Object.ReferenceEquals(Object, Object) Method
Definition
Important
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Determines whether the specified Object instances are the same instance.
public:
static bool ReferenceEquals(System::Object ^ objA, System::Object ^ objB);
public static bool ReferenceEquals (object objA, object objB);
public static bool ReferenceEquals (object? objA, object? objB);
static member ReferenceEquals : obj * obj -> bool
Public Shared Function ReferenceEquals (objA As Object, objB As Object) As Boolean
Parameters
- objA
- Object
The first object to compare.
- objB
- Object
The second object to compare.
Returns
true
if objA
is the same instance as objB
or if both are null; otherwise, false
.
Examples
The following example uses ReferenceEquals to determine if two objects are the same instance.
using namespace System;
int main()
{
Object^ o = nullptr;
Object^ p = nullptr;
Object^ q = gcnew Object;
Console::WriteLine( Object::ReferenceEquals( o, p ) );
p = q;
Console::WriteLine( Object::ReferenceEquals( p, q ) );
Console::WriteLine( Object::ReferenceEquals( o, p ) );
}
/*
This code produces the following output.
True
True
False
*/
object o = null;
object p = null;
object q = new Object();
Console.WriteLine(Object.ReferenceEquals(o, p));
p = q;
Console.WriteLine(Object.ReferenceEquals(p, q));
Console.WriteLine(Object.ReferenceEquals(o, p));
// This code produces the following output:
// True
// True
// False
let o: obj = null
let mutable p: obj = null
let q = obj ()
printfn $"{Object.ReferenceEquals(o, p)}"
p <- q
printfn $"{Object.ReferenceEquals(p, q)}"
printfn $"{Object.ReferenceEquals(o, p)}"
// This code produces the following output:
// True
// True
// False
Public Class App
Public Shared Sub Main()
Dim o As Object = Nothing
Dim p As Object = Nothing
Dim q As New Object
Console.WriteLine(Object.ReferenceEquals(o, p))
p = q
Console.WriteLine(Object.ReferenceEquals(p, q))
Console.WriteLine(Object.ReferenceEquals(o, p))
End Sub
End Class
' This code produces the following output:
'
' True
' True
' False
'
Remarks
Unlike the Equals method and the equality operator, the ReferenceEquals method cannot be overridden. Because of this, if you want to test two object references for equality and you are unsure about the implementation of the Equals
method, you can call the ReferenceEquals method.
However, the return value of the ReferenceEquals method may appear to be anomalous in these two scenarios:
When comparing value types. If
objA
andobjB
are value types, they are boxed before they are passed to the ReferenceEquals method. This means that if bothobjA
andobjB
represent the same instance of a value type, the ReferenceEquals method nevertheless returnsfalse
, as the following example shows.int int1 = 3; Console.WriteLine(Object.ReferenceEquals(int1, int1)); Console.WriteLine(int1.GetType().IsValueType); // The example displays the following output: // False // True
let int1 = 3 printfn $"{Object.ReferenceEquals(int1, int1)}" printfn $"{int1.GetType().IsValueType}" // The example displays the following output: // False // True
Public Module Example Public Sub Main Dim int1 As Integer = 3 Console.WriteLine(Object.ReferenceEquals(int1, int1)) Console.WriteLine(int1.GetType().IsValueType) End Sub End Module ' The example displays the following output: ' False ' True
For information on boxing value types, see Boxing and Unboxing.
When comparing strings. If
objA
andobjB
are strings, the ReferenceEquals method returnstrue
if the string is interned. It does not perform a test for value equality. In the following example,s1
ands2
are equal because they are two instances of a single interned string. However,s3
ands4
are not equal, because although they have identical string values, that string is not interned.String s1 = "String1"; String s2 = "String1"; Console.WriteLine("s1 = s2: {0}", Object.ReferenceEquals(s1, s2)); Console.WriteLine("{0} interned: {1}", s1, String.IsNullOrEmpty(String.IsInterned(s1)) ? "No" : "Yes"); String suffix = "A"; String s3 = "String" + suffix; String s4 = "String" + suffix; Console.WriteLine("s3 = s4: {0}", Object.ReferenceEquals(s3, s4)); Console.WriteLine("{0} interned: {1}", s3, String.IsNullOrEmpty(String.IsInterned(s3)) ? "No" : "Yes"); // The example displays the following output: // s1 = s2: True // String1 interned: Yes // s3 = s4: False // StringA interned: No
open System let s1 = "String1" let s2 = "String1" printfn $"s1 = s2: {Object.ReferenceEquals(s1, s2)}" printfn $"""{s1} interned: {if String.IsNullOrEmpty(String.IsInterned s1) then "No" else "Yes"}""" let suffix = "A" let s3 = "String" + suffix let s4 = "String" + suffix printfn $"s3 = s4: {Object.ReferenceEquals(s3, s4)}" printfn $"""{s3} interned: {if String.IsNullOrEmpty(String.IsInterned s3) then "No" else "Yes"}""" // The example displays the following output: // s1 = s2: True // String1 interned: Yes // s3 = s4: False // StringA interned: No
Module Example Public Sub Main() Dim s1 As String = "String1" Dim s2 As String = "String1" Console.WriteLine("s1 = s2: {0}", Object.ReferenceEquals(s1, s2)) Console.WriteLine("{0} interned: {1}", s1, If(String.IsNullOrEmpty(String.IsInterned(s1)), "No", "Yes")) Dim suffix As String = "A" Dim s3 = "String" + suffix Dim s4 = "String" + suffix Console.WriteLine("s3 = s4: {0}", Object.ReferenceEquals(s3, s4)) Console.WriteLine("{0} interned: {1}", s3, If(String.IsNullOrEmpty(String.IsInterned(s3)), "No", "Yes")) End Sub End Module ' The example displays the following output: ' s1 = s2: True ' String1 interned: Yes ' s3 = s4: False ' StringA interned: No
For more information about string interning, see String.IsInterned.