XObject.NodeType Property

Reference

Definition

Namespace:: System.Xml.Linq

Assembly:: System.Xml.XDocument.dll

Assembly:: System.Xml.Linq.dll

Assembly:: netstandard.dll

Source:: XObject.cs

Source:: XObject.cs

Source:: XObject.cs

Important

Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.

Gets the node type for this XObject.

public:
 abstract property System::Xml::XmlNodeType NodeType { System::Xml::XmlNodeType get(); };

public abstract System.Xml.XmlNodeType NodeType { get; }

member this.NodeType : System.Xml.XmlNodeType

Public MustOverride ReadOnly Property NodeType As XmlNodeType

Property Value

XmlNodeType

The node type for this XObject.

Examples

The following example uses this method to retrieve the node type for a variety of nodes.

// Note that XNode uses XmlNodeType, which is in the System.Xml namespace.  
XDocument xmlTree = new XDocument(  
    new XComment("a comment"),  
    new XProcessingInstruction("xml-stylesheet", "type=\"text/xsl\" href=\"hello.xsl\""),  
    new XElement("Root",  
        new XAttribute("Att", "attContent"),  
        new XElement("Child1",  
            new XCData("CDATA content")  
        ),  
        new XElement("Child2",  
            new XText("Text content")  
        )  
    )  
);  

foreach (XNode node in xmlTree.DescendantNodes())  
{  
    Console.WriteLine(node.NodeType);  
    if (node.NodeType == XmlNodeType.Element)  
    {  
        foreach (XAttribute att in ((XElement)node).Attributes())  
            Console.WriteLine(att.NodeType);  
    }  
}

' Note that XNode uses XmlNodeType, which is in the System.Xml  namespace.  
Dim xmlTree As XDocument = _   
    <?xml version="1.0"?>  
    <!--a comment-->  
    <?xml-stylesheet type="text/xsl" href="hello.xsl"?>  
    <Root Att="attContent">  
        <Child1><![CDATA[CDATA content]]></Child1>  
        <Child2>Text content</Child2>  
     </Root>  

For Each node As XNode In xmlTree.DescendantNodes  
    Console.WriteLine(node.NodeType.ToString())  
    If node.NodeType = XmlNodeType.Element Then  
        For Each att In DirectCast(node, XElement).Attributes  
            Console.WriteLine(att.NodeType.ToString())  
        Next  
    End If  
Next

This example produces the following output:

Comment  
ProcessingInstruction  
Element  
Attribute  
Element  
CDATA  
Element  
Text

Remarks

Because all classes that derive from XObject contain a NodeType property, you can write code that operates on collections of concrete subclass of XObject. Your code can then test for the node type of each node in the collection.

Applies to

Deila með