Tuple<T1,T2,T3,T4,T5,T6,T7>.Item3 Properti

Definisi

Ruang nama:

System

Rakitan:

netstandard.dll, System.Runtime.dll

Sumber:

Tuple.cs

Mendapatkan nilai komponen ketiga objek saat ini Tuple<T1,T2,T3,T4,T5,T6,T7> .

public:
 property T3 Item3 { T3 get(); };

public T3 Item3 { get; }

member this.Item3 : 'T3

Public ReadOnly Property Item3 As T3

Nilai Properti

T3

Nilai komponen ketiga objek saat ini Tuple<T1,T2,T3,T4,T5,T6,T7> .

Contoh

Contoh berikut mendefinisikan array Tuple<T1,T2,T3,T4,T5,T6,T7> objek yang komponennya berisi data populasi untuk tiga kota AS (New York, Chicago, dan Los Angeles) dari 1950 hingga 2000. Kemudian menampilkan tabel yang mencantumkan data. Untuk menampilkan populasi pada tahun 1960, ia mengambil nilai Item3 properti untuk setiap Tuple<T1,T2,T3,T4,T5,T6,T7> objek.

using System;
using System.Text.RegularExpressions;

public class Class1
{
   public static void Main()
   {
      // Create tuples containing population data for New York, Chicago, 
      // and Los Angeles, 1960-2000.
      Tuple<string, int, int, int, int, int, int>[] cities =
           { Tuple.Create("New York", 7891957, 7781984, 7894862, 7071639, 7322564, 8008278),
             Tuple.Create("Los Angeles", 1970358, 2479015, 2816061, 2966850, 3485398, 3694820),
             Tuple.Create("Chicago", 3620962, 3550904, 3366957, 3005072, 2783726, 2896016) };

      // Display tuple data in table.
      string header = "Population in";
      Console.WriteLine("{0,-12} {1,66}", 
                        "City", new String('-',(66-header.Length)/2) + header + 
                                new String('-', (66-header.Length)/2));
      Console.WriteLine("{0,24}{1,11}{2,11}{3,11}{4,11}{5,11}\n", 
                        "1950", "1960", "1970", "1980", "1990", "2000");         

      foreach (var city in cities)                      
         Console.WriteLine("{0,-12} {1,11:N0}{2,11:N0}{3,11:N0}{4,11:N0}{5,11:N0}{6,11:N0}", 
                           city.Item1, city.Item2, city.Item3, city.Item4, 
                           city.Item5, city.Item6, city.Item7);
   }
}
// The example displays the following output:
//   City          --------------------------Population in--------------------------
//                       1950       1960       1970       1980       1990       2000
//
//   New York       7,891,957  7,781,984  7,894,862  7,071,639  7,322,564  8,008,278
//   Los Angeles    1,970,358  2,479,015  2,816,061  2,966,850  3,485,398  3,694,820
//   Chicago        3,620,962  3,550,904  3,366,957  3,005,072  2,783,726  2,896,016

open System

// Create tuples containing population data for New York, Chicago, 
// and Los Angeles, 1960-2000.
let cities =
    [| Tuple.Create("New York", 7891957, 7781984, 7894862, 7071639, 7322564, 8008278)
       Tuple.Create("Los Angeles", 1970358, 2479015, 2816061, 2966850, 3485398, 3694820)
       Tuple.Create("Chicago", 3620962, 3550904, 3366957, 3005072, 2783726, 2896016) |]

// Display tuple data in table.
let header = "Population in"
printfn $"""{"City",-12} {String('-',(66 - header.Length) / 2) + header + String('-', (66 - header.Length) / 2),66}""" 
printfn "%24s%11s%11s%11s%11s%11s\n" "1950" "1960" "1970" "1980" "1990" "2000"         

for city in cities do
    printfn $"{city.Item1,-12} {city.Item2,11:N0}{city.Item3,11:N0}{city.Item4,11:N0}{city.Item5,11:N0}{city.Item6,11:N0}{city.Item7,11:N0}"
// The example displays the following output:
//   City          --------------------------Population in--------------------------
//                       1950       1960       1970       1980       1990       2000
//
//   New York       7,891,957  7,781,984  7,894,862  7,071,639  7,322,564  8,008,278
//   Los Angeles    1,970,358  2,479,015  2,816,061  2,966,850  3,485,398  3,694,820
//   Chicago        3,620,962  3,550,904  3,366,957  3,005,072  2,783,726  2,896,016

Module Example
   Public Sub Main()
      ' Create tuples containing population data for New York, Chicago, 
      ' and Los Angeles, 1960-2000.
      Dim cities() =
           { Tuple.Create("New York", 7891957, 7781984, 7894862, 
                          7071639, 7322564, 8008278),
             Tuple.Create("Los Angeles", 1970358, 2479015, 2816061, 
                          2966850, 3485398, 3694820),
             Tuple.Create("Chicago", 3620962, 3550904, 3366957, 
                          3005072, 2783726, 2896016) }

      ' Display tuple data in table.
      Dim header As String = "Population in"
      Console.WriteLine("{0,-12} {1,66}", 
                        "City", New String("-"c,(66-header.Length)\2) + header + _
                                New String("-"c, (66-header.Length)\2))
      Console.WriteLine("{0,24}{1,11}{2,11}{3,11}{4,11}{5,11}", 
                        "1950", "1960", "1970", "1980", "1990", "2000")                  
      Console.WriteLine()
      For Each city In cities                      
         Console.WriteLine("{0,-12} {1,11:N0}{2,11:N0}{3,11:N0}{4,11:N0}{5,11:N0}{6,11:N0}", 
                           city.Item1, city.Item2, city.Item3, city.Item4, 
                           city.Item5, city.Item6, city.Item7)
      Next
   End Sub
End Module
' The example displays the following output:
'    City          --------------------------Population in--------------------------
'                        1950       1960       1970       1980       1990       2000
'    
'    New York       7,891,957  7,781,984  7,894,862  7,071,639  7,322,564  8,008,278
'    Los Angeles    1,970,358  2,479,015  2,816,061  2,966,850  3,485,398  3,694,820
'    Chicago        3,620,962  3,550,904  3,366,957  3,005,072  2,783,726  2,896,016

Keterangan

Anda dapat menentukan jenis Item3 komponen secara dinamis dengan salah satu dari dua cara:

• Dengan memanggil GetType metode pada nilai yang dikembalikan oleh Item3 properti .

• Dengan mengambil Type objek yang mewakili Tuple<T1,T2,T3,T4,T5,T6,T7> objek, dan mengambil elemen ketiga dari array yang dikembalikan oleh metodenya Type.GetGenericArguments .