ArrayList.LastIndexOf Metoda
Definice
Důležité
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Vrátí index založený na nule posledního výskytu hodnoty v ArrayList nebo jeho části.
Přetížení
| Name | Description |
|---|---|
| LastIndexOf(Object) |
Vyhledá zadaný Object index a vrátí index založený na nule posledního výskytu v celém ArrayListrozsahu . |
| LastIndexOf(Object, Int32) |
Vyhledá zadaný Object index a vrátí index založený na nule posledního výskytu v rozsahu prvků v ArrayList prvku, který se rozšiřuje od prvního prvku do zadaného indexu. |
| LastIndexOf(Object, Int32, Int32) |
Vyhledá zadaný Object a vrátí index založený na nule posledního výskytu v rozsahu prvků, ArrayList který obsahuje zadaný počet prvků a končí na zadaném indexu. |
LastIndexOf(Object)
- Zdroj:
- ArrayList.cs
- Zdroj:
- ArrayList.cs
- Zdroj:
- ArrayList.cs
- Zdroj:
- ArrayList.cs
- Zdroj:
- ArrayList.cs
public:
virtual int LastIndexOf(System::Object ^ value);
public virtual int LastIndexOf(object value);
public virtual int LastIndexOf(object? value);
abstract member LastIndexOf : obj -> int
override this.LastIndexOf : obj -> int
Public Overridable Function LastIndexOf (value As Object) As Integer
Parametry
Návraty
Index založený na nule posledního value výskytu v celém objektu ArrayList, pokud byl nalezen; jinak -1.
Příklady
Následující příklad kódu ukazuje, jak určit index posledního výskytu zadaného prvku.
using System;
using System.Collections;
public class SamplesArrayList {
public static void Main() {
// Creates and initializes a new ArrayList with three elements of the same value.
ArrayList myAL = new ArrayList();
myAL.Add( "the" );
myAL.Add( "quick" );
myAL.Add( "brown" );
myAL.Add( "fox" );
myAL.Add( "jumps" );
myAL.Add( "over" );
myAL.Add( "the" );
myAL.Add( "lazy" );
myAL.Add( "dog" );
myAL.Add( "in" );
myAL.Add( "the" );
myAL.Add( "barn" );
// Displays the values of the ArrayList.
Console.WriteLine( "The ArrayList contains the following values:" );
PrintIndexAndValues( myAL );
// Searches for the last occurrence of the duplicated value.
string myString = "the";
int myIndex = myAL.LastIndexOf( myString );
Console.WriteLine( "The last occurrence of \"{0}\" is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL.LastIndexOf( myString, 8 );
Console.WriteLine( "The last occurrence of \"{0}\" between the start and index 8 is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL.LastIndexOf( myString, 10, 6 );
Console.WriteLine( "The last occurrence of \"{0}\" between index 10 and index 5 is at index {1}.", myString, myIndex );
}
public static void PrintIndexAndValues( IEnumerable myList ) {
int i = 0;
foreach ( Object obj in myList )
Console.WriteLine( " [{0}]: {1}", i++, obj );
Console.WriteLine();
}
}
/*
This code produces the following output.
The ArrayList contains the following values:
[0]: the
[1]: quick
[2]: brown
[3]: fox
[4]: jumps
[5]: over
[6]: the
[7]: lazy
[8]: dog
[9]: in
[10]: the
[11]: barn
The last occurrence of "the" is at index 10.
The last occurrence of "the" between the start and index 8 is at index 6.
The last occurrence of "the" between index 10 and index 5 is at index 10.
*/
Imports System.Collections
Public Class SamplesArrayList
Public Shared Sub Main()
' Creates and initializes a new ArrayList with three elements of the same value.
Dim myAL As New ArrayList()
myAL.Add("the")
myAL.Add("quick")
myAL.Add("brown")
myAL.Add("fox")
myAL.Add("jumps")
myAL.Add("over")
myAL.Add("the")
myAL.Add("lazy")
myAL.Add("dog")
myAL.Add("in")
myAL.Add("the")
myAL.Add("barn")
' Displays the values of the ArrayList.
Console.WriteLine("The ArrayList contains the following values:")
PrintIndexAndValues(myAL)
' Searches for the last occurrence of the duplicated value.
Dim myString As [String] = "the"
Dim myIndex As Integer = myAL.LastIndexOf(myString)
Console.WriteLine("The last occurrence of ""{0}"" is at index {1}.", myString, myIndex)
' Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL.LastIndexOf(myString, 8)
Console.WriteLine("The last occurrence of ""{0}"" between the start and index 8 is at index {1}.", myString, myIndex)
' Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL.LastIndexOf(myString, 10, 6)
Console.WriteLine("The last occurrence of ""{0}"" between index 10 and index 5 is at index {1}.", myString, myIndex)
End Sub
Public Shared Sub PrintIndexAndValues(myList As IEnumerable)
Dim i as Integer
Dim obj As [Object]
For Each obj In myList
Console.WriteLine(" [{0}]: {1}", i, obj)
i = i + 1
Next obj
Console.WriteLine()
End Sub
End Class
' This code produces the following output.
'
' The ArrayList contains the following values:
' [0]: the
' [1]: quick
' [2]: brown
' [3]: fox
' [4]: jumps
' [5]: over
' [6]: the
' [7]: lazy
' [8]: dog
' [9]: in
' [10]: the
' [11]: barn
'
' The last occurrence of "the" is at index 10.
' The last occurrence of "the" between the start and index 8 is at index 6.
' The last occurrence of "the" between index 10 and index 5 is at index 10.
Poznámky
Vyhledá se ArrayList zpětně počínaje posledním prvkem a končí na prvním prvku.
Tato metoda provádí lineární vyhledávání; proto je O(n) tato metoda operace, kde n je Count.
Tato metoda používá objekty Equals a CompareTo metody item kolekce k určení, zda položka existuje.
Viz také
Platí pro
LastIndexOf(Object, Int32)
- Zdroj:
- ArrayList.cs
- Zdroj:
- ArrayList.cs
- Zdroj:
- ArrayList.cs
- Zdroj:
- ArrayList.cs
- Zdroj:
- ArrayList.cs
public:
virtual int LastIndexOf(System::Object ^ value, int startIndex);
public virtual int LastIndexOf(object value, int startIndex);
public virtual int LastIndexOf(object? value, int startIndex);
abstract member LastIndexOf : obj * int -> int
override this.LastIndexOf : obj * int -> int
Public Overridable Function LastIndexOf (value As Object, startIndex As Integer) As Integer
Parametry
- startIndex
- Int32
Počáteční index zpětného vyhledávání založený na nule.
Návraty
Index založený na nule posledního výskytu value v rozsahu prvků, ArrayList který rozšiřuje od prvního prvku na startIndex, pokud je nalezen; jinak - 1.
Výjimky
startIndex je mimo rozsah platných indexů pro ArrayList.
Příklady
Následující příklad kódu ukazuje, jak určit index posledního výskytu zadaného prvku.
using System;
using System.Collections;
public class SamplesArrayList {
public static void Main() {
// Creates and initializes a new ArrayList with three elements of the same value.
ArrayList myAL = new ArrayList();
myAL.Add( "the" );
myAL.Add( "quick" );
myAL.Add( "brown" );
myAL.Add( "fox" );
myAL.Add( "jumps" );
myAL.Add( "over" );
myAL.Add( "the" );
myAL.Add( "lazy" );
myAL.Add( "dog" );
myAL.Add( "in" );
myAL.Add( "the" );
myAL.Add( "barn" );
// Displays the values of the ArrayList.
Console.WriteLine( "The ArrayList contains the following values:" );
PrintIndexAndValues( myAL );
// Searches for the last occurrence of the duplicated value.
string myString = "the";
int myIndex = myAL.LastIndexOf( myString );
Console.WriteLine( "The last occurrence of \"{0}\" is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL.LastIndexOf( myString, 8 );
Console.WriteLine( "The last occurrence of \"{0}\" between the start and index 8 is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL.LastIndexOf( myString, 10, 6 );
Console.WriteLine( "The last occurrence of \"{0}\" between index 10 and index 5 is at index {1}.", myString, myIndex );
}
public static void PrintIndexAndValues( IEnumerable myList ) {
int i = 0;
foreach ( Object obj in myList )
Console.WriteLine( " [{0}]: {1}", i++, obj );
Console.WriteLine();
}
}
/*
This code produces the following output.
The ArrayList contains the following values:
[0]: the
[1]: quick
[2]: brown
[3]: fox
[4]: jumps
[5]: over
[6]: the
[7]: lazy
[8]: dog
[9]: in
[10]: the
[11]: barn
The last occurrence of "the" is at index 10.
The last occurrence of "the" between the start and index 8 is at index 6.
The last occurrence of "the" between index 10 and index 5 is at index 10.
*/
Imports System.Collections
Public Class SamplesArrayList
Public Shared Sub Main()
' Creates and initializes a new ArrayList with three elements of the same value.
Dim myAL As New ArrayList()
myAL.Add("the")
myAL.Add("quick")
myAL.Add("brown")
myAL.Add("fox")
myAL.Add("jumps")
myAL.Add("over")
myAL.Add("the")
myAL.Add("lazy")
myAL.Add("dog")
myAL.Add("in")
myAL.Add("the")
myAL.Add("barn")
' Displays the values of the ArrayList.
Console.WriteLine("The ArrayList contains the following values:")
PrintIndexAndValues(myAL)
' Searches for the last occurrence of the duplicated value.
Dim myString As [String] = "the"
Dim myIndex As Integer = myAL.LastIndexOf(myString)
Console.WriteLine("The last occurrence of ""{0}"" is at index {1}.", myString, myIndex)
' Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL.LastIndexOf(myString, 8)
Console.WriteLine("The last occurrence of ""{0}"" between the start and index 8 is at index {1}.", myString, myIndex)
' Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL.LastIndexOf(myString, 10, 6)
Console.WriteLine("The last occurrence of ""{0}"" between index 10 and index 5 is at index {1}.", myString, myIndex)
End Sub
Public Shared Sub PrintIndexAndValues(myList As IEnumerable)
Dim i as Integer
Dim obj As [Object]
For Each obj In myList
Console.WriteLine(" [{0}]: {1}", i, obj)
i = i + 1
Next obj
Console.WriteLine()
End Sub
End Class
' This code produces the following output.
'
' The ArrayList contains the following values:
' [0]: the
' [1]: quick
' [2]: brown
' [3]: fox
' [4]: jumps
' [5]: over
' [6]: the
' [7]: lazy
' [8]: dog
' [9]: in
' [10]: the
' [11]: barn
'
' The last occurrence of "the" is at index 10.
' The last occurrence of "the" between the start and index 8 is at index 6.
' The last occurrence of "the" between index 10 and index 5 is at index 10.
Poznámky
Vyhledá se ArrayList zpětně počínaje startIndex prvním prvkem a končí na prvním prvku.
Tato metoda provádí lineární vyhledávání; proto je tato metoda O(n) operace, kde n je počet prvků od začátku ArrayList do startIndex.
Tato metoda určuje rovnost voláním Object.Equals.
Tato metoda používá objekty Equals a CompareTo metody item kolekce k určení, zda položka existuje.
Viz také
Platí pro
LastIndexOf(Object, Int32, Int32)
- Zdroj:
- ArrayList.cs
- Zdroj:
- ArrayList.cs
- Zdroj:
- ArrayList.cs
- Zdroj:
- ArrayList.cs
- Zdroj:
- ArrayList.cs
public:
virtual int LastIndexOf(System::Object ^ value, int startIndex, int count);
public virtual int LastIndexOf(object value, int startIndex, int count);
public virtual int LastIndexOf(object? value, int startIndex, int count);
abstract member LastIndexOf : obj * int * int -> int
override this.LastIndexOf : obj * int * int -> int
Public Overridable Function LastIndexOf (value As Object, startIndex As Integer, count As Integer) As Integer
Parametry
- startIndex
- Int32
Počáteční index zpětného vyhledávání založený na nule.
- count
- Int32
Počet prvků v oddílu, které se mají prohledávat.
Návraty
Index založený na nule posledního výskytu value v rozsahu prvků, ArrayList který obsahuje count počet prvků a končí na startIndex, pokud je nalezen; jinak - 1.
Výjimky
startIndex je mimo rozsah platných indexů pro ArrayList.
nebo
Hodnota count je menší než nula.
nebo
startIndex a count nezadávejte platný oddíl v sekci ArrayList.
Příklady
Následující příklad kódu ukazuje, jak určit index posledního výskytu zadaného prvku. Všimněte si, že LastIndexOf vyhledávání je zpětné, count proto musí být menší než nebo rovno startIndex + 1.
using System;
using System.Collections;
public class SamplesArrayList {
public static void Main() {
// Creates and initializes a new ArrayList with three elements of the same value.
ArrayList myAL = new ArrayList();
myAL.Add( "the" );
myAL.Add( "quick" );
myAL.Add( "brown" );
myAL.Add( "fox" );
myAL.Add( "jumps" );
myAL.Add( "over" );
myAL.Add( "the" );
myAL.Add( "lazy" );
myAL.Add( "dog" );
myAL.Add( "in" );
myAL.Add( "the" );
myAL.Add( "barn" );
// Displays the values of the ArrayList.
Console.WriteLine( "The ArrayList contains the following values:" );
PrintIndexAndValues( myAL );
// Searches for the last occurrence of the duplicated value.
string myString = "the";
int myIndex = myAL.LastIndexOf( myString );
Console.WriteLine( "The last occurrence of \"{0}\" is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL.LastIndexOf( myString, 8 );
Console.WriteLine( "The last occurrence of \"{0}\" between the start and index 8 is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL.LastIndexOf( myString, 10, 6 );
Console.WriteLine( "The last occurrence of \"{0}\" between index 10 and index 5 is at index {1}.", myString, myIndex );
}
public static void PrintIndexAndValues( IEnumerable myList ) {
int i = 0;
foreach ( Object obj in myList )
Console.WriteLine( " [{0}]: {1}", i++, obj );
Console.WriteLine();
}
}
/*
This code produces the following output.
The ArrayList contains the following values:
[0]: the
[1]: quick
[2]: brown
[3]: fox
[4]: jumps
[5]: over
[6]: the
[7]: lazy
[8]: dog
[9]: in
[10]: the
[11]: barn
The last occurrence of "the" is at index 10.
The last occurrence of "the" between the start and index 8 is at index 6.
The last occurrence of "the" between index 10 and index 5 is at index 10.
*/
Imports System.Collections
Public Class SamplesArrayList
Public Shared Sub Main()
' Creates and initializes a new ArrayList with three elements of the same value.
Dim myAL As New ArrayList()
myAL.Add("the")
myAL.Add("quick")
myAL.Add("brown")
myAL.Add("fox")
myAL.Add("jumps")
myAL.Add("over")
myAL.Add("the")
myAL.Add("lazy")
myAL.Add("dog")
myAL.Add("in")
myAL.Add("the")
myAL.Add("barn")
' Displays the values of the ArrayList.
Console.WriteLine("The ArrayList contains the following values:")
PrintIndexAndValues(myAL)
' Searches for the last occurrence of the duplicated value.
Dim myString As [String] = "the"
Dim myIndex As Integer = myAL.LastIndexOf(myString)
Console.WriteLine("The last occurrence of ""{0}"" is at index {1}.", myString, myIndex)
' Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL.LastIndexOf(myString, 8)
Console.WriteLine("The last occurrence of ""{0}"" between the start and index 8 is at index {1}.", myString, myIndex)
' Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL.LastIndexOf(myString, 10, 6)
Console.WriteLine("The last occurrence of ""{0}"" between index 10 and index 5 is at index {1}.", myString, myIndex)
End Sub
Public Shared Sub PrintIndexAndValues(myList As IEnumerable)
Dim i as Integer
Dim obj As [Object]
For Each obj In myList
Console.WriteLine(" [{0}]: {1}", i, obj)
i = i + 1
Next obj
Console.WriteLine()
End Sub
End Class
' This code produces the following output.
'
' The ArrayList contains the following values:
' [0]: the
' [1]: quick
' [2]: brown
' [3]: fox
' [4]: jumps
' [5]: over
' [6]: the
' [7]: lazy
' [8]: dog
' [9]: in
' [10]: the
' [11]: barn
'
' The last occurrence of "the" is at index 10.
' The last occurrence of "the" between the start and index 8 is at index 6.
' The last occurrence of "the" between index 10 and index 5 is at index 10.
Poznámky
Vyhledá se ArrayList zpětně počínaje startIndex a končí na startIndex mínus count plus 1, pokud count je větší než 0.
Tato metoda provádí lineární vyhledávání; proto je O(n) tato metoda operace, kde n je count.
Tato metoda určuje rovnost voláním Object.Equals.
Tato metoda používá objekty Equals a CompareTo metody item kolekce k určení, zda položka existuje.