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Tuple<T1,T2,T3,T4,T5,T6,T7>.Item6 Properti

Definisi

Mendapatkan nilai komponen keenam objek saat ini Tuple<T1,T2,T3,T4,T5,T6,T7> .

public:
 property T6 Item6 { T6 get(); };
public T6 Item6 { get; }
member this.Item6 : 'T6
Public ReadOnly Property Item6 As T6

Nilai Properti

T6

Nilai komponen keenam objek saat ini Tuple<T1,T2,T3,T4,T5,T6,T7> .

Contoh

Contoh berikut mendefinisikan array Tuple<T1,T2,T3,T4,T5,T6,T7> objek yang komponennya berisi data populasi untuk tiga kota AS (New York, Chicago, dan Los Angeles) dari 1950 hingga 2000. Kemudian menampilkan tabel yang mencantumkan data. Untuk menampilkan populasi pada tahun 1990, ia mengambil nilai Item6 properti untuk setiap Tuple<T1,T2,T3,T4,T5,T6,T7> objek.

using System;
using System.Text.RegularExpressions;

public class Class1
{
   public static void Main()
   {
      // Create tuples containing population data for New York, Chicago, 
      // and Los Angeles, 1960-2000.
      Tuple<string, int, int, int, int, int, int>[] cities =
           { Tuple.Create("New York", 7891957, 7781984, 7894862, 7071639, 7322564, 8008278),
             Tuple.Create("Los Angeles", 1970358, 2479015, 2816061, 2966850, 3485398, 3694820),
             Tuple.Create("Chicago", 3620962, 3550904, 3366957, 3005072, 2783726, 2896016) };

      // Display tuple data in table.
      string header = "Population in";
      Console.WriteLine("{0,-12} {1,66}", 
                        "City", new String('-',(66-header.Length)/2) + header + 
                                new String('-', (66-header.Length)/2));
      Console.WriteLine("{0,24}{1,11}{2,11}{3,11}{4,11}{5,11}\n", 
                        "1950", "1960", "1970", "1980", "1990", "2000");         

      foreach (var city in cities)                      
         Console.WriteLine("{0,-12} {1,11:N0}{2,11:N0}{3,11:N0}{4,11:N0}{5,11:N0}{6,11:N0}", 
                           city.Item1, city.Item2, city.Item3, city.Item4, 
                           city.Item5, city.Item6, city.Item7);
   }
}
// The example displays the following output:
//   City          --------------------------Population in--------------------------
//                       1950       1960       1970       1980       1990       2000
//
//   New York       7,891,957  7,781,984  7,894,862  7,071,639  7,322,564  8,008,278
//   Los Angeles    1,970,358  2,479,015  2,816,061  2,966,850  3,485,398  3,694,820
//   Chicago        3,620,962  3,550,904  3,366,957  3,005,072  2,783,726  2,896,016
open System

// Create tuples containing population data for New York, Chicago, 
// and Los Angeles, 1960-2000.
let cities =
    [| Tuple.Create("New York", 7891957, 7781984, 7894862, 7071639, 7322564, 8008278)
       Tuple.Create("Los Angeles", 1970358, 2479015, 2816061, 2966850, 3485398, 3694820)
       Tuple.Create("Chicago", 3620962, 3550904, 3366957, 3005072, 2783726, 2896016) |]

// Display tuple data in table.
let header = "Population in"
printfn $"""{"City",-12} {String('-',(66 - header.Length) / 2) + header + String('-', (66 - header.Length) / 2),66}""" 
printfn "%24s%11s%11s%11s%11s%11s\n" "1950" "1960" "1970" "1980" "1990" "2000"         

for city in cities do
    printfn $"{city.Item1,-12} {city.Item2,11:N0}{city.Item3,11:N0}{city.Item4,11:N0}{city.Item5,11:N0}{city.Item6,11:N0}{city.Item7,11:N0}"
// The example displays the following output:
//   City          --------------------------Population in--------------------------
//                       1950       1960       1970       1980       1990       2000
//
//   New York       7,891,957  7,781,984  7,894,862  7,071,639  7,322,564  8,008,278
//   Los Angeles    1,970,358  2,479,015  2,816,061  2,966,850  3,485,398  3,694,820
//   Chicago        3,620,962  3,550,904  3,366,957  3,005,072  2,783,726  2,896,016
Module Example
   Public Sub Main()
      ' Create tuples containing population data for New York, Chicago, 
      ' and Los Angeles, 1960-2000.
      Dim cities() =
           { Tuple.Create("New York", 7891957, 7781984, 7894862, 
                          7071639, 7322564, 8008278),
             Tuple.Create("Los Angeles", 1970358, 2479015, 2816061, 
                          2966850, 3485398, 3694820),
             Tuple.Create("Chicago", 3620962, 3550904, 3366957, 
                          3005072, 2783726, 2896016) }

      ' Display tuple data in table.
      Dim header As String = "Population in"
      Console.WriteLine("{0,-12} {1,66}", 
                        "City", New String("-"c,(66-header.Length)\2) + header + _
                                New String("-"c, (66-header.Length)\2))
      Console.WriteLine("{0,24}{1,11}{2,11}{3,11}{4,11}{5,11}", 
                        "1950", "1960", "1970", "1980", "1990", "2000")                  
      Console.WriteLine()
      For Each city In cities                      
         Console.WriteLine("{0,-12} {1,11:N0}{2,11:N0}{3,11:N0}{4,11:N0}{5,11:N0}{6,11:N0}", 
                           city.Item1, city.Item2, city.Item3, city.Item4, 
                           city.Item5, city.Item6, city.Item7)
      Next
   End Sub
End Module
' The example displays the following output:
'    City          --------------------------Population in--------------------------
'                        1950       1960       1970       1980       1990       2000
'    
'    New York       7,891,957  7,781,984  7,894,862  7,071,639  7,322,564  8,008,278
'    Los Angeles    1,970,358  2,479,015  2,816,061  2,966,850  3,485,398  3,694,820
'    Chicago        3,620,962  3,550,904  3,366,957  3,005,072  2,783,726  2,896,016

Keterangan

Anda dapat menentukan jenis Item6 komponen secara dinamis dengan salah satu dari dua cara:

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