CharEnumerator.MoveNext Metode

Definisi

Ruang nama:

System

Rakitan:

netstandard.dll, System.Runtime.dll

Sumber:

CharEnumerator.cs

Meningkatkan indeks internal objek saat ini CharEnumerator ke karakter berikutnya dari string enumerasi.

public:
 virtual bool MoveNext();

public bool MoveNext();

abstract member MoveNext : unit -> bool
override this.MoveNext : unit -> bool

Public Function MoveNext () As Boolean

Mengembalikan

Boolean

true jika indeks berhasil dinaikkan dan dalam string enumerasi; jika tidak, false.

Penerapan

MoveNext()

Contoh

Contoh berikut menggunakan CharEnumerator kelas untuk menghitung karakter individual dalam string. Ini membuat instans CharEnumerator objek dengan memanggil String.GetEnumerator metode , berpindah dari satu karakter ke karakter berikutnya dengan memanggil MoveNext metode , dan menampilkan karakter saat ini dengan mengambil nilai Current properti .

string title = "A Tale of Two Cities";
CharEnumerator chEnum = title.GetEnumerator();
int ctr = 1;
string outputLine1 = null;
string outputLine2 = null;
string outputLine3 = null;

while (chEnum.MoveNext())
{
   outputLine1 += ctr < 10 || ctr % 10 != 0 ? "  " : (ctr / 10) + " ";
   outputLine2 += (ctr % 10) + " ";
   outputLine3 += chEnum.Current + " ";
   ctr++;
}

Console.WriteLine("The length of the string is {0} characters:",
                  title.Length);
Console.WriteLine(outputLine1);
Console.WriteLine(outputLine2);
Console.WriteLine(outputLine3);
// The example displays the following output to the console:
//       The length of the string is 20 characters:
//                         1                   2
//       1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0
//       A   T a l e   o f   T w o   C i t i e s

let title = "A Tale of Two Cities"
let chEnum = title.GetEnumerator()

printfn $"The length of the string is {title.Length} characters:"

let mutable outputLine1 = ""
let mutable outputLine2 = ""
let mutable outputLine3 = ""
let mutable i = 1

while chEnum.MoveNext() do
    outputLine1 <- outputLine1 + if i < 10 || i % 10 <> 0 then "  " else $"{i / 10} "
    outputLine2 <- outputLine2 + $"{i % 10} ";
    outputLine3 <- outputLine3 + $"{chEnum.Current} "
    i <- i + 1

printfn "%s" outputLine1
printfn "%s" outputLine2
printfn "%s" outputLine3

// The example displays the following output to the console:
//       The length of the string is 20 characters:
//                         1                   2
//       1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0
//       A   T a l e   o f   T w o   C i t i e s

Dim title As String = "A Tale of Two Cities"
Dim chEnum As CharEnumerator = title.GetEnumerator()
Dim ctr As Integer = 1
Dim outputLine1, outputLine2, outputLine3 As String 

Do While chEnum.MoveNext()
   outputLine1 += CStr(iif(ctr < 10 Or ctr Mod 10 <> 0, "  ", CStr(ctr \ 10) + " ")) 
   outputLine2 += (ctr Mod 10)& " "
   outputLine3 += chEnum.Current & " "
   ctr += 1
Loop

Console.WriteLine("The length of the string is {0} characters:", _
                  title.Length)
Console.WriteLine(outputLine1)
Console.WriteLine(outputLine2)    
Console.WriteLine(outputLine3)
' The example displays the following output to the console:      
'       The length of the string is 20 characters:
'                         1                   2
'       1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0
'       A   T a l e   o f   T w o   C i t i e s

Perhatikan, bagaimanapun, bahwa operasi yang sama dapat dilakukan agak lebih intuitif dengan menggunakan foreach (dalam C#) atau For Each (di Visual Basic), seperti yang ditunjukkan contoh berikut.

string title = "A Tale of Two Cities";
int ctr = 1;
string outputLine1 = null;
string outputLine2 = null;
string outputLine3 = null;

foreach (char ch in title)
{
   outputLine1 += ctr < 10 || ctr % 10 != 0 ? "  " : (ctr / 10) + " ";
   outputLine2 += (ctr % 10) + " ";
   outputLine3 += ch + " ";
   ctr++;
}

Console.WriteLine("The length of the string is {0} characters:",
                  title.Length);
Console.WriteLine(outputLine1);
Console.WriteLine(outputLine2);
Console.WriteLine(outputLine3);
// The example displays the following output to the console:
//       The length of the string is 20 characters:
//                         1                   2
//       1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0
//       A   T a l e   o f   T w o   C i t i e s

let title = "A Tale of Two Cities"
let chEnum = title.GetEnumerator()

printfn $"The length of the string is {title.Length} characters:"

let mutable outputLine1 = ""
let mutable outputLine2 = ""
let mutable outputLine3 = ""
let mutable i = 1

for ch in title do
    outputLine1 <- outputLine1 + if i < 10 || i % 10 <> 0 then "  " else $"{i / 10} "
    outputLine2 <- outputLine2 + $"{i % 10} ";
    outputLine3 <- outputLine3 + $"{ch} "
    i <- i + 1

printfn "%s" outputLine1
printfn "%s" outputLine2
printfn "%s" outputLine3

// The example displays the following output to the console:
//       The length of the string is 20 characters:
//                         1                   2
//       1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0
//       A   T a l e   o f   T w o   C i t i e s

Dim title As String = "A Tale of Two Cities"
Dim ctr As Integer = 1
Dim outputLine1, outputLine2, outputLine3 As String 

For Each ch As Char In title
   outputLine1 += CStr(iif(ctr < 10 Or ctr Mod 10 <> 0, "  ", CStr(ctr \ 10) + " ")) 
   outputLine2 += (ctr Mod 10)& " "
   outputLine3 += ch & " "
   ctr += 1
Next

Console.WriteLine("The length of the string is {0} characters:", _
                  title.Length)
Console.WriteLine(outputLine1)
Console.WriteLine(outputLine2)    
Console.WriteLine(outputLine3)
' The example displays the following output to the console:      
'       The length of the string is 20 characters:
'                         1                   2
'       1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0
'       A   T a l e   o f   T w o   C i t i e s

Keterangan

Kelas CharEnumerator mempertahankan indeks internal ke string enumerasi, dan MoveNext metode meningkatkan indeks satu per satu. Panggil MoveNext setelah memanggil GetEnumerator atau Reset untuk meningkatkan posisi karakter saat ini ke karakter pertama dalam string enumerasi. Periksa apakah nilai yang dikembalikan adalah true untuk menentukan bahwa posisi karakter saat ini valid.

Jika indeks sudah melampaui karakter terakhir dari string enumerasi, indeks tidak diubah dan false dikembalikan.

Perhatikan bahwa jika string enumerasi kosong (""), status CharEnumerator selalu tidak valid. Ini karena indeks internal untuk CharEnumerator awalnya sebelum karakter pertama dari string enumerasi dan karenanya tidak valid. MoveNext secara logis mengatur indeks setelah karakter terakhir (tidak ada) dari string enumerasi, yang juga tidak valid.