Math.Log Metode

Referensi

Definisi

Ruang nama:: System

Rakitan:: System.Runtime.Extensions.dll

Rakitan:: System.Runtime.dll

Rakitan:: mscorlib.dll

Rakitan:: netstandard.dll

Penting

Beberapa informasi terkait produk prarilis yang dapat diubah secara signifikan sebelum dirilis. Microsoft tidak memberikan jaminan, tersirat maupun tersurat, sehubungan dengan informasi yang diberikan di sini.

Mengembalikan logaritma dari angka yang ditentukan.

Overload

Log(Double, Double)	Mengembalikan logaritma dari angka tertentu dalam basis tertentu.
Log(Double)	Mengembalikan logaritma alami (dasar `e`) dari angka tertentu.

Log(Double, Double)

Sumber:: Math.cs

Sumber:: Math.cs

Sumber:: Math.cs

Mengembalikan logaritma dari angka tertentu dalam basis tertentu.

public:
 static double Log(double a, double newBase);

public static double Log (double a, double newBase);

static member Log : double * double -> double

Public Shared Function Log (a As Double, newBase As Double) As Double

Parameter

a: Double

Angka yang logaritmanya akan ditemukan.

newBase: Double

Dasar logaritma.

Mengembalikan

Double

Salah satu nilai dalam tabel berikut ini. (+Infinity menunjukkan PositiveInfinity, -Infinity menunjukkan NegativeInfinity, dan NaN menunjukkan NaN.)

`a`	`newBase`	Mengembalikan nilai
`a`> 0	(0 <`newBase`< 1) -atau- (`newBase`> 1)	lognewBase(a)
`a`< 0	(nilai apa pun)	NaN
(nilai apa pun)	`newBase`< 0	NaN
`a` != 1	`newBase` = 0	NaN
`a` != 1	`newBase` = +Tak terbatas	NaN
`a` = NaN	(nilai apa pun)	NaN
(nilai apa pun)	`newBase` = NaN	NaN
(nilai apa pun)	`newBase` = 1	NaN
`a` = 0	0 <`newBase`< 1	+Tak terbatas
`a` = 0	`newBase`> 1	-Infinity
`a` = +Tak terbatas	0 <`newBase`< 1	-Infinity
`a` = +Tak terbatas	`newBase`> 1	+Tak terbatas
`a` = 1	`newBase` = 0	0
`a` = 1	`newBase` = +Tak terbatas	0

Contoh

Contoh berikut menggunakan Log untuk mengevaluasi identitas logaritmik tertentu untuk nilai yang dipilih.

// Example for the Math::Log( double ) and Math::Log( double, double ) methods.
using namespace System;

// Evaluate logarithmic identities that are functions of two arguments.
void UseBaseAndArg( double argB, double argX )
{
   
   // Evaluate log(B)[X] == 1 / log(X)[B].
   Console::WriteLine( "\n                     Math::Log({1}, {0}) == {2:E16}"
   "\n               1.0 / Math::Log({0}, {1}) == {3:E16}", argB, argX, Math::Log( argX, argB ), 1.0 / Math::Log( argB, argX ) );
   
   // Evaluate log(B)[X] == ln[X] / ln[B].
   Console::WriteLine( "         Math::Log({1}) / Math::Log({0}) == {2:E16}", argB, argX, Math::Log( argX ) / Math::Log( argB ) );
   
   // Evaluate log(B)[X] == log(B)[e] * ln[X].
   Console::WriteLine( "Math::Log(Math::E, {0}) * Math::Log({1}) == {2:E16}", argB, argX, Math::Log( Math::E, argB ) * Math::Log( argX ) );
}

void main()
{
   Console::WriteLine( "This example of Math::Log( double ) and "
   "Math::Log( double, double )\n"
   "generates the following output.\n" );
   Console::WriteLine( "Evaluate these identities with "
   "selected values for X and B (base):" );
   Console::WriteLine( "   log(B)[X] == 1 / log(X)[B]" );
   Console::WriteLine( "   log(B)[X] == ln[X] / ln[B]" );
   Console::WriteLine( "   log(B)[X] == log(B)[e] * ln[X]" );
   UseBaseAndArg( 0.1, 1.2 );
   UseBaseAndArg( 1.2, 4.9 );
   UseBaseAndArg( 4.9, 9.9 );
   UseBaseAndArg( 9.9, 0.1 );
}

/*
This example of Math::Log( double ) and Math::Log( double, double )
generates the following output.

Evaluate these identities with selected values for X and B (base):
   log(B)[X] == 1 / log(X)[B]
   log(B)[X] == ln[X] / ln[B]
   log(B)[X] == log(B)[e] * ln[X]

                     Math::Log(1.2, 0.1) == -7.9181246047624818E-002
               1.0 / Math::Log(0.1, 1.2) == -7.9181246047624818E-002
         Math::Log(1.2) / Math::Log(0.1) == -7.9181246047624818E-002
Math::Log(Math::E, 0.1) * Math::Log(1.2) == -7.9181246047624804E-002

                     Math::Log(4.9, 1.2) == 8.7166610085093179E+000
               1.0 / Math::Log(1.2, 4.9) == 8.7166610085093161E+000
         Math::Log(4.9) / Math::Log(1.2) == 8.7166610085093179E+000
Math::Log(Math::E, 1.2) * Math::Log(4.9) == 8.7166610085093179E+000

                     Math::Log(9.9, 4.9) == 1.4425396251981288E+000
               1.0 / Math::Log(4.9, 9.9) == 1.4425396251981288E+000
         Math::Log(9.9) / Math::Log(4.9) == 1.4425396251981288E+000
Math::Log(Math::E, 4.9) * Math::Log(9.9) == 1.4425396251981288E+000

                     Math::Log(0.1, 9.9) == -1.0043839404494075E+000
               1.0 / Math::Log(9.9, 0.1) == -1.0043839404494075E+000
         Math::Log(0.1) / Math::Log(9.9) == -1.0043839404494075E+000
Math::Log(Math::E, 9.9) * Math::Log(0.1) == -1.0043839404494077E+000
*/

// Example for the Math.Log( double ) and Math.Log( double, double ) methods.
using System;

class LogDLogDD
{
    public static void Main()
    {
        Console.WriteLine(
            "This example of Math.Log( double ) and " +
            "Math.Log( double, double )\n" +
            "generates the following output.\n" );
        Console.WriteLine(
            "Evaluate these identities with " +
            "selected values for X and B (base):" );
        Console.WriteLine( "   log(B)[X] == 1 / log(X)[B]" );
        Console.WriteLine( "   log(B)[X] == ln[X] / ln[B]" );
        Console.WriteLine( "   log(B)[X] == log(B)[e] * ln[X]" );

        UseBaseAndArg(0.1, 1.2);
        UseBaseAndArg(1.2, 4.9);
        UseBaseAndArg(4.9, 9.9);
        UseBaseAndArg(9.9, 0.1);
    }

    // Evaluate logarithmic identities that are functions of two arguments.
    static void UseBaseAndArg(double argB, double argX)
    {
        // Evaluate log(B)[X] == 1 / log(X)[B].
        Console.WriteLine(
            "\n                   Math.Log({1}, {0}) == {2:E16}" +
            "\n             1.0 / Math.Log({0}, {1}) == {3:E16}",
            argB, argX, Math.Log(argX, argB),
            1.0 / Math.Log(argB, argX) );

        // Evaluate log(B)[X] == ln[X] / ln[B].
        Console.WriteLine(
            "        Math.Log({1}) / Math.Log({0}) == {2:E16}",
            argB, argX, Math.Log(argX) / Math.Log(argB) );

        // Evaluate log(B)[X] == log(B)[e] * ln[X].
        Console.WriteLine(
            "Math.Log(Math.E, {0}) * Math.Log({1}) == {2:E16}",
            argB, argX, Math.Log(Math.E, argB) * Math.Log(argX) );
    }
}

/*
This example of Math.Log( double ) and Math.Log( double, double )
generates the following output.

Evaluate these identities with selected values for X and B (base):
   log(B)[X] == 1 / log(X)[B]
   log(B)[X] == ln[X] / ln[B]
   log(B)[X] == log(B)[e] * ln[X]

                   Math.Log(1.2, 0.1) == -7.9181246047624818E-002
             1.0 / Math.Log(0.1, 1.2) == -7.9181246047624818E-002
        Math.Log(1.2) / Math.Log(0.1) == -7.9181246047624818E-002
Math.Log(Math.E, 0.1) * Math.Log(1.2) == -7.9181246047624804E-002

                   Math.Log(4.9, 1.2) == 8.7166610085093179E+000
             1.0 / Math.Log(1.2, 4.9) == 8.7166610085093161E+000
        Math.Log(4.9) / Math.Log(1.2) == 8.7166610085093179E+000
Math.Log(Math.E, 1.2) * Math.Log(4.9) == 8.7166610085093179E+000

                   Math.Log(9.9, 4.9) == 1.4425396251981288E+000
             1.0 / Math.Log(4.9, 9.9) == 1.4425396251981288E+000
        Math.Log(9.9) / Math.Log(4.9) == 1.4425396251981288E+000
Math.Log(Math.E, 4.9) * Math.Log(9.9) == 1.4425396251981288E+000

                   Math.Log(0.1, 9.9) == -1.0043839404494075E+000
             1.0 / Math.Log(9.9, 0.1) == -1.0043839404494075E+000
        Math.Log(0.1) / Math.Log(9.9) == -1.0043839404494075E+000
Math.Log(Math.E, 9.9) * Math.Log(0.1) == -1.0043839404494077E+000
*/

// Example for the Math.Log( double ) and Math.Log( double, double ) methods.
open System

// Evaluate logarithmic identities that are functions of two arguments.
let useBaseAndArg argB argX =
    // Evaluate log(B)[X] == 1 / log(X)[B].
    printfn $"""
                   Math.Log({argX}, {argB}) == {Math.Log(argX, argB):E16}
             1.0 / Math.Log({argB}, {argX}) == {1. / Math.Log(argB, argX):E16}"""

    // Evaluate log(B)[X] == ln[X] / ln[B].
    printfn $"        Math.Log({argX}) / Math.Log({argB}) == {Math.Log argX / Math.Log argB:E16}"

    // Evaluate log(B)[X] == log(B)[e] * ln[X].
    printfn $"Math.Log(Math.E, {argB}) * Math.Log({argX}) == {Math.Log(Math.E, argB) * Math.Log argX:E16}"


printfn
    """This example of Math.Log( double ) and Math.Log( double, double )
generates the following output.

printfn "Evaluate these identities with selected values for X and B (base):"""
printfn "   log(B)[X] == 1 / log(X)[B]"
printfn "   log(B)[X] == ln[X] / ln[B]" 
printfn "   log(B)[X] == log(B)[e] * ln[X]" 

useBaseAndArg 0.1 1.2
useBaseAndArg 1.2 4.9
useBaseAndArg 4.9 9.9
useBaseAndArg 9.9 0.1


// This example of Math.Log( double ) and Math.Log( double, double )
// generates the following output.
//
// Evaluate these identities with selected values for X and B (base):
//    log(B)[X] == 1 / log(X)[B]
//    log(B)[X] == ln[X] / ln[B]
//    log(B)[X] == log(B)[e] * ln[X]
//
//                    Math.Log(1.2, 0.1) == -7.9181246047624818E-002
//              1.0 / Math.Log(0.1, 1.2) == -7.9181246047624818E-002
//         Math.Log(1.2) / Math.Log(0.1) == -7.9181246047624818E-002
// Math.Log(Math.E, 0.1) * Math.Log(1.2) == -7.9181246047624804E-002
//
//                    Math.Log(4.9, 1.2) == 8.7166610085093179E+000
//              1.0 / Math.Log(1.2, 4.9) == 8.7166610085093161E+000
//         Math.Log(4.9) / Math.Log(1.2) == 8.7166610085093179E+000
// Math.Log(Math.E, 1.2) * Math.Log(4.9) == 8.7166610085093179E+000
//
//                    Math.Log(9.9, 4.9) == 1.4425396251981288E+000
//              1.0 / Math.Log(4.9, 9.9) == 1.4425396251981288E+000
//         Math.Log(9.9) / Math.Log(4.9) == 1.4425396251981288E+000
// Math.Log(Math.E, 4.9) * Math.Log(9.9) == 1.4425396251981288E+000
//
//                    Math.Log(0.1, 9.9) == -1.0043839404494075E+000
//              1.0 / Math.Log(9.9, 0.1) == -1.0043839404494075E+000
//         Math.Log(0.1) / Math.Log(9.9) == -1.0043839404494075E+000
// Math.Log(Math.E, 9.9) * Math.Log(0.1) == -1.0043839404494077E+000

' Example for the Math.Log( Double ) and Math.Log( Double, Double ) methods.
Module LogDLogDD
   
    Sub Main()
        Console.WriteLine( _
            "This example of Math.Log( Double ) and " + _
            "Math.Log( Double, Double )" & vbCrLf & _
            "generates the following output." & vbCrLf)
        Console.WriteLine( _
            "Evaluate these identities with selected " & _
            "values for X and B (base):")
        Console.WriteLine("   log(B)[X] = 1 / log(X)[B]")
        Console.WriteLine("   log(B)[X] = ln[X] / ln[B]")
        Console.WriteLine("   log(B)[X] = log(B)[e] * ln[X]")
          
        UseBaseAndArg(0.1, 1.2)
        UseBaseAndArg(1.2, 4.9)
        UseBaseAndArg(4.9, 9.9)
        UseBaseAndArg(9.9, 0.1)
    End Sub
       
    ' Evaluate logarithmic identities that are functions of two arguments.
    Sub UseBaseAndArg(argB As Double, argX As Double)

        ' Evaluate log(B)[X] = 1 / log(X)[B].
        Console.WriteLine( _
            vbCrLf & "                   Math.Log({1}, {0}) = {2:E16}" + _
            vbCrLf & "             1.0 / Math.Log({0}, {1}) = {3:E16}", _
            argB, argX, Math.Log(argX, argB), _
            1.0 / Math.Log(argB, argX))
          
        ' Evaluate log(B)[X] = ln[X] / ln[B].
        Console.WriteLine( _
            "        Math.Log({1}) / Math.Log({0}) = {2:E16}", _
            argB, argX, Math.Log(argX) / Math.Log(argB))
          
        ' Evaluate log(B)[X] = log(B)[e] * ln[X].
        Console.WriteLine( _
            "Math.Log(Math.E, {0}) * Math.Log({1}) = {2:E16}", _
            argB, argX, Math.Log(Math.E, argB) * Math.Log(argX))

    End Sub
End Module 'LogDLogDD

' This example of Math.Log( Double ) and Math.Log( Double, Double )
' generates the following output.
' 
' Evaluate these identities with selected values for X and B (base):
'    log(B)[X] = 1 / log(X)[B]
'    log(B)[X] = ln[X] / ln[B]
'    log(B)[X] = log(B)[e] * ln[X]
' 
'                    Math.Log(1.2, 0.1) = -7.9181246047624818E-002
'              1.0 / Math.Log(0.1, 1.2) = -7.9181246047624818E-002
'         Math.Log(1.2) / Math.Log(0.1) = -7.9181246047624818E-002
' Math.Log(Math.E, 0.1) * Math.Log(1.2) = -7.9181246047624804E-002
' 
'                    Math.Log(4.9, 1.2) = 8.7166610085093179E+000
'              1.0 / Math.Log(1.2, 4.9) = 8.7166610085093161E+000
'         Math.Log(4.9) / Math.Log(1.2) = 8.7166610085093179E+000
' Math.Log(Math.E, 1.2) * Math.Log(4.9) = 8.7166610085093179E+000
' 
'                    Math.Log(9.9, 4.9) = 1.4425396251981288E+000
'              1.0 / Math.Log(4.9, 9.9) = 1.4425396251981288E+000
'         Math.Log(9.9) / Math.Log(4.9) = 1.4425396251981288E+000
' Math.Log(Math.E, 4.9) * Math.Log(9.9) = 1.4425396251981288E+000
' 
'                    Math.Log(0.1, 9.9) = -1.0043839404494075E+000
'              1.0 / Math.Log(9.9, 0.1) = -1.0043839404494075E+000
'         Math.Log(0.1) / Math.Log(9.9) = -1.0043839404494075E+000
' Math.Log(Math.E, 9.9) * Math.Log(0.1) = -1.0043839404494077E+000

Keterangan

Metode ini memanggil runtime C yang mendasarinya, dan hasil yang tepat atau rentang input yang valid mungkin berbeda antara sistem operasi atau arsitektur yang berbeda.

Berlaku untuk

Log(Double)

Sumber:: Math.cs

Sumber:: Math.cs

Sumber:: Math.cs

Mengembalikan logaritma alami (dasar e) dari angka tertentu.

public:
 static double Log(double d);

public static double Log (double d);

static member Log : double -> double

Public Shared Function Log (d As Double) As Double

Parameter

d: Double

Angka yang logaritmanya akan ditemukan.

Mengembalikan

Double

Salah satu nilai dalam tabel berikut ini.

parameter `d`	Nilai kembali
Positif	Logaritma alami dari `d`; yaitu, ln `d`, atau log e `d`
Nol	NegativeInfinity
Negatif	NaN
Sama dengan NaN	NaN
Sama dengan PositiveInfinity	PositiveInfinity

Contoh

Contoh berikut mengilustrasikan Log metode .

using System;
public class Example
{
   public static void Main()
   {
      Console.WriteLine("  Evaluate this identity with selected values for X:");
      Console.WriteLine("                              ln(x) = 1 / log[X](B)");
      Console.WriteLine();

      double[] XArgs = { 1.2, 4.9, 9.9, 0.1 };

      foreach (double argX in XArgs)
      {
         // Find natural log of argX.
         Console.WriteLine("                      Math.Log({0}) = {1:E16}",
                           argX, Math.Log(argX));

         // Evaluate 1 / log[X](e).
         Console.WriteLine("             1.0 / Math.Log(e, {0}) = {1:E16}",
                           argX, 1.0 / Math.Log(Math.E, argX));
         Console.WriteLine();
      }
   }
}
// This example displays the following output:
//         Evaluate this identity with selected values for X:
//                                     ln(x) = 1 / log[X](B)
//
//                             Math.Log(1.2) = 1.8232155679395459E-001
//                    1.0 / Math.Log(e, 1.2) = 1.8232155679395459E-001
//
//                             Math.Log(4.9) = 1.5892352051165810E+000
//                    1.0 / Math.Log(e, 4.9) = 1.5892352051165810E+000
//
//                             Math.Log(9.9) = 2.2925347571405443E+000
//                    1.0 / Math.Log(e, 9.9) = 2.2925347571405443E+000
//
//                             Math.Log(0.1) = -2.3025850929940455E+000
//                    1.0 / Math.Log(e, 0.1) = -2.3025850929940455E+000

open System

printfn "  Evaluate this identity with selected values for X:"
printfn "                              ln(x) = 1 / log[X](B)\n"

let XArgs = [| 1.2; 4.9; 9.9; 0.1 |]

for argX in XArgs do
    // Find natural log of argX.
    // The F# log function may be used instead
    printfn $"                      Math.Log({argX}) = {Math.Log argX:E16}"

    // Evaluate 1 / log[X](e).
    printfn $"             1.0 / Math.Log(e, {argX}) = {1. / Math.Log(Math.E, argX):E16}\n"

// This example displays the following output:
//         Evaluate this identity with selected values for X:
//                                     ln(x) = 1 / log[X](B)
//
//                             Math.Log(1.2) = 1.8232155679395459E-001
//                    1.0 / Math.Log(e, 1.2) = 1.8232155679395459E-001
//
//                             Math.Log(4.9) = 1.5892352051165810E+000
//                    1.0 / Math.Log(e, 4.9) = 1.5892352051165810E+000
//
//                             Math.Log(9.9) = 2.2925347571405443E+000
//                    1.0 / Math.Log(e, 9.9) = 2.2925347571405443E+000
//
//                             Math.Log(0.1) = -2.3025850929940455E+000
//                    1.0 / Math.Log(e, 0.1) = -2.3025850929940455E+000

Module Example
   Sub Main()
      Console.WriteLine( _
         "  Evaluate this identity with selected values for X:")
      Console.WriteLine("                              ln(x) = 1 / log[X](B)")
      Console.WriteLine()
          
      Dim XArgs() As Double = { 1.2, 4.9, 9.9, 0.1 }
   
      For Each argX As Double In XArgs
         ' Find natural log of argX.
         Console.WriteLine("                      Math.Log({0}) = {1:E16}", _
                           argX, Math.Log(argX))

         ' Evaluate 1 / log[X](e).
         Console.WriteLine("             1.0 / Math.Log(e, {0}) = {1:E16}", _
                           argX, 1.0 / Math.Log(Math.E, argX))
         Console.WriteLine()
      Next
   End Sub 
End Module
' This example displays the following output:
'         Evaluate this identity with selected values for X:
'                                     ln(x) = 1 / log[X](B)
'       
'                             Math.Log(1.2) = 1.8232155679395459E-001
'                    1.0 / Math.Log(e, 1.2) = 1.8232155679395459E-001
'       
'                             Math.Log(4.9) = 1.5892352051165810E+000
'                    1.0 / Math.Log(e, 4.9) = 1.5892352051165810E+000
'       
'                             Math.Log(9.9) = 2.2925347571405443E+000
'                    1.0 / Math.Log(e, 9.9) = 2.2925347571405443E+000
'       
'                             Math.Log(0.1) = -2.3025850929940455E+000
'                    1.0 / Math.Log(e, 0.1) = -2.3025850929940455E+000

Keterangan

Parameter d ditentukan sebagai angka dasar 10.

Metode ini memanggil runtime C yang mendasarinya, dan hasil yang tepat atau rentang input yang valid mungkin berbeda antara sistem operasi atau arsitektur yang berbeda.

Lihat juga

Berlaku untuk

Math.Log Metode

Definisi

Overload

Log(Double, Double)

Parameter

Mengembalikan

Contoh

Keterangan

Berlaku untuk

Log(Double)

Parameter

Mengembalikan

Contoh

Keterangan

Lihat juga

Berlaku untuk

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