XmlSerializer.CanDeserialize(XmlReader) Method

Reference

Definition

Namespace:: System.Xml.Serialization

Assembly:: System.Xml.XmlSerializer.dll

Assembly:: System.Xml.dll

Assembly:: netstandard.dll

Source:: XmlSerializer.cs

Source:: XmlSerializer.cs

Source:: XmlSerializer.cs

Important

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Gets a value that indicates whether this XmlSerializer can deserialize a specified XML document.

public:
 virtual bool CanDeserialize(System::Xml::XmlReader ^ xmlReader);

public virtual bool CanDeserialize (System.Xml.XmlReader xmlReader);

abstract member CanDeserialize : System.Xml.XmlReader -> bool
override this.CanDeserialize : System.Xml.XmlReader -> bool

Public Overridable Function CanDeserialize (xmlReader As XmlReader) As Boolean

Parameters

xmlReader: XmlReader

An XmlReader that points to the document to deserialize.

Returns

Boolean

true if this XmlSerializer can deserialize the object that the XmlReader points to; otherwise, false.

Examples

The following example calls the CanDeserialize method to check whether an XML document can be deserialized.

private:
   void TestDocument( String^ filename, Type^ objType )
   {
      // Using a FileStream, create an XmlTextReader.
      Stream^ fs = gcnew FileStream( filename,FileMode::Open );
      XmlReader^ reader = gcnew XmlTextReader( fs );
      XmlSerializer^ serializer = gcnew XmlSerializer( objType );
      if ( serializer->CanDeserialize( reader ) )
      {
         Object^ o = serializer->Deserialize( reader );
      }
      fs->Close();
   }

private void TestDocument(string filename, Type objType)
{
    // Using a FileStream, create an XmlTextReader.
    Stream fs = new FileStream(filename, FileMode.Open);
    XmlReader reader = new XmlTextReader(fs);
    XmlSerializer serializer = new XmlSerializer(objType);
    if (serializer.CanDeserialize(reader))
    {
        Object o = serializer.Deserialize(reader);
    }
    fs.Close();
}

Private Sub TestDocument _
                (ByVal filename As String, _
                 ByVal objType As Type)
    ' Using a FileStream, create an XmlTextReader.
    Dim fs As New FileStream(filename, FileMode.Open)
    Dim reader As New XmlTextReader(fs)
    Dim serializer As New XmlSerializer(objType)
    If serializer.CanDeserialize(reader) Then
        Dim o As Object = serializer.Deserialize(reader)
    End If
    fs.Close()
End Sub

Applies to

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