DateTime.DaysInMonth(Int32, Int32) Método
Definición
Importante
Parte de la información hace referencia a la versión preliminar del producto, que puede haberse modificado sustancialmente antes de lanzar la versión definitiva. Microsoft no otorga ninguna garantía, explícita o implícita, con respecto a la información proporcionada aquí.
Devuelve el número de días del mes y año especificados.
public:
static int DaysInMonth(int year, int month);public static int DaysInMonth (int year, int month);static member DaysInMonth : int * int -> intPublic Shared Function DaysInMonth (year As Integer, month As Integer) As IntegerParámetros
- year
- Int32
Año.
- month
- Int32
Mes (número del 1 al 12).
Devoluciones
Número de días de month para el year especificado.
Por ejemplo, si month es igual a 2 para febrero, el valor devuelto será 28 o 29, en función de que year sea un año bisiesto.
Excepciones
month es menor que 1 o mayor que 12.
O bien
year es menor que 1 o mayor que 9999.
Ejemplos
En el ejemplo siguiente se muestra cómo usar el DaysInMonth método para determinar el número de días de julio de 2001, febrero de 1998 (un año no bisiesto) y febrero de 1996 (año bisiesto).
using namespace System;
int main()
{
const int July = 7;
const int Feb = 2;
int daysInJuly = System::DateTime::DaysInMonth( 2001, July );
Console::WriteLine(daysInJuly);
// daysInFeb gets 28 because the year 1998 was not a leap year.
int daysInFeb = System::DateTime::DaysInMonth( 1998, Feb );
Console::WriteLine(daysInFeb);
// daysInFebLeap gets 29 because the year 1996 was a leap year.
int daysInFebLeap = System::DateTime::DaysInMonth( 1996, Feb );
Console::WriteLine(daysInFebLeap);
}
// The example displays the following output:
// 31
// 28
// 29
open System
let July = 7
let Feb = 2
let daysInJuly = DateTime.DaysInMonth(2001, July)
printfn $"{daysInJuly}"
// daysInFeb gets 28 because the year 1998 was not a leap year.
let daysInFeb = DateTime.DaysInMonth(1998, Feb)
printfn $"{daysInFeb}"
// daysInFebLeap gets 29 because the year 1996 was a leap year.
let daysInFebLeap = DateTime.DaysInMonth(1996, Feb)
printfn $"{daysInFebLeap}"
// The example displays the following output:
// 31
// 28
// 29
using System;
class Example
{
static void Main()
{
const int July = 7;
const int Feb = 2;
int daysInJuly = System.DateTime.DaysInMonth(2001, July);
Console.WriteLine(daysInJuly);
// daysInFeb gets 28 because the year 1998 was not a leap year.
int daysInFeb = System.DateTime.DaysInMonth(1998, Feb);
Console.WriteLine(daysInFeb);
// daysInFebLeap gets 29 because the year 1996 was a leap year.
int daysInFebLeap = System.DateTime.DaysInMonth(1996, Feb);
Console.WriteLine(daysInFebLeap);
}
}
// The example displays the following output:
// 31
// 28
// 29
Class Example
Public Shared Sub Main()
Const July As Integer = 7
Const Feb As Integer = 2
Dim daysInJuly As Integer = System.DateTime.DaysInMonth(2001, July)
Console.WriteLine(daysInJuly)
' daysInFeb gets 28 because the year 1998 was not a leap year.
Dim daysInFeb As Integer = System.DateTime.DaysInMonth(1998, Feb)
Console.WriteLine(daysInFeb)
' daysInFebLeap gets 29 because the year 1996 was a leap year.
Dim daysInFebLeap As Integer = System.DateTime.DaysInMonth(1996, Feb)
Console.WriteLine(daysInFebLeap)
End Sub
End Class
' The example displays the following output:
' 31
' 28
' 29
En el ejemplo siguiente se muestra el número de días de cada mes de un año especificado en una matriz de enteros.
using System;
using System.Globalization;
public class Example
{
public static void Main()
{
int[] years = { 2012, 2014 };
DateTimeFormatInfo dtfi = DateTimeFormatInfo.CurrentInfo;
Console.WriteLine("Days in the Month for the {0} culture " +
"using the {1} calendar\n",
CultureInfo.CurrentCulture.Name,
dtfi.Calendar.GetType().Name.Replace("Calendar", ""));
Console.WriteLine("{0,-10}{1,-15}{2,4}\n", "Year", "Month", "Days");
foreach (var year in years) {
for (int ctr = 0; ctr <= dtfi.MonthNames.Length - 1; ctr++) {
if (String.IsNullOrEmpty(dtfi.MonthNames[ctr]))
continue;
Console.WriteLine("{0,-10}{1,-15}{2,4}", year,
dtfi.MonthNames[ctr],
DateTime.DaysInMonth(year, ctr + 1));
}
Console.WriteLine();
}
}
}
// The example displays the following output:
// Days in the Month for the en-US culture using the Gregorian calendar
//
// Year Month Days
//
// 2012 January 31
// 2012 February 29
// 2012 March 31
// 2012 April 30
// 2012 May 31
// 2012 June 30
// 2012 July 31
// 2012 August 31
// 2012 September 30
// 2012 October 31
// 2012 November 30
// 2012 December 31
//
// 2014 January 31
// 2014 February 28
// 2014 March 31
// 2014 April 30
// 2014 May 31
// 2014 June 30
// 2014 July 31
// 2014 August 31
// 2014 September 30
// 2014 October 31
// 2014 November 30
// 2014 December 31
open System
open System.Globalization
let years = [| 2012; 2014 |]
let dtfi = DateTimeFormatInfo.CurrentInfo
printfn $"""Days in the Month for the {CultureInfo.CurrentCulture.Name} culture using the {dtfi.Calendar.GetType().Name.Replace("Calendar", "")} calendar\n"""
printfn $"""{"Year",-10}{"Month",-15}{"Days",4}\n"""
for year in years do
for i = 0 to dtfi.MonthNames.Length - 1 do
if not (String.IsNullOrEmpty dtfi.MonthNames[i]) then
printfn $"{year,-10}{dtfi.MonthNames[i],-15}{DateTime.DaysInMonth(year, i + 1),4}"
printfn ""
// The example displays the following output:
// Days in the Month for the en-US culture using the Gregorian calendar
//
// Year Month Days
//
// 2012 January 31
// 2012 February 29
// 2012 March 31
// 2012 April 30
// 2012 May 31
// 2012 June 30
// 2012 July 31
// 2012 August 31
// 2012 September 30
// 2012 October 31
// 2012 November 30
// 2012 December 31
//
// 2014 January 31
// 2014 February 28
// 2014 March 31
// 2014 April 30
// 2014 May 31
// 2014 June 30
// 2014 July 31
// 2014 August 31
// 2014 September 30
// 2014 October 31
// 2014 November 30
// 2014 December 31
Imports System.Globalization
Module Example
Public Sub Main()
Dim years() As Integer = { 2012, 2014 }
Dim dtfi As DateTimeFormatInfo = DateTimeFormatInfo.CurrentInfo
Console.WriteLine("Days in the Month for the {0} culture " +
"using the {1} calendar",
CultureInfo.CurrentCulture.Name,
dtfi.Calendar.GetType.Name.Replace("Calendar", ""))
Console.WriteLine()
Console.WriteLine("{0,-10}{1,-15}{2,4}", "Year", "Month", "Days")
Console.WriteLine()
For Each [year] As Integer In years
For ctr As Integer = 0 To dtfi.MonthNames.Length - 1
If String.IsNullOrEmpty(dtfi.MonthNames(ctr)) Then
Continue For
End If
Console.WriteLine("{0,-10}{1,-15}{2,4}", [year],
dtfi.MonthNames(ctr),
DateTime.DaysInMonth([year], ctr + 1))
Next
Console.WriteLine()
Next
End Sub
End Module
' The example displays the following output:
' Days in the Month for the en-US culture using the Gregorian calendar
'
' Year Month Days
'
' 2012 January 31
' 2012 February 29
' 2012 March 31
' 2012 April 30
' 2012 May 31
' 2012 June 30
' 2012 July 31
' 2012 August 31
' 2012 September 30
' 2012 October 31
' 2012 November 30
' 2012 December 31
'
' 2014 January 31
' 2014 February 28
' 2014 March 31
' 2014 April 30
' 2014 May 31
' 2014 June 30
' 2014 July 31
' 2014 August 31
' 2014 September 30
' 2014 October 31
' 2014 November 30
' 2014 December 31
Comentarios
El DaysInMonth método siempre interpreta month y year como mes y año del calendario gregoriano incluso si el calendario gregoriano no es el calendario actual de la referencia cultural actual. Para obtener el número de días de un mes especificado de un calendario determinado, llame al método del GetDaysInMonth calendario.