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Tuple<T1,T2,T3,T4,T5,T6,T7>.Item3 Vlastnost

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Definice

Obor názvů:
System
Sestavení:
System.Runtime.dll
Sestavení:
mscorlib.dll
Sestavení:
netstandard.dll

Získá hodnotu aktuálního Tuple<T1,T2,T3,T4,T5,T6,T7> objektu třetí komponenty.

public:
 property T3 Item3 { T3 get(); };
public T3 Item3 { get; }
member this.Item3 : 'T3
Public ReadOnly Property Item3 As T3

Hodnota vlastnosti

T3

Hodnota třetí komponenty aktuálního Tuple<T1,T2,T3,T4,T5,T6,T7> objektu.

Příklady

Následující příklad definuje pole Tuple<T1,T2,T3,T4,T5,T6,T7> objektů, jejichž součásti obsahují data o populaci pro tři města USA (New York, Chicago a Los Angeles) od roku 1950 do roku 2000. Pak zobrazí tabulku obsahující data. Chcete-li zobrazit základní soubor v roce 1960, načte hodnotu Item3 vlastnosti pro každý Tuple<T1,T2,T3,T4,T5,T6,T7> objekt.

using System;
using System.Text.RegularExpressions;

public class Class1
{
   public static void Main()
   {
      // Create tuples containing population data for New York, Chicago, 
      // and Los Angeles, 1960-2000.
      Tuple<string, int, int, int, int, int, int>[] cities =
           { Tuple.Create("New York", 7891957, 7781984, 7894862, 7071639, 7322564, 8008278),
             Tuple.Create("Los Angeles", 1970358, 2479015, 2816061, 2966850, 3485398, 3694820),
             Tuple.Create("Chicago", 3620962, 3550904, 3366957, 3005072, 2783726, 2896016) };

      // Display tuple data in table.
      string header = "Population in";
      Console.WriteLine("{0,-12} {1,66}", 
                        "City", new String('-',(66-header.Length)/2) + header + 
                                new String('-', (66-header.Length)/2));
      Console.WriteLine("{0,24}{1,11}{2,11}{3,11}{4,11}{5,11}\n", 
                        "1950", "1960", "1970", "1980", "1990", "2000");         

      foreach (var city in cities)                      
         Console.WriteLine("{0,-12} {1,11:N0}{2,11:N0}{3,11:N0}{4,11:N0}{5,11:N0}{6,11:N0}", 
                           city.Item1, city.Item2, city.Item3, city.Item4, 
                           city.Item5, city.Item6, city.Item7);
   }
}
// The example displays the following output:
//   City          --------------------------Population in--------------------------
//                       1950       1960       1970       1980       1990       2000
//
//   New York       7,891,957  7,781,984  7,894,862  7,071,639  7,322,564  8,008,278
//   Los Angeles    1,970,358  2,479,015  2,816,061  2,966,850  3,485,398  3,694,820
//   Chicago        3,620,962  3,550,904  3,366,957  3,005,072  2,783,726  2,896,016

open System

// Create tuples containing population data for New York, Chicago, 
// and Los Angeles, 1960-2000.
let cities =
    [| Tuple.Create("New York", 7891957, 7781984, 7894862, 7071639, 7322564, 8008278)
       Tuple.Create("Los Angeles", 1970358, 2479015, 2816061, 2966850, 3485398, 3694820)
       Tuple.Create("Chicago", 3620962, 3550904, 3366957, 3005072, 2783726, 2896016) |]

// Display tuple data in table.
let header = "Population in"
printfn $"""{"City",-12} {String('-',(66 - header.Length) / 2) + header + String('-', (66 - header.Length) / 2),66}""" 
printfn "%24s%11s%11s%11s%11s%11s\n" "1950" "1960" "1970" "1980" "1990" "2000"         

for city in cities do
    printfn $"{city.Item1,-12} {city.Item2,11:N0}{city.Item3,11:N0}{city.Item4,11:N0}{city.Item5,11:N0}{city.Item6,11:N0}{city.Item7,11:N0}"
// The example displays the following output:
//   City          --------------------------Population in--------------------------
//                       1950       1960       1970       1980       1990       2000
//
//   New York       7,891,957  7,781,984  7,894,862  7,071,639  7,322,564  8,008,278
//   Los Angeles    1,970,358  2,479,015  2,816,061  2,966,850  3,485,398  3,694,820
//   Chicago        3,620,962  3,550,904  3,366,957  3,005,072  2,783,726  2,896,016

Module Example
   Public Sub Main()
      ' Create tuples containing population data for New York, Chicago, 
      ' and Los Angeles, 1960-2000.
      Dim cities() =
           { Tuple.Create("New York", 7891957, 7781984, 7894862, 
                          7071639, 7322564, 8008278),
             Tuple.Create("Los Angeles", 1970358, 2479015, 2816061, 
                          2966850, 3485398, 3694820),
             Tuple.Create("Chicago", 3620962, 3550904, 3366957, 
                          3005072, 2783726, 2896016) }

      ' Display tuple data in table.
      Dim header As String = "Population in"
      Console.WriteLine("{0,-12} {1,66}", 
                        "City", New String("-"c,(66-header.Length)\2) + header + _
                                New String("-"c, (66-header.Length)\2))
      Console.WriteLine("{0,24}{1,11}{2,11}{3,11}{4,11}{5,11}", 
                        "1950", "1960", "1970", "1980", "1990", "2000")                  
      Console.WriteLine()
      For Each city In cities                      
         Console.WriteLine("{0,-12} {1,11:N0}{2,11:N0}{3,11:N0}{4,11:N0}{5,11:N0}{6,11:N0}", 
                           city.Item1, city.Item2, city.Item3, city.Item4, 
                           city.Item5, city.Item6, city.Item7)
      Next
   End Sub
End Module
' The example displays the following output:
'    City          --------------------------Population in--------------------------
'                        1950       1960       1970       1980       1990       2000
'    
'    New York       7,891,957  7,781,984  7,894,862  7,071,639  7,322,564  8,008,278
'    Los Angeles    1,970,358  2,479,015  2,816,061  2,966,850  3,485,398  3,694,820
'    Chicago        3,620,962  3,550,904  3,366,957  3,005,072  2,783,726  2,896,016

Poznámky

Typ Item3 komponenty můžete dynamicky určit jedním ze dvou způsobů:

Platí pro