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DateTime.DaysInMonth(Int32, Int32) Método

Definición

Devuelve el número de días del mes y año especificados.

public:
 static int DaysInMonth(int year, int month);
public static int DaysInMonth (int year, int month);
static member DaysInMonth : int * int -> int
Public Shared Function DaysInMonth (year As Integer, month As Integer) As Integer

Parámetros

year
Int32

Año.

month
Int32

Mes (número del 1 al 12).

Devoluciones

Int32

Número de días de month para el year especificado.

Por ejemplo, si month es igual a 2 para febrero, el valor devuelto será 28 o 29, en función de que year sea un año bisiesto.

Excepciones

month es menor que 1 o mayor que 12.

O bien

year es menor que 1 o mayor que 9999.

Ejemplos

En el ejemplo siguiente se muestra cómo usar el DaysInMonth método para determinar el número de días de julio de 2001, febrero de 1998 (un año no bisiesto) y febrero de 1996 (año bisiesto).

using namespace System;

int main()
{
   const int July = 7;
   const int Feb = 2;
   
   int daysInJuly = System::DateTime::DaysInMonth( 2001, July );
   Console::WriteLine(daysInJuly);   
   // daysInFeb gets 28 because the year 1998 was not a leap year.
   int daysInFeb = System::DateTime::DaysInMonth( 1998, Feb );
   Console::WriteLine(daysInFeb);
   // daysInFebLeap gets 29 because the year 1996 was a leap year.
   int daysInFebLeap = System::DateTime::DaysInMonth( 1996, Feb );
   Console::WriteLine(daysInFebLeap);
}
// The example displays the following output:
//       31
//       28
//       29
open System

let July = 7
let Feb = 2

let daysInJuly = DateTime.DaysInMonth(2001, July)
printfn $"{daysInJuly}"

// daysInFeb gets 28 because the year 1998 was not a leap year.
let daysInFeb = DateTime.DaysInMonth(1998, Feb)
printfn $"{daysInFeb}"

// daysInFebLeap gets 29 because the year 1996 was a leap year.
let daysInFebLeap = DateTime.DaysInMonth(1996, Feb)
printfn $"{daysInFebLeap}"

// The example displays the following output:
//       31
//       28
//       29
using System;

class Example
{
    static void Main()
    {
        const int July = 7;
        const int Feb = 2;

        int daysInJuly = System.DateTime.DaysInMonth(2001, July);
        Console.WriteLine(daysInJuly);

        // daysInFeb gets 28 because the year 1998 was not a leap year.
        int daysInFeb = System.DateTime.DaysInMonth(1998, Feb);
        Console.WriteLine(daysInFeb);

        // daysInFebLeap gets 29 because the year 1996 was a leap year.
        int daysInFebLeap = System.DateTime.DaysInMonth(1996, Feb);
        Console.WriteLine(daysInFebLeap);
    }
}
// The example displays the following output:
//       31
//       28
//       29
Class Example
   Public Shared Sub Main()
      Const July As Integer = 7
      Const Feb As Integer = 2

      Dim daysInJuly As Integer = System.DateTime.DaysInMonth(2001, July)
      Console.WriteLine(daysInJuly)
      
      ' daysInFeb gets 28 because the year 1998 was not a leap year.
      Dim daysInFeb As Integer = System.DateTime.DaysInMonth(1998, Feb)
      Console.WriteLine(daysInFeb)
      ' daysInFebLeap gets 29 because the year 1996 was a leap year.
      Dim daysInFebLeap As Integer = System.DateTime.DaysInMonth(1996, Feb)
      Console.WriteLine(daysInFebLeap)
   End Sub
End Class
' The example displays the following output:
'       31
'       28
'       29

En el ejemplo siguiente se muestra el número de días de cada mes de un año especificado en una matriz de enteros.

using System;
using System.Globalization;

public class Example
{
   public static void Main()
   {
      int[] years = { 2012, 2014 };
      DateTimeFormatInfo dtfi = DateTimeFormatInfo.CurrentInfo;
      Console.WriteLine("Days in the Month for the {0} culture " +
                        "using the {1} calendar\n",
                        CultureInfo.CurrentCulture.Name,
                        dtfi.Calendar.GetType().Name.Replace("Calendar", ""));
      Console.WriteLine("{0,-10}{1,-15}{2,4}\n", "Year", "Month", "Days");

      foreach (var year in years) {
         for (int ctr = 0; ctr <= dtfi.MonthNames.Length - 1; ctr++) {
            if (String.IsNullOrEmpty(dtfi.MonthNames[ctr]))
               continue;

            Console.WriteLine("{0,-10}{1,-15}{2,4}", year,
                              dtfi.MonthNames[ctr],
                              DateTime.DaysInMonth(year, ctr + 1));
         }
         Console.WriteLine();
      }
   }
}
// The example displays the following output:
//    Days in the Month for the en-US culture using the Gregorian calendar
//
//    Year      Month          Days
//
//    2012      January          31
//    2012      February         29
//    2012      March            31
//    2012      April            30
//    2012      May              31
//    2012      June             30
//    2012      July             31
//    2012      August           31
//    2012      September        30
//    2012      October          31
//    2012      November         30
//    2012      December         31
//
//    2014      January          31
//    2014      February         28
//    2014      March            31
//    2014      April            30
//    2014      May              31
//    2014      June             30
//    2014      July             31
//    2014      August           31
//    2014      September        30
//    2014      October          31
//    2014      November         30
//    2014      December         31
open System
open System.Globalization

let years = [| 2012; 2014 |]
let dtfi = DateTimeFormatInfo.CurrentInfo
printfn $"""Days in the Month for the {CultureInfo.CurrentCulture.Name} culture using the {dtfi.Calendar.GetType().Name.Replace("Calendar", "")} calendar\n"""
printfn $"""{"Year",-10}{"Month",-15}{"Days",4}\n"""

for year in years do
    for i = 0 to dtfi.MonthNames.Length - 1 do
        if not (String.IsNullOrEmpty dtfi.MonthNames[i]) then
            printfn $"{year,-10}{dtfi.MonthNames[i],-15}{DateTime.DaysInMonth(year, i + 1),4}"
    printfn ""

// The example displays the following output:
//    Days in the Month for the en-US culture using the Gregorian calendar
//
//    Year      Month          Days
//
//    2012      January          31
//    2012      February         29
//    2012      March            31
//    2012      April            30
//    2012      May              31
//    2012      June             30
//    2012      July             31
//    2012      August           31
//    2012      September        30
//    2012      October          31
//    2012      November         30
//    2012      December         31
//
//    2014      January          31
//    2014      February         28
//    2014      March            31
//    2014      April            30
//    2014      May              31
//    2014      June             30
//    2014      July             31
//    2014      August           31
//    2014      September        30
//    2014      October          31
//    2014      November         30
//    2014      December         31
Imports System.Globalization

Module Example
   Public Sub Main()
      Dim years() As Integer = { 2012, 2014 }
      Dim dtfi As DateTimeFormatInfo = DateTimeFormatInfo.CurrentInfo
      Console.WriteLine("Days in the Month for the {0} culture " +
                        "using the {1} calendar", 
                        CultureInfo.CurrentCulture.Name, 
                        dtfi.Calendar.GetType.Name.Replace("Calendar", ""))
      Console.WriteLine()
      Console.WriteLine("{0,-10}{1,-15}{2,4}", "Year", "Month", "Days")
      Console.WriteLine()
      
      For Each [year] As Integer In years
         For ctr As Integer = 0 To dtfi.MonthNames.Length - 1
            If String.IsNullOrEmpty(dtfi.MonthNames(ctr)) Then 
               Continue For
            End If    
            
            Console.WriteLine("{0,-10}{1,-15}{2,4}", [year], 
                              dtfi.MonthNames(ctr), 
                              DateTime.DaysInMonth([year], ctr + 1))
         Next
         Console.WriteLine() 
      Next
   End Sub
End Module
' The example displays the following output:
'    Days in the Month for the en-US culture using the Gregorian calendar
'    
'    Year      Month          Days
'    
'    2012      January          31
'    2012      February         29
'    2012      March            31
'    2012      April            30
'    2012      May              31
'    2012      June             30
'    2012      July             31
'    2012      August           31
'    2012      September        30
'    2012      October          31
'    2012      November         30
'    2012      December         31
'    
'    2014      January          31
'    2014      February         28
'    2014      March            31
'    2014      April            30
'    2014      May              31
'    2014      June             30
'    2014      July             31
'    2014      August           31
'    2014      September        30
'    2014      October          31
'    2014      November         30
'    2014      December         31

Comentarios

El DaysInMonth método siempre interpreta month y year como mes y año del calendario gregoriano incluso si el calendario gregoriano no es el calendario actual de la referencia cultural actual. Para obtener el número de días de un mes especificado de un calendario determinado, llame al método del GetDaysInMonth calendario.

Se aplica a