DateTime.Date Property

Reference

Definition

Namespace:: System

Assembly:: System.Runtime.dll

Assembly:: mscorlib.dll

Assembly:: netstandard.dll

Source:: DateTime.cs

Source:: DateTime.cs

Source:: DateTime.cs

Important

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Gets the date component of this instance.

public:
 property DateTime Date { DateTime get(); };

public DateTime Date { get; }

member this.Date : DateTime

Public ReadOnly Property Date As DateTime

Property Value

DateTime

A new object with the same date as this instance, and the time value set to 12:00:00 midnight (00:00:00).

Examples

The following example uses the Date property to extract the date component of a DateTime value with its time component set to zero (or 0:00:00, or midnight). It also illustrates that, depending on the format string used when displaying the DateTime value, the time component can continue to appear in formatted output.

using namespace System;

void main()
{
   DateTime^ date1 = gcnew DateTime(2008, 6, 1, 7, 47, 0);
   Console::WriteLine(date1->ToString());
   
   // Get date-only portion of date, without its time.
   DateTime dateOnly = date1->Date;
   // Display date using short date string.
   Console::WriteLine(dateOnly.ToString("d"));
   // Display date using 24-hour clock.
   Console::WriteLine(dateOnly.ToString("g"));
   Console::WriteLine(dateOnly.ToString(L"MM/dd/yyyy HH:mm"));   
}
// The example displays the following output to the console:
//       6/1/2008 7:47:00 AM
//       6/1/2008
//       6/1/2008 12:00 AM
//       06/01/2008 00:00

using System;

public class Example
{
   public static void Main()
   {
      DateTime date1 = new DateTime(2008, 6, 1, 7, 47, 0);
      Console.WriteLine(date1.ToString());

      // Get date-only portion of date, without its time.
      DateTime dateOnly = date1.Date;
      // Display date using short date string.
      Console.WriteLine(dateOnly.ToString("d"));
      // Display date using 24-hour clock.
      Console.WriteLine(dateOnly.ToString("g"));
      Console.WriteLine(dateOnly.ToString("MM/dd/yyyy HH:mm"));
   }
}
// The example displays output like the following output:
//       6/1/2008 7:47:00 AM
//       6/1/2008
//       6/1/2008 12:00 AM
//       06/01/2008 00:00

open System

let date1 = DateTime(2008, 6, 1, 7, 47, 0)
printfn $"{date1}"

// Get date-only portion of date, without its time.
let dateOnly = date1.Date
// Display date using short date string.
printfn $"{dateOnly:d}"
// Display date using 24-hour clock.
printfn $"{dateOnly:g}"
printfn $"""{dateOnly.ToString "MM/dd/yyyy HH:mm"}"""

// The example displays output like the following output:
//       6/1/2008 7:47:00 AM
//       6/1/2008
//       6/1/2008 12:00 AM
//       06/01/2008 00:00

Module Example
   Public Sub Main()
      Dim date1 As Date = #6/1/2008 7:47AM#
      Console.WriteLine(date1.ToString())
      
      ' Get date-only portion of date, without its time.
      Dim dateOnly As Date = date1.Date
      ' Display date using short date string.
      Console.WriteLine(dateOnly.ToString("d"))
      ' Display date using 24-hour clock.
      Console.WriteLine(dateOnly.ToString("g"))
      Console.WriteLine(dateOnly.ToString("MM/dd/yyyy HH:mm"))   
   End Sub
End Module
' The example displays output like the following:
'       6/1/2008 7:47:00 AM                     
'       6/1/2008
'       6/1/2008 12:00 AM
'       06/01/2008 00:00

Remarks

The value of the Kind property of the returned DateTime value is the same as that of the current instance.

Because the DateTime type represents both dates and times in a single type, it is important to avoid misinterpreting a date returned by the Date property as a date and time.

Applies to

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