TreeNode.Index Properti

Definisi

Ruang nama:

System.Windows.Forms

Rakitan:

System.Windows.Forms.dll

Mendapatkan posisi simpul pohon dalam koleksi simpul pohon.

public:
 property int Index { int get(); };

public int Index { get; }

member this.Index : int

Public ReadOnly Property Index As Integer

Nilai Properti

Int32

Nilai indeks berbasis nol yang mewakili posisi simpul pohon dalam Nodes koleksi.

Contoh

Contoh kode berikut menampilkan Text nilai properti dan Index dari yang TreeNode diwakili oleh Parent properti dari TreeView.SelectedNode. Contoh ini mengharuskan Anda memiliki Form dengan TreeView kontrol di atasnya. TreeView harus memiliki setidaknya dua simpul akar, masing-masing memiliki setidaknya satu simpul anak.

private:
   void treeView1_AfterSelect( Object^ /*sender*/, TreeViewEventArgs^ e )
   {
      /* Display the Text and Index of the
            * selected tree node's Parent. */
      if ( e->Node->Parent != nullptr && e->Node->Parent->GetType() == TreeNode::typeid )
      {
         statusBar1->Text = String::Format( "Parent: {0}\n Index Position: {1}", e->Node->Parent->Text, e->Node->Parent->Index );
      }
      else
      {
         statusBar1->Text = "No parent node.";
      }
   }

private void treeView1_AfterSelect(object sender, TreeViewEventArgs e)
{  
   /* Display the Text and Index of the 
    * selected tree node's Parent. */
   if(e.Node.Parent!= null && 
     e.Node.Parent.GetType() == typeof(TreeNode) )
   {
      statusBar1.Text = "Parent: " + e.Node.Parent.Text + "\n"
         + "Index Position: " + e.Node.Parent.Index.ToString();
   }
   else
   {
      statusBar1.Text = "No parent node.";
   }
}

Private Sub treeView1_AfterSelect(sender As Object, _
  e As TreeViewEventArgs) Handles treeView1.AfterSelect
   ' Display the Text and Index of the 
   ' selected tree node's Parent. 
   If (e.Node.Parent IsNot Nothing) 
      If (e.Node.Parent.GetType() Is GetType(TreeNode)) Then
         statusBar1.Text = "Parent: " + e.Node.Parent.Text + _
           ControlChars.Cr + "Index Position: " + e.Node.Parent.Index.ToString()
      End If
   Else
      statusBar1.Text = "No parent node."
   End If
End Sub