DateTime.AddMonths(Int32) Method

Reference

Definition

Namespace:: System

Assembly:: System.Runtime.dll

Assembly:: mscorlib.dll

Assembly:: netstandard.dll

Source:: DateTime.cs

Source:: DateTime.cs

Source:: DateTime.cs

Important

Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.

Returns a new DateTime that adds the specified number of months to the value of this instance.

public:
 DateTime AddMonths(int months);

public DateTime AddMonths (int months);

member this.AddMonths : int -> DateTime

Public Function AddMonths (months As Integer) As DateTime

Parameters

months: Int32

A number of months. The months parameter can be negative or positive.

Returns

DateTime

An object whose value is the sum of the date and time represented by this instance and months.

Exceptions

ArgumentOutOfRangeException

The resulting DateTime is less than DateTime.MinValue or greater than DateTime.MaxValue.

-or-

months is less than -120,000 or greater than 120,000.

Examples

The following example adds between zero and fifteen months to the last day of December, 2015. In this case, the AddMonths method returns the date of the last day of each month, and successfully handles leap years.

using System;

public class Example
{
   public static void Main()
   {
      var dat = new DateTime(2015, 12, 31);
      for (int ctr = 0; ctr <= 15; ctr++)
         Console.WriteLine(dat.AddMonths(ctr).ToString("d"));
   }
}
// The example displays the following output:
//       12/31/2015
//       1/31/2016
//       2/29/2016
//       3/31/2016
//       4/30/2016
//       5/31/2016
//       6/30/2016
//       7/31/2016
//       8/31/2016
//       9/30/2016
//       10/31/2016
//       11/30/2016
//       12/31/2016
//       1/31/2017
//       2/28/2017
//       3/31/2017

open System

let dat = DateTime(2015, 12, 31)
for i = 0 to 15 do
    printfn $"{dat.AddMonths i:d}"

// The example displays the following output:
//       12/31/2015
//       1/31/2016
//       2/29/2016
//       3/31/2016
//       4/30/2016
//       5/31/2016
//       6/30/2016
//       7/31/2016
//       8/31/2016
//       9/30/2016
//       10/31/2016
//       11/30/2016
//       12/31/2016
//       1/31/2017
//       2/28/2017
//       3/31/2017

Module Example
   Public Sub Main()
      Dim dat As Date = #12/31/2015#
      For ctr As Integer = 0 To 15
         Console.WriteLine(dat.AddMonths(ctr).ToString("d"))
      Next
   End Sub
End Module
' The example displays the following output:
'       12/31/2015
'       1/31/2016
'       2/29/2016
'       3/31/2016
'       4/30/2016
'       5/31/2016
'       6/30/2016
'       7/31/2016
'       8/31/2016
'       9/30/2016
'       10/31/2016
'       11/30/2016
'       12/31/2016
'       1/31/2017
'       2/28/2017
'       3/31/2017

Remarks

This method does not change the value of this DateTime object. Instead, it returns a new DateTime object whose value is the result of this operation.

The AddMonths method calculates the resulting month and year, taking into account leap years and the number of days in a month, then adjusts the day part of the resulting DateTime object. If the resulting day is not a valid day in the resulting month, the last valid day of the resulting month is used. For example, March 31st + 1 month = April 30th, and March 31st - 1 month = February 28 for a non-leap year and February 29 for a leap year.

The time-of-day part of the resulting DateTime object remains the same as this instance.

Applies to

Jagamisviis: