Properties.Replace Metode
Definisi
Penting
Beberapa informasi terkait produk prarilis yang dapat diubah secara signifikan sebelum dirilis. Microsoft tidak memberikan jaminan, tersirat maupun tersurat, sehubungan dengan informasi yang diberikan di sini.
Overload
| Nama | Deskripsi |
|---|---|
| Replace(Object, Object) | |
| Replace(Object, Object, Object) |
Replace(Object, Object)
[Android.Runtime.Register("replace", "(Ljava/lang/Object;Ljava/lang/Object;)Ljava/lang/Object;", "GetReplace_Ljava_lang_Object_Ljava_lang_Object_Handler", ApiSince=35)]
public virtual Java.Lang.Object? Replace(Java.Lang.Object? key, Java.Lang.Object? value);
[<Android.Runtime.Register("replace", "(Ljava/lang/Object;Ljava/lang/Object;)Ljava/lang/Object;", "GetReplace_Ljava_lang_Object_Ljava_lang_Object_Handler", ApiSince=35)>]
abstract member Replace : Java.Lang.Object * Java.Lang.Object -> Java.Lang.Object
override this.Replace : Java.Lang.Object * Java.Lang.Object -> Java.Lang.Object
Parameter
- key
- Object
- value
- Object
Mengembalikan
- Atribut
Berlaku untuk
Replace(Object, Object, Object)
[Android.Runtime.Register("replace", "(Ljava/lang/Object;Ljava/lang/Object;Ljava/lang/Object;)Z", "GetReplace_Ljava_lang_Object_Ljava_lang_Object_Ljava_lang_Object_Handler", ApiSince=35)]
public virtual bool Replace(Java.Lang.Object? key, Java.Lang.Object? oldValue, Java.Lang.Object? newValue);
[<Android.Runtime.Register("replace", "(Ljava/lang/Object;Ljava/lang/Object;Ljava/lang/Object;)Z", "GetReplace_Ljava_lang_Object_Ljava_lang_Object_Ljava_lang_Object_Handler", ApiSince=35)>]
abstract member Replace : Java.Lang.Object * Java.Lang.Object * Java.Lang.Object -> bool
override this.Replace : Java.Lang.Object * Java.Lang.Object * Java.Lang.Object -> bool
Parameter
- key
- Object
- oldValue
- Object
- newValue
- Object
Mengembalikan
- Atribut