 = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-"
let br2 = "0123456789012345678901234567890123456789012345678901234567890123456"
let str = "Now is the time for all good men to come to the aid of their party."
let target = "is"
let anyOf = target.ToCharArray()
let start = (str.Length - 1) / 2
printfn $"The last character occurrence from position {start} to 0."
printfn $"{br1}{Environment.NewLine}{br2}{Environment.NewLine}{str}{Environment.NewLine}"
printf $"A character in '{target}' occurs at position: "
let at = str.LastIndexOfAny(anyOf, start)
if at > -1 then
printf $"{at}"
else
printf "(not found)"
printf $"{Environment.NewLine}{Environment.NewLine}{Environment.NewLine}"
(*
This example produces the following results:
The last character occurrence from position 33 to 0.
0----+----1----+----2----+----3----+----4----+----5----+----6----+-
0123456789012345678901234567890123456789012345678901234567890123456
Now is the time for all good men to come to the aid of their party.
A character in 'is' occurs at position: 12
*)
' Sample for String.LastIndexOfAny(Char[], Int32)
_
Class Sample
Public Shared Sub Main()
Dim br1 As String = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-"
Dim br2 As String = "0123456789012345678901234567890123456789012345678901234567890123456"
Dim str As String = "Now is the time for all good men to come to the aid of their party."
Dim start As Integer
Dim at As Integer
Dim target As String = "is"
Dim anyOf As Char() = target.ToCharArray()
start =(str.Length - 1) / 2
Console.WriteLine("The last character occurrence from position {0} to 0.", start)
Console.WriteLine("{1}{0}{2}{0}{3}{0}", Environment.NewLine, br1, br2, str)
Console.Write("A character in '{0}' occurs at position: ", target)
at = str.LastIndexOfAny(anyOf, start)
If at > - 1 Then
Console.Write(at)
Else
Console.Write("(not found)")
End If
Console.Write("{0}{0}{0}", Environment.NewLine)
End Sub
End Class
'
'This example produces the following results:
'The last character occurrence from position 33 to 0.
'0----+----1----+----2----+----3----+----4----+----5----+----6----+-
'0123456789012345678901234567890123456789012345678901234567890123456
'Now is the time for all good men to come to the aid of their party.
'
'A character in 'is' occurs at position: 12
'
'
'
備註
索引編號從零開始。
這個方法會開始搜尋 startIndex 這個實例的字元位置，並往後往回移至開頭，直到找到 中的 anyOf 字元或檢查第一個字元位置為止。 搜尋會區分大小寫。
這個方法會執行不區分文化特性的序數 (不區分文化特性) 搜尋，其中字元只有在 Unicode 純量值相同時，才會被視為相當於另一個字元。 若要執行區分文化特性的搜尋，請使用 CompareInfo.LastIndexOf 方法，其中代表預先編譯字元的 Unicode 純量值，例如 ligature 「Æ」 (U+00C6) ，可能會視為相當於正確序列中任何出現的字元元件，例如 「AE」 (U+0041、U+0045) ，視文化特性而定。
另請參閱
適用於
.NET 9 及其他版本
| 產品 | 版本 |
|---|---|
| .NET | Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9 |
| .NET Framework | 1.1, 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1 |
| .NET Standard | 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 2.0, 2.1 |
| UWP | 10.0 |
報告 Unicode 陣列中的一或多個指定的字元，在這個執行個體中最後一次出現時的所在索引 (以零為起始)。 搜尋會從指定的字元位置開始，然後反向朝字串開頭指定數目的字元位置進行。
public:
int LastIndexOfAny(cli::array <char> ^ anyOf, int startIndex, int count);C#
public int LastIndexOfAny (char[] anyOf, int startIndex, int count);member this.LastIndexOfAny : char[] * int * int -> intPublic Function LastIndexOfAny (anyOf As Char(), startIndex As Integer, count As Integer) As Integer參數
- anyOf
- Char[]
Unicode 字元陣列，含有一或多個要搜尋的字元。
- startIndex
- Int32
搜尋開始位置。 搜尋會從 startIndex 朝這個執行個體的開頭進行。
- count
- Int32
要檢視的字元位置數目。
傳回
所找到之 anyOf 的任何字元，在這個執行個體中最後一次出現的索引位置；如果找不到 anyOf 中的字元，或目前的執行個體等於 Empty，則為 -1。
例外狀況
anyOf 為 null。
範例
下列範例會在另一個字串的子字串內，尋找字串 「aid」 中最後一個出現任何字元的索引。
// Sample for String::LastIndexOfAny(Char[], Int32, Int32)
using namespace System;
int main()
{
String^ br1 = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-";
String^ br2 = "0123456789012345678901234567890123456789012345678901234567890123456";
String^ str = "Now is the time for all good men to come to the aid of their party.";
int start;
int at;
int count;
String^ target = "aid";
array<Char>^anyOf = target->ToCharArray();
start = ((str->Length - 1) * 2) / 3;
count = (str->Length - 1) / 3;
Console::WriteLine( "The last character occurrence from position {0} for {1} characters.", start, count );
Console::WriteLine( "{1}{0}{2}{0}{3}{0}", Environment::NewLine, br1, br2, str );
Console::Write( "A character in '{0}' occurs at position: ", target );
at = str->LastIndexOfAny( anyOf, start, count );
if ( at > -1 )
Console::Write( at );
else
Console::Write( "(not found)" );
Console::Write( "{0}{0}{0}", Environment::NewLine );
}
/*
This example produces the following results:
The last character occurrence from position 44 for 22 characters.
0----+----1----+----2----+----3----+----4----+----5----+----6----+-
0123456789012345678901234567890123456789012345678901234567890123456
Now is the time for all good men to come to the aid of their party.
A character in 'aid' occurs at position: 27
*/
C#
// Sample for String.LastIndexOfAny(Char[], Int32, Int32)
using System;
class Sample {
public static void Main() {
string br1 = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-";
string br2 = "0123456789012345678901234567890123456789012345678901234567890123456";
string str = "Now is the time for all good men to come to the aid of their party.";
int start;
int at;
int count;
string target = "aid";
char[] anyOf = target.ToCharArray();
start = ((str.Length-1)*2)/3;
count = (str.Length-1)/3;
Console.WriteLine("The last character occurrence from position {0} for {1} characters.", start, count);
Console.WriteLine("{1}{0}{2}{0}{3}{0}", Environment.NewLine, br1, br2, str);
Console.Write("A character in '{0}' occurs at position: ", target);
at = str.LastIndexOfAny(anyOf, start, count);
if (at > -1)
Console.Write(at);
else
Console.Write("(not found)");
Console.Write("{0}{0}{0}", Environment.NewLine);
}
}
/*
This example produces the following results:
The last character occurrence from position 44 for 22 characters.
0----+----1----+----2----+----3----+----4----+----5----+----6----+-
0123456789012345678901234567890123456789012345678901234567890123456
Now is the time for all good men to come to the aid of their party.
A character in 'aid' occurs at position: 27
*/
// Sample for String.LastIndexOfAny(Char[], Int32, Int32)
open System
let br1 = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-"
let br2 = "0123456789012345678901234567890123456789012345678901234567890123456"
let str = "Now is the time for all good men to come to the aid of their party."
let target = "aid"
let anyOf = target.ToCharArray()
let start = ((str.Length - 1) * 2) / 3
let count = (str.Length - 1) / 3
printfn $"The last character occurrence from position {start} for {count} characters."
printfn $"{br1}{Environment.NewLine}{br2}{Environment.NewLine}{str}{Environment.NewLine}"
printf $"A character in '{target}' occurs at position: "
let at = str.LastIndexOfAny(anyOf, start, count)
if at > -1 then
printf $"{at}"
else
printf "(not found)"
printf $"{Environment.NewLine}{Environment.NewLine}{Environment.NewLine}"
(*
This example produces the following results:
The last character occurrence from position 44 for 22 characters.
0----+----1----+----2----+----3----+----4----+----5----+----6----+-
0123456789012345678901234567890123456789012345678901234567890123456
Now is the time for all good men to come to the aid of their party.
A character in 'aid' occurs at position: 27
*)
' Sample for String.LastIndexOfAny(Char[], Int32, Int32)
_
Class Sample
Public Shared Sub Main()
Dim br1 As String = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-"
Dim br2 As String = "0123456789012345678901234567890123456789012345678901234567890123456"
Dim str As String = "Now is the time for all good men to come to the aid of their party."
Dim start As Integer
Dim at As Integer
Dim count As Integer
Dim target As String = "aid"
Dim anyOf As Char() = target.ToCharArray()
start =(str.Length - 1) * 2 / 3
count =(str.Length - 1) / 3
Console.WriteLine("The last character occurrence from position {0} for {1} characters.", start, count)
Console.WriteLine("{1}{0}{2}{0}{3}{0}", Environment.NewLine, br1, br2, str)
Console.Write("A character in '{0}' occurs at position: ", target)
at = str.LastIndexOfAny(anyOf, start, count)
If at > - 1 Then
Console.Write(at)
Else
Console.Write("(not found)")
End If
Console.Write("{0}{0}{0}", Environment.NewLine)
End Sub
End Class
'
'This example produces the following results:
'The last character occurrence from position 44 for 22 characters.
'0----+----1----+----2----+----3----+----4----+----5----+----6----+-
'0123456789012345678901234567890123456789012345678901234567890123456
'Now is the time for all good men to come to the aid of their party.
'
'A character in 'aid' occurs at position: 27
'
備註
索引編號從零開始。
這個方法會開始搜尋 startIndex 這個實例的字元位置，並往後往回移至開頭，直到找到 中的 anyOf 字元或 count 檢查字元位置為止。 搜尋會區分大小寫。
這個方法會執行不區分文化特性的序數 (不區分文化特性) 搜尋，其中字元只有在 Unicode 純量值相同時，才會被視為相當於另一個字元。 若要執行區分文化特性的搜尋，請使用 CompareInfo.LastIndexOf 方法，其中代表預先編譯字元的 Unicode 純量值，例如 ligature 「Æ」 (U+00C6) ，可能會視為相當於正確序列中任何出現的字元元件，例如 「AE」 (U+0041、U+0045) ，視文化特性而定。
另請參閱
適用於
.NET 9 及其他版本
| 產品 | 版本 |
|---|---|
| .NET | Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9 |
| .NET Framework | 1.1, 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1 |
| .NET Standard | 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 2.0, 2.1 |
| UWP | 10.0 |
