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TimeOnly.AddHours Method

Definition

Overloads

AddHours(Double, Int32)

Returns a new TimeOnly that adds the specified number of hours to the value of this instance. If the result wraps past the end of the day, this method returns the number of excess days as an out parameter.

AddHours(Double)

Returns a new TimeOnly that adds the specified number of hours to the value of this instance.

AddHours(Double, Int32)

Source:
TimeOnly.cs
Source:
TimeOnly.cs
Source:
TimeOnly.cs

Returns a new TimeOnly that adds the specified number of hours to the value of this instance. If the result wraps past the end of the day, this method returns the number of excess days as an out parameter.

public:
 TimeOnly AddHours(double value, [Runtime::InteropServices::Out] int % wrappedDays);
public TimeOnly AddHours (double value, out int wrappedDays);
member this.AddHours : double * int -> TimeOnly
Public Function AddHours (value As Double, ByRef wrappedDays As Integer) As TimeOnly

Parameters

value
Double

A number of whole and fractional hours. The value parameter can be negative or positive.

wrappedDays
Int32

When this method returns, contains the number of excess days, if any, that resulted from wrapping during this addition operation.

Returns

An object whose value is the sum of the time represented by this instance and the number of hours represented by value.

Applies to

AddHours(Double)

Source:
TimeOnly.cs
Source:
TimeOnly.cs
Source:
TimeOnly.cs

Returns a new TimeOnly that adds the specified number of hours to the value of this instance.

public:
 TimeOnly AddHours(double value);
public TimeOnly AddHours (double value);
member this.AddHours : double -> TimeOnly
Public Function AddHours (value As Double) As TimeOnly

Parameters

value
Double

A number of whole and fractional hours. The value parameter can be negative or positive.

Returns

An object whose value is the sum of the time represented by this instance and the number of hours represented by value.

Applies to