Tuple<T1,T2,T3,T4,T5,T6,T7>.Item6 Properti
Definisi
Penting
Beberapa informasi terkait produk prarilis yang dapat diubah secara signifikan sebelum dirilis. Microsoft tidak memberikan jaminan, tersirat maupun tersurat, sehubungan dengan informasi yang diberikan di sini.
Mendapatkan nilai komponen keenam objek saat ini Tuple<T1,T2,T3,T4,T5,T6,T7> .
public:
property T6 Item6 { T6 get(); };
public T6 Item6 { get; }
member this.Item6 : 'T6
Public ReadOnly Property Item6 As T6
Nilai Properti
Nilai komponen keenam objek saat ini Tuple<T1,T2,T3,T4,T5,T6,T7> .
Contoh
Contoh berikut mendefinisikan array Tuple<T1,T2,T3,T4,T5,T6,T7> objek yang komponennya berisi data populasi untuk tiga kota AS (New York, Chicago, dan Los Angeles) dari 1950 hingga 2000. Kemudian menampilkan tabel yang mencantumkan data. Untuk menampilkan populasi pada tahun 1990, ia mengambil nilai Item6 properti untuk setiap Tuple<T1,T2,T3,T4,T5,T6,T7> objek.
using System;
using System.Text.RegularExpressions;
public class Class1
{
public static void Main()
{
// Create tuples containing population data for New York, Chicago,
// and Los Angeles, 1960-2000.
Tuple<string, int, int, int, int, int, int>[] cities =
{ Tuple.Create("New York", 7891957, 7781984, 7894862, 7071639, 7322564, 8008278),
Tuple.Create("Los Angeles", 1970358, 2479015, 2816061, 2966850, 3485398, 3694820),
Tuple.Create("Chicago", 3620962, 3550904, 3366957, 3005072, 2783726, 2896016) };
// Display tuple data in table.
string header = "Population in";
Console.WriteLine("{0,-12} {1,66}",
"City", new String('-',(66-header.Length)/2) + header +
new String('-', (66-header.Length)/2));
Console.WriteLine("{0,24}{1,11}{2,11}{3,11}{4,11}{5,11}\n",
"1950", "1960", "1970", "1980", "1990", "2000");
foreach (var city in cities)
Console.WriteLine("{0,-12} {1,11:N0}{2,11:N0}{3,11:N0}{4,11:N0}{5,11:N0}{6,11:N0}",
city.Item1, city.Item2, city.Item3, city.Item4,
city.Item5, city.Item6, city.Item7);
}
}
// The example displays the following output:
// City --------------------------Population in--------------------------
// 1950 1960 1970 1980 1990 2000
//
// New York 7,891,957 7,781,984 7,894,862 7,071,639 7,322,564 8,008,278
// Los Angeles 1,970,358 2,479,015 2,816,061 2,966,850 3,485,398 3,694,820
// Chicago 3,620,962 3,550,904 3,366,957 3,005,072 2,783,726 2,896,016
open System
// Create tuples containing population data for New York, Chicago,
// and Los Angeles, 1960-2000.
let cities =
[| Tuple.Create("New York", 7891957, 7781984, 7894862, 7071639, 7322564, 8008278)
Tuple.Create("Los Angeles", 1970358, 2479015, 2816061, 2966850, 3485398, 3694820)
Tuple.Create("Chicago", 3620962, 3550904, 3366957, 3005072, 2783726, 2896016) |]
// Display tuple data in table.
let header = "Population in"
printfn $"""{"City",-12} {String('-',(66 - header.Length) / 2) + header + String('-', (66 - header.Length) / 2),66}"""
printfn "%24s%11s%11s%11s%11s%11s\n" "1950" "1960" "1970" "1980" "1990" "2000"
for city in cities do
printfn $"{city.Item1,-12} {city.Item2,11:N0}{city.Item3,11:N0}{city.Item4,11:N0}{city.Item5,11:N0}{city.Item6,11:N0}{city.Item7,11:N0}"
// The example displays the following output:
// City --------------------------Population in--------------------------
// 1950 1960 1970 1980 1990 2000
//
// New York 7,891,957 7,781,984 7,894,862 7,071,639 7,322,564 8,008,278
// Los Angeles 1,970,358 2,479,015 2,816,061 2,966,850 3,485,398 3,694,820
// Chicago 3,620,962 3,550,904 3,366,957 3,005,072 2,783,726 2,896,016
Module Example
Public Sub Main()
' Create tuples containing population data for New York, Chicago,
' and Los Angeles, 1960-2000.
Dim cities() =
{ Tuple.Create("New York", 7891957, 7781984, 7894862,
7071639, 7322564, 8008278),
Tuple.Create("Los Angeles", 1970358, 2479015, 2816061,
2966850, 3485398, 3694820),
Tuple.Create("Chicago", 3620962, 3550904, 3366957,
3005072, 2783726, 2896016) }
' Display tuple data in table.
Dim header As String = "Population in"
Console.WriteLine("{0,-12} {1,66}",
"City", New String("-"c,(66-header.Length)\2) + header + _
New String("-"c, (66-header.Length)\2))
Console.WriteLine("{0,24}{1,11}{2,11}{3,11}{4,11}{5,11}",
"1950", "1960", "1970", "1980", "1990", "2000")
Console.WriteLine()
For Each city In cities
Console.WriteLine("{0,-12} {1,11:N0}{2,11:N0}{3,11:N0}{4,11:N0}{5,11:N0}{6,11:N0}",
city.Item1, city.Item2, city.Item3, city.Item4,
city.Item5, city.Item6, city.Item7)
Next
End Sub
End Module
' The example displays the following output:
' City --------------------------Population in--------------------------
' 1950 1960 1970 1980 1990 2000
'
' New York 7,891,957 7,781,984 7,894,862 7,071,639 7,322,564 8,008,278
' Los Angeles 1,970,358 2,479,015 2,816,061 2,966,850 3,485,398 3,694,820
' Chicago 3,620,962 3,550,904 3,366,957 3,005,072 2,783,726 2,896,016
Keterangan
Anda dapat menentukan jenis Item6 komponen secara dinamis dengan salah satu dari dua cara:
Dengan memanggil
GetTypemetode pada nilai yang dikembalikan oleh Item6 properti .Dengan mengambil Type objek yang mewakili Tuple<T1,T2,T3,T4,T5,T6,T7> objek, dan mengambil elemen keenam dari array yang dikembalikan oleh metodenya Type.GetGenericArguments .