Enumerable.Append<TSource>(IEnumerable<TSource>, TSource) Metoda

Definice

Obor názvů:

System.Linq

Sestavení:

System.Linq.dll

Zdroj:

AppendPrepend.cs

Připojí hodnotu na konec sekvence.

public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
 static System::Collections::Generic::IEnumerable<TSource> ^ Append(System::Collections::Generic::IEnumerable<TSource> ^ source, TSource element);

public static System.Collections.Generic.IEnumerable<TSource> Append<TSource> (this System.Collections.Generic.IEnumerable<TSource> source, TSource element);

static member Append : seq<'Source> * 'Source -> seq<'Source>

<Extension()>
Public Function Append(Of TSource) (source As IEnumerable(Of TSource), element As TSource) As IEnumerable(Of TSource)

Parametry typu

TSource

Typ prvků objektu source.

Parametry

source

IEnumerable<TSource>

Posloupnost hodnot.

element

TSource

Hodnota, která se má připojit k source.

Návraty

IEnumerable<TSource>

Nová sekvence, která končí na element.

Výjimky

ArgumentNullException

source je null.

Příklady

Následující příklad kódu ukazuje, jak použít Append k připojení hodnoty na konec sekvence.

// Creating a list of numbers
List<int> numbers = new List<int> { 1, 2, 3, 4 };

// Trying to append any value of the same type
numbers.Append(5);

// It doesn't work because the original list has not been changed
Console.WriteLine(string.Join(", ", numbers));

// It works now because we are using a changed copy of the original list
Console.WriteLine(string.Join(", ", numbers.Append(5)));

// If you prefer, you can create a new list explicitly
List<int> newNumbers = numbers.Append(5).ToList();

// And then write to the console output
Console.WriteLine(string.Join(", ", newNumbers));

// This code produces the following output:
//
// 1, 2, 3, 4
// 1, 2, 3, 4, 5
// 1, 2, 3, 4, 5

' Creating a list of numbers
Dim numbers As New List(Of Integer)(New Integer() {1, 2, 3, 4})

' Trying to append any value of the same type
numbers.Append(5)

' It doesn't work because the original list has not been changed
Console.WriteLine(String.Join(", ", numbers))

' It works now because we are using a changed copy of the original list
Console.WriteLine(String.Join(", ", numbers.Append(5)))

' If you prefer, you can create a new list explicitly
Dim newNumbers As List(Of Integer) = numbers.Append(5).ToList

' And then write to the console output
Console.WriteLine(String.Join(", ", newNumbers))

' This code produces the following output:
'
' 1, 2, 3, 4
' 1, 2, 3, 4, 5
' 1, 2, 3, 4, 5

Poznámky

Poznámka

Tato metoda nemění prvky kolekce. Místo toho vytvoří kopii kolekce s novým elementem.