ArrayList.LastIndexOf Metode
Definisi
Penting
Beberapa informasi terkait produk prarilis yang dapat diubah secara signifikan sebelum dirilis. Microsoft tidak memberikan jaminan, tersirat maupun tersurat, sehubungan dengan informasi yang diberikan di sini.
Mengembalikan indeks berbasis nol dari kemunculan terakhir nilai dalam ArrayList atau dalam bagiannya.
Overload
LastIndexOf(Object) |
Mencari Object yang ditentukan dan mengembalikan indeks berbasis nol dari kemunculan terakhir dalam seluruh ArrayList. |
LastIndexOf(Object, Int32) |
Mencari Object yang ditentukan dan mengembalikan indeks berbasis nol dari kemunculan terakhir dalam rentang elemen dalam ArrayList yang meluas dari elemen pertama ke indeks yang ditentukan. |
LastIndexOf(Object, Int32, Int32) |
Mencari Object yang ditentukan dan mengembalikan indeks berbasis nol dari kemunculan terakhir dalam rentang elemen dalam ArrayList yang berisi jumlah elemen yang ditentukan dan berakhir pada indeks yang ditentukan. |
LastIndexOf(Object)
- Sumber:
- ArrayList.cs
- Sumber:
- ArrayList.cs
- Sumber:
- ArrayList.cs
public:
virtual int LastIndexOf(System::Object ^ value);
public virtual int LastIndexOf (object value);
public virtual int LastIndexOf (object? value);
abstract member LastIndexOf : obj -> int
override this.LastIndexOf : obj -> int
Public Overridable Function LastIndexOf (value As Object) As Integer
Parameter
Mengembalikan
Indeks berbasis nol dari kemunculan terakhir value
di seluruh ArrayList, jika ditemukan; jika tidak, -1.
Contoh
Contoh kode berikut menunjukkan cara menentukan indeks kemunculan terakhir elemen yang ditentukan.
using namespace System;
using namespace System::Collections;
void PrintIndexAndValues( IEnumerable^ myList );
int main()
{
// Creates and initializes a new ArrayList with three elements of the same value.
ArrayList^ myAL = gcnew ArrayList;
myAL->Add( "the" );
myAL->Add( "quick" );
myAL->Add( "brown" );
myAL->Add( "fox" );
myAL->Add( "jumps" );
myAL->Add( "over" );
myAL->Add( "the" );
myAL->Add( "lazy" );
myAL->Add( "dog" );
myAL->Add( "in" );
myAL->Add( "the" );
myAL->Add( "barn" );
// Displays the values of the ArrayList.
Console::WriteLine( "The ArrayList contains the following values:" );
PrintIndexAndValues( myAL );
// Searches for the last occurrence of the duplicated value.
String^ myString = "the";
int myIndex = myAL->LastIndexOf( myString );
Console::WriteLine( "The last occurrence of \"{0}\" is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL->LastIndexOf( myString, 8 );
Console::WriteLine( "The last occurrence of \"{0}\" between the start and index 8 is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL->LastIndexOf( myString, 10, 6 );
Console::WriteLine( "The last occurrence of \"{0}\" between index 10 and index 5 is at index {1}.", myString, myIndex );
}
void PrintIndexAndValues( IEnumerable^ myList )
{
int i = 0;
IEnumerator^ myEnum = myList->GetEnumerator();
while ( myEnum->MoveNext() )
{
Object^ obj = safe_cast<Object^>(myEnum->Current);
Console::WriteLine( " [{0}]: {1}", i++, obj );
}
Console::WriteLine();
}
/*
This code produces the following output.
The ArrayList contains the following values:
[0]: the
[1]: quick
[2]: brown
[3]: fox
[4]: jumps
[5]: over
[6]: the
[7]: lazy
[8]: dog
[9]: in
[10]: the
[11]: barn
The last occurrence of "the" is at index 10.
The last occurrence of "the" between the start and index 8 is at index 6.
The last occurrence of "the" between index 10 and index 5 is at index 10.
*/
using System;
using System.Collections;
public class SamplesArrayList {
public static void Main() {
// Creates and initializes a new ArrayList with three elements of the same value.
ArrayList myAL = new ArrayList();
myAL.Add( "the" );
myAL.Add( "quick" );
myAL.Add( "brown" );
myAL.Add( "fox" );
myAL.Add( "jumps" );
myAL.Add( "over" );
myAL.Add( "the" );
myAL.Add( "lazy" );
myAL.Add( "dog" );
myAL.Add( "in" );
myAL.Add( "the" );
myAL.Add( "barn" );
// Displays the values of the ArrayList.
Console.WriteLine( "The ArrayList contains the following values:" );
PrintIndexAndValues( myAL );
// Searches for the last occurrence of the duplicated value.
string myString = "the";
int myIndex = myAL.LastIndexOf( myString );
Console.WriteLine( "The last occurrence of \"{0}\" is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL.LastIndexOf( myString, 8 );
Console.WriteLine( "The last occurrence of \"{0}\" between the start and index 8 is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL.LastIndexOf( myString, 10, 6 );
Console.WriteLine( "The last occurrence of \"{0}\" between index 10 and index 5 is at index {1}.", myString, myIndex );
}
public static void PrintIndexAndValues( IEnumerable myList ) {
int i = 0;
foreach ( Object obj in myList )
Console.WriteLine( " [{0}]: {1}", i++, obj );
Console.WriteLine();
}
}
/*
This code produces the following output.
The ArrayList contains the following values:
[0]: the
[1]: quick
[2]: brown
[3]: fox
[4]: jumps
[5]: over
[6]: the
[7]: lazy
[8]: dog
[9]: in
[10]: the
[11]: barn
The last occurrence of "the" is at index 10.
The last occurrence of "the" between the start and index 8 is at index 6.
The last occurrence of "the" between index 10 and index 5 is at index 10.
*/
Imports System.Collections
Public Class SamplesArrayList
Public Shared Sub Main()
' Creates and initializes a new ArrayList with three elements of the same value.
Dim myAL As New ArrayList()
myAL.Add("the")
myAL.Add("quick")
myAL.Add("brown")
myAL.Add("fox")
myAL.Add("jumps")
myAL.Add("over")
myAL.Add("the")
myAL.Add("lazy")
myAL.Add("dog")
myAL.Add("in")
myAL.Add("the")
myAL.Add("barn")
' Displays the values of the ArrayList.
Console.WriteLine("The ArrayList contains the following values:")
PrintIndexAndValues(myAL)
' Searches for the last occurrence of the duplicated value.
Dim myString As [String] = "the"
Dim myIndex As Integer = myAL.LastIndexOf(myString)
Console.WriteLine("The last occurrence of ""{0}"" is at index {1}.", myString, myIndex)
' Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL.LastIndexOf(myString, 8)
Console.WriteLine("The last occurrence of ""{0}"" between the start and index 8 is at index {1}.", myString, myIndex)
' Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL.LastIndexOf(myString, 10, 6)
Console.WriteLine("The last occurrence of ""{0}"" between index 10 and index 5 is at index {1}.", myString, myIndex)
End Sub
Public Shared Sub PrintIndexAndValues(myList As IEnumerable)
Dim i as Integer
Dim obj As [Object]
For Each obj In myList
Console.WriteLine(" [{0}]: {1}", i, obj)
i = i + 1
Next obj
Console.WriteLine()
End Sub
End Class
' This code produces the following output.
'
' The ArrayList contains the following values:
' [0]: the
' [1]: quick
' [2]: brown
' [3]: fox
' [4]: jumps
' [5]: over
' [6]: the
' [7]: lazy
' [8]: dog
' [9]: in
' [10]: the
' [11]: barn
'
' The last occurrence of "the" is at index 10.
' The last occurrence of "the" between the start and index 8 is at index 6.
' The last occurrence of "the" between index 10 and index 5 is at index 10.
Keterangan
ArrayList dicari mundur mulai dari elemen terakhir dan berakhir pada elemen pertama.
Metode ini melakukan pencarian linier; oleh karena itu, metode ini adalah operasi O(n)
, di mana n
Count.
Dimulai dengan .NET Framework 2.0, metode ini menggunakan metode Equals dan CompareTo objek koleksi pada item
untuk menentukan apakah item ada. Dalam versi .NET Framework sebelumnya, penentuan ini dibuat dengan menggunakan metode Equals dan CompareTo parameter item
pada objek dalam koleksi.
Lihat juga
Berlaku untuk
LastIndexOf(Object, Int32)
- Sumber:
- ArrayList.cs
- Sumber:
- ArrayList.cs
- Sumber:
- ArrayList.cs
public:
virtual int LastIndexOf(System::Object ^ value, int startIndex);
public virtual int LastIndexOf (object value, int startIndex);
public virtual int LastIndexOf (object? value, int startIndex);
abstract member LastIndexOf : obj * int -> int
override this.LastIndexOf : obj * int -> int
Public Overridable Function LastIndexOf (value As Object, startIndex As Integer) As Integer
Parameter
- startIndex
- Int32
Indeks awal berbasis nol dari pencarian mundur.
Mengembalikan
Indeks berbasis nol dari kemunculan terakhir value
dalam rentang elemen dalam ArrayList yang meluas dari elemen pertama ke startIndex
, jika ditemukan; jika tidak, -1.
Pengecualian
startIndex
berada di luar rentang indeks yang valid untuk ArrayList.
Contoh
Contoh kode berikut menunjukkan cara menentukan indeks kemunculan terakhir elemen yang ditentukan.
using namespace System;
using namespace System::Collections;
void PrintIndexAndValues( IEnumerable^ myList );
int main()
{
// Creates and initializes a new ArrayList with three elements of the same value.
ArrayList^ myAL = gcnew ArrayList;
myAL->Add( "the" );
myAL->Add( "quick" );
myAL->Add( "brown" );
myAL->Add( "fox" );
myAL->Add( "jumps" );
myAL->Add( "over" );
myAL->Add( "the" );
myAL->Add( "lazy" );
myAL->Add( "dog" );
myAL->Add( "in" );
myAL->Add( "the" );
myAL->Add( "barn" );
// Displays the values of the ArrayList.
Console::WriteLine( "The ArrayList contains the following values:" );
PrintIndexAndValues( myAL );
// Searches for the last occurrence of the duplicated value.
String^ myString = "the";
int myIndex = myAL->LastIndexOf( myString );
Console::WriteLine( "The last occurrence of \"{0}\" is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL->LastIndexOf( myString, 8 );
Console::WriteLine( "The last occurrence of \"{0}\" between the start and index 8 is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL->LastIndexOf( myString, 10, 6 );
Console::WriteLine( "The last occurrence of \"{0}\" between index 10 and index 5 is at index {1}.", myString, myIndex );
}
void PrintIndexAndValues( IEnumerable^ myList )
{
int i = 0;
IEnumerator^ myEnum = myList->GetEnumerator();
while ( myEnum->MoveNext() )
{
Object^ obj = safe_cast<Object^>(myEnum->Current);
Console::WriteLine( " [{0}]: {1}", i++, obj );
}
Console::WriteLine();
}
/*
This code produces the following output.
The ArrayList contains the following values:
[0]: the
[1]: quick
[2]: brown
[3]: fox
[4]: jumps
[5]: over
[6]: the
[7]: lazy
[8]: dog
[9]: in
[10]: the
[11]: barn
The last occurrence of "the" is at index 10.
The last occurrence of "the" between the start and index 8 is at index 6.
The last occurrence of "the" between index 10 and index 5 is at index 10.
*/
using System;
using System.Collections;
public class SamplesArrayList {
public static void Main() {
// Creates and initializes a new ArrayList with three elements of the same value.
ArrayList myAL = new ArrayList();
myAL.Add( "the" );
myAL.Add( "quick" );
myAL.Add( "brown" );
myAL.Add( "fox" );
myAL.Add( "jumps" );
myAL.Add( "over" );
myAL.Add( "the" );
myAL.Add( "lazy" );
myAL.Add( "dog" );
myAL.Add( "in" );
myAL.Add( "the" );
myAL.Add( "barn" );
// Displays the values of the ArrayList.
Console.WriteLine( "The ArrayList contains the following values:" );
PrintIndexAndValues( myAL );
// Searches for the last occurrence of the duplicated value.
string myString = "the";
int myIndex = myAL.LastIndexOf( myString );
Console.WriteLine( "The last occurrence of \"{0}\" is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL.LastIndexOf( myString, 8 );
Console.WriteLine( "The last occurrence of \"{0}\" between the start and index 8 is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL.LastIndexOf( myString, 10, 6 );
Console.WriteLine( "The last occurrence of \"{0}\" between index 10 and index 5 is at index {1}.", myString, myIndex );
}
public static void PrintIndexAndValues( IEnumerable myList ) {
int i = 0;
foreach ( Object obj in myList )
Console.WriteLine( " [{0}]: {1}", i++, obj );
Console.WriteLine();
}
}
/*
This code produces the following output.
The ArrayList contains the following values:
[0]: the
[1]: quick
[2]: brown
[3]: fox
[4]: jumps
[5]: over
[6]: the
[7]: lazy
[8]: dog
[9]: in
[10]: the
[11]: barn
The last occurrence of "the" is at index 10.
The last occurrence of "the" between the start and index 8 is at index 6.
The last occurrence of "the" between index 10 and index 5 is at index 10.
*/
Imports System.Collections
Public Class SamplesArrayList
Public Shared Sub Main()
' Creates and initializes a new ArrayList with three elements of the same value.
Dim myAL As New ArrayList()
myAL.Add("the")
myAL.Add("quick")
myAL.Add("brown")
myAL.Add("fox")
myAL.Add("jumps")
myAL.Add("over")
myAL.Add("the")
myAL.Add("lazy")
myAL.Add("dog")
myAL.Add("in")
myAL.Add("the")
myAL.Add("barn")
' Displays the values of the ArrayList.
Console.WriteLine("The ArrayList contains the following values:")
PrintIndexAndValues(myAL)
' Searches for the last occurrence of the duplicated value.
Dim myString As [String] = "the"
Dim myIndex As Integer = myAL.LastIndexOf(myString)
Console.WriteLine("The last occurrence of ""{0}"" is at index {1}.", myString, myIndex)
' Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL.LastIndexOf(myString, 8)
Console.WriteLine("The last occurrence of ""{0}"" between the start and index 8 is at index {1}.", myString, myIndex)
' Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL.LastIndexOf(myString, 10, 6)
Console.WriteLine("The last occurrence of ""{0}"" between index 10 and index 5 is at index {1}.", myString, myIndex)
End Sub
Public Shared Sub PrintIndexAndValues(myList As IEnumerable)
Dim i as Integer
Dim obj As [Object]
For Each obj In myList
Console.WriteLine(" [{0}]: {1}", i, obj)
i = i + 1
Next obj
Console.WriteLine()
End Sub
End Class
' This code produces the following output.
'
' The ArrayList contains the following values:
' [0]: the
' [1]: quick
' [2]: brown
' [3]: fox
' [4]: jumps
' [5]: over
' [6]: the
' [7]: lazy
' [8]: dog
' [9]: in
' [10]: the
' [11]: barn
'
' The last occurrence of "the" is at index 10.
' The last occurrence of "the" between the start and index 8 is at index 6.
' The last occurrence of "the" between index 10 and index 5 is at index 10.
Keterangan
ArrayList dicari mundur mulai dari startIndex
dan berakhir pada elemen pertama.
Metode ini melakukan pencarian linier; oleh karena itu, metode ini adalah operasi O(n)
, di mana n
adalah jumlah elemen dari awal ArrayList hingga startIndex
.
Metode ini menentukan kesetaraan dengan memanggil Object.Equals.
Dimulai dengan .NET Framework 2.0, metode ini menggunakan metode Equals dan CompareTo objek koleksi pada item
untuk menentukan apakah item ada. Dalam versi .NET Framework sebelumnya, penentuan ini dibuat dengan menggunakan metode Equals dan CompareTo parameter item
pada objek dalam koleksi.
Lihat juga
Berlaku untuk
LastIndexOf(Object, Int32, Int32)
- Sumber:
- ArrayList.cs
- Sumber:
- ArrayList.cs
- Sumber:
- ArrayList.cs
public:
virtual int LastIndexOf(System::Object ^ value, int startIndex, int count);
public virtual int LastIndexOf (object value, int startIndex, int count);
public virtual int LastIndexOf (object? value, int startIndex, int count);
abstract member LastIndexOf : obj * int * int -> int
override this.LastIndexOf : obj * int * int -> int
Public Overridable Function LastIndexOf (value As Object, startIndex As Integer, count As Integer) As Integer
Parameter
- startIndex
- Int32
Indeks awal berbasis nol dari pencarian mundur.
- count
- Int32
Jumlah elemen di bagian untuk dicari.
Mengembalikan
Indeks berbasis nol dari kemunculan terakhir value
dalam rentang elemen dalam ArrayList yang berisi count
jumlah elemen dan berakhir pada startIndex
, jika ditemukan; jika tidak, -1.
Pengecualian
startIndex
berada di luar rentang indeks yang valid untuk ArrayList.
-atau-
count
kurang dari nol.
-atau-
startIndex
dan count
tidak menentukan bagian yang valid di ArrayList.
Contoh
Contoh kode berikut menunjukkan cara menentukan indeks kemunculan terakhir elemen yang ditentukan. Perhatikan bahwa LastIndexOf
adalah pencarian mundur; oleh karena itu, count
harus kurang dari atau sama dengan startIndex
+ 1.
using namespace System;
using namespace System::Collections;
void PrintIndexAndValues( IEnumerable^ myList );
int main()
{
// Creates and initializes a new ArrayList with three elements of the same value.
ArrayList^ myAL = gcnew ArrayList;
myAL->Add( "the" );
myAL->Add( "quick" );
myAL->Add( "brown" );
myAL->Add( "fox" );
myAL->Add( "jumps" );
myAL->Add( "over" );
myAL->Add( "the" );
myAL->Add( "lazy" );
myAL->Add( "dog" );
myAL->Add( "in" );
myAL->Add( "the" );
myAL->Add( "barn" );
// Displays the values of the ArrayList.
Console::WriteLine( "The ArrayList contains the following values:" );
PrintIndexAndValues( myAL );
// Searches for the last occurrence of the duplicated value.
String^ myString = "the";
int myIndex = myAL->LastIndexOf( myString );
Console::WriteLine( "The last occurrence of \"{0}\" is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL->LastIndexOf( myString, 8 );
Console::WriteLine( "The last occurrence of \"{0}\" between the start and index 8 is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL->LastIndexOf( myString, 10, 6 );
Console::WriteLine( "The last occurrence of \"{0}\" between index 10 and index 5 is at index {1}.", myString, myIndex );
}
void PrintIndexAndValues( IEnumerable^ myList )
{
int i = 0;
IEnumerator^ myEnum = myList->GetEnumerator();
while ( myEnum->MoveNext() )
{
Object^ obj = safe_cast<Object^>(myEnum->Current);
Console::WriteLine( " [{0}]: {1}", i++, obj );
}
Console::WriteLine();
}
/*
This code produces the following output.
The ArrayList contains the following values:
[0]: the
[1]: quick
[2]: brown
[3]: fox
[4]: jumps
[5]: over
[6]: the
[7]: lazy
[8]: dog
[9]: in
[10]: the
[11]: barn
The last occurrence of "the" is at index 10.
The last occurrence of "the" between the start and index 8 is at index 6.
The last occurrence of "the" between index 10 and index 5 is at index 10.
*/
using System;
using System.Collections;
public class SamplesArrayList {
public static void Main() {
// Creates and initializes a new ArrayList with three elements of the same value.
ArrayList myAL = new ArrayList();
myAL.Add( "the" );
myAL.Add( "quick" );
myAL.Add( "brown" );
myAL.Add( "fox" );
myAL.Add( "jumps" );
myAL.Add( "over" );
myAL.Add( "the" );
myAL.Add( "lazy" );
myAL.Add( "dog" );
myAL.Add( "in" );
myAL.Add( "the" );
myAL.Add( "barn" );
// Displays the values of the ArrayList.
Console.WriteLine( "The ArrayList contains the following values:" );
PrintIndexAndValues( myAL );
// Searches for the last occurrence of the duplicated value.
string myString = "the";
int myIndex = myAL.LastIndexOf( myString );
Console.WriteLine( "The last occurrence of \"{0}\" is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL.LastIndexOf( myString, 8 );
Console.WriteLine( "The last occurrence of \"{0}\" between the start and index 8 is at index {1}.", myString, myIndex );
// Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL.LastIndexOf( myString, 10, 6 );
Console.WriteLine( "The last occurrence of \"{0}\" between index 10 and index 5 is at index {1}.", myString, myIndex );
}
public static void PrintIndexAndValues( IEnumerable myList ) {
int i = 0;
foreach ( Object obj in myList )
Console.WriteLine( " [{0}]: {1}", i++, obj );
Console.WriteLine();
}
}
/*
This code produces the following output.
The ArrayList contains the following values:
[0]: the
[1]: quick
[2]: brown
[3]: fox
[4]: jumps
[5]: over
[6]: the
[7]: lazy
[8]: dog
[9]: in
[10]: the
[11]: barn
The last occurrence of "the" is at index 10.
The last occurrence of "the" between the start and index 8 is at index 6.
The last occurrence of "the" between index 10 and index 5 is at index 10.
*/
Imports System.Collections
Public Class SamplesArrayList
Public Shared Sub Main()
' Creates and initializes a new ArrayList with three elements of the same value.
Dim myAL As New ArrayList()
myAL.Add("the")
myAL.Add("quick")
myAL.Add("brown")
myAL.Add("fox")
myAL.Add("jumps")
myAL.Add("over")
myAL.Add("the")
myAL.Add("lazy")
myAL.Add("dog")
myAL.Add("in")
myAL.Add("the")
myAL.Add("barn")
' Displays the values of the ArrayList.
Console.WriteLine("The ArrayList contains the following values:")
PrintIndexAndValues(myAL)
' Searches for the last occurrence of the duplicated value.
Dim myString As [String] = "the"
Dim myIndex As Integer = myAL.LastIndexOf(myString)
Console.WriteLine("The last occurrence of ""{0}"" is at index {1}.", myString, myIndex)
' Searches for the last occurrence of the duplicated value in the first section of the ArrayList.
myIndex = myAL.LastIndexOf(myString, 8)
Console.WriteLine("The last occurrence of ""{0}"" between the start and index 8 is at index {1}.", myString, myIndex)
' Searches for the last occurrence of the duplicated value in a section of the ArrayList. Note that the start index is greater than the end index because the search is done backward.
myIndex = myAL.LastIndexOf(myString, 10, 6)
Console.WriteLine("The last occurrence of ""{0}"" between index 10 and index 5 is at index {1}.", myString, myIndex)
End Sub
Public Shared Sub PrintIndexAndValues(myList As IEnumerable)
Dim i as Integer
Dim obj As [Object]
For Each obj In myList
Console.WriteLine(" [{0}]: {1}", i, obj)
i = i + 1
Next obj
Console.WriteLine()
End Sub
End Class
' This code produces the following output.
'
' The ArrayList contains the following values:
' [0]: the
' [1]: quick
' [2]: brown
' [3]: fox
' [4]: jumps
' [5]: over
' [6]: the
' [7]: lazy
' [8]: dog
' [9]: in
' [10]: the
' [11]: barn
'
' The last occurrence of "the" is at index 10.
' The last occurrence of "the" between the start and index 8 is at index 6.
' The last occurrence of "the" between index 10 and index 5 is at index 10.
Keterangan
ArrayList dicari mundur mulai dari startIndex
dan berakhir pada startIndex
dikurangi count
ditambah 1, jika count
lebih besar dari 0.
Metode ini melakukan pencarian linier; oleh karena itu, metode ini adalah operasi O(n)
, di mana n
count
.
Metode ini menentukan kesetaraan dengan memanggil Object.Equals.
Dimulai dengan .NET Framework 2.0, metode ini menggunakan metode Equals dan CompareTo objek koleksi pada item
untuk menentukan apakah item ada. Dalam versi .NET Framework sebelumnya, penentuan ini dibuat dengan menggunakan metode Equals dan CompareTo parameter item
pada objek dalam koleksi.