CodeClass.FullName Property

Definition

Namespace:

EnvDTE

Assembly:

Microsoft.VisualStudio.Interop.dll

Package:

Microsoft.VisualStudio.Interop v17.11.40262

Gets the full path and name of the CodeClass object's source file.

public:
 property System::String ^ FullName { System::String ^ get(); };

public:
 property Platform::String ^ FullName { Platform::String ^ get(); };

[System.Runtime.InteropServices.DispId(3)]
public string FullName { [System.Runtime.InteropServices.DispId(3)] get; }

[<System.Runtime.InteropServices.DispId(3)>]
[<get: System.Runtime.InteropServices.DispId(3)>]
member this.FullName : string

Public ReadOnly Property FullName As String

Property Value

String

A string representing the full path and name of the CodeClass object's source file.

Attributes

DispIdAttribute

Examples

Public Sub CodeClassExample(ByVal dte As DTE2)   
    ' Before running this example, open a code document from a  
    ' project and place the insertion point inside a class definition.  
    Try  
        Dim objTextSel As TextSelection  
        Dim objCodeCls As CodeClass  
        Dim objCodeElem As CodeElement  
        objTextSel = CType(dte.ActiveDocument.Selection, TextSelection)  
        objCodeCls = CType(objTextSel.ActivePoint.CodeElement(vsCMElement.vsCMElementClass), CodeClass)  
        ' Display the fullname of CodeClass object.  
        MessageBox.Show(objCodeCls.FullName)  
        ' Prove that the parent object of a CodeClass is a CodeElement.  
        objCodeElem = CType(objCodeCls.Parent, CodeElement)  
        ' Get access privilege for CodeClass.  
        MessageBox.Show(objCodeCls.Access.ToString())  
        ' Change access privilege for CodeClass objCodeCls.  
        ' Note the change in access keyword in your code document.  
        objCodeCls.Access = vsCMAccess.vsCMAccessPublic  
    Catch ex As Exception  
        MessageBox.Show(ex.Message)  
    End Try  
End Sub  

public void CodeClassExample(DTE2 dte)  
{   
   // Before running this example, open a code document from a  
   // project and place the insertion point inside a class definition.  
   try  
   {  
      TextSelection objTextSel;  
      CodeClass objCodeCls;  
      CodeElement objCodeElem;  
      objTextSel = (TextSelection)dte.ActiveDocument.Selection;  
      objCodeCls = (CodeClass)objTextSel.ActivePoint.get_CodeElement(vsCMElement.vsCMElementClass);  
      // Display the fullname of CodeClass object.  
      MessageBox.Show(objCodeCls.FullName);  
      // Prove that the parent object of a CodeClass is a CodeElement.  
      objCodeElem = (CodeElement)objCodeCls.Parent;  
      // Get access privilege for CodeClass.  
      MessageBox.Show(objCodeCls.Access.ToString());  
      // Change access privilege for CodeClass objCodeCls.  
      // Note the change in access keyword in your code document.  
      objCodeCls.Access = vsCMAccess.vsCMAccessPublic;  
   }  
   catch (Exception ex)  
   {   
      MessageBox.Show(ex.Message);  
   }  

Remarks

The FullName property is known as the FileName property in some versions of Visual Studio.

Note

The values of code model elements such as classes, structs, functions, attributes, delegates, and so forth can be non-deterministic after making certain kinds of edits, meaning that their values cannot be relied upon to always remain the same. For more information, see the section Code Model Element Values Can Change in Discovering Code by Using the Code Model (Visual Basic).