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StyleSelector.SelectStyle(Object, DependencyObject) Method

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Definition

Namespace:
System.Windows.Controls
Assembly:
PresentationFramework.dll

When overridden in a derived class, returns a Style based on custom logic.

public:
 virtual System::Windows::Style ^ SelectStyle(System::Object ^ item, System::Windows::DependencyObject ^ container);
public virtual System.Windows.Style SelectStyle (object item, System.Windows.DependencyObject container);
abstract member SelectStyle : obj * System.Windows.DependencyObject -> System.Windows.Style
override this.SelectStyle : obj * System.Windows.DependencyObject -> System.Windows.Style
Public Overridable Function SelectStyle (item As Object, container As DependencyObject) As Style

Parameters

item
Object

The content.

container
DependencyObject

The element to which the style will be applied.

Returns

Style

Returns an application-specific style to apply; otherwise, null.

Examples

The following example shows how to define a StyleSelector that defines a Style for a row. This example defines the Background color according to the row index.

public class ListViewItemStyleSelector : StyleSelector
{
    public override Style SelectStyle(object item, 
        DependencyObject container)
    {
        Style st = new Style();
        st.TargetType = typeof(ListViewItem);
        Setter backGroundSetter = new Setter();
        backGroundSetter.Property = ListViewItem.BackgroundProperty;
        ListView listView = 
            ItemsControl.ItemsControlFromItemContainer(container) 
              as ListView;
        int index = 
            listView.ItemContainerGenerator.IndexFromContainer(container);
        if (index % 2 == 0)
        {
            backGroundSetter.Value = Brushes.LightBlue;
        }
        else
        {
            backGroundSetter.Value = Brushes.Beige;
        }
        st.Setters.Add(backGroundSetter);
        return st;
    }
}

Public Class ListViewItemStyleSelector
    Inherits StyleSelector
    Public Overrides Function SelectStyle(ByVal item As Object, ByVal container As DependencyObject) As Style
        Dim st As New Style()
        st.TargetType = GetType(ListViewItem)
        Dim backGroundSetter As New Setter()
        backGroundSetter.Property = ListViewItem.BackgroundProperty
        Dim listView As ListView = TryCast(ItemsControl.ItemsControlFromItemContainer(container), ListView)
        Dim index As Integer = listView.ItemContainerGenerator.IndexFromContainer(container)
        If index Mod 2 = 0 Then
            backGroundSetter.Value = Brushes.LightBlue
        Else
            backGroundSetter.Value = Brushes.Beige
        End If
        st.Setters.Add(backGroundSetter)
        Return st
    End Function
End Class

The following example shows how to define a ResourceKey for the StyleSelector. The namespc prefix maps to a CLR namespace and the corresponding assembly where the StyleSelector is defined. For more information, see XAML Namespaces and Namespace Mapping for WPF XAML.

<namespc:ListViewItemStyleSelector x:Key="myStyleSelector"/>

The following example shows how to set the ItemContainerStyleSelector property of a ListView to this StyleSelector resource.

<ListView 
      ItemsSource="{Binding Source={StaticResource EmployeeData}, 
                                        XPath=Employee}"
      ItemContainerStyleSelector="{DynamicResource myStyleSelector}" >      
  <ListView.View>
    <GridView>
      <GridViewColumn DisplayMemberBinding="{Binding XPath=FirstName}" 
                      Header="First Name" Width="120"/>
      <GridViewColumn DisplayMemberBinding="{Binding XPath=LastName}" 
                      Header="Last Name" Width="120"/>
      <GridViewColumn DisplayMemberBinding="{Binding XPath=FavoriteCity}" 
                      Header="Favorite City" Width="120"/>
    </GridView>
  </ListView.View>
</ListView>

For an example of how to create a selector to choose a defined style resource, see the implementation of DataTemplateSelector.SelectTemplate, which allows you to use custom logic to select a DataTemplate, based on a similar concept.

Remarks

To create a StyleSelector that applies a style based on custom logic, create a subclass of the StyleSelector class and implement the SelectStyle method.

Applies to

See also