XmlArrayItemAttribute コンストラクター

定義

名前空間:: System.Xml.Serialization

アセンブリ:: System.Xml.dll, System.Xml.XmlSerializer.dll

アセンブリ:: netstandard.dll, System.Xml.XmlSerializer.dll

アセンブリ:: System.Xml.XmlSerializer.dll

アセンブリ:: System.Xml.dll

アセンブリ:: netstandard.dll

重要

一部の情報は、リリース前に大きく変更される可能性があるプレリリースされた製品に関するものです。 Microsoft は、ここに記載されている情報について、明示または黙示を問わず、一切保証しません。

XmlArrayItemAttribute クラスの新しいインスタンスを初期化します。

オーバーロード

名前	説明
XmlArrayItemAttribute()	XmlArrayItemAttribute クラスの新しいインスタンスを初期化します。
XmlArrayItemAttribute(String)	XmlArrayItemAttribute クラスの新しいインスタンスを初期化し、XML ドキュメントで生成される XML 要素の名前を指定します。
XmlArrayItemAttribute(Type)	XmlArrayItemAttribute クラスの新しいインスタンスを初期化し、シリアル化された配列に挿入できるTypeを指定します。
XmlArrayItemAttribute(String, Type)	XmlArrayItemAttribute クラスの新しいインスタンスを初期化し、XML ドキュメントで生成された XML 要素の名前と、生成された XML ドキュメントに挿入できるTypeを指定します。

XmlArrayItemAttribute()

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

XmlArrayItemAttribute クラスの新しいインスタンスを初期化します。

public:
 XmlArrayItemAttribute();

public XmlArrayItemAttribute();

Public Sub New ()

例

using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

public class Vehicle
{
   public string id;
}
public class Car:Vehicle
{
   public string Maker;
}

public class Transportation
{
   [XmlArrayItem(),
   XmlArrayItem(typeof(Car), ElementName = "Automobile")]
   public Vehicle[] MyVehicles;
}

public class Run
{
   public static void Main()
   {
      Run test = new Run();
      test.SerializeObject("XmlArrayItem1.xml");
      test.DeserializeObject("XmlArrayItem1.xml");
   }

   private void SerializeObject(string filename){
      // Creates an XmlSerializer for the Transportation class.
      XmlSerializer MySerializer = new XmlSerializer(typeof(Transportation));

      // Writing the XML file to disk requires a TextWriter.
      TextWriter myTextWriter = new StreamWriter(filename);

      // Creates the object to serialize.
      Transportation myTransportation = new Transportation();

      // Creates objects to add to the array.
      Vehicle myVehicle= new Vehicle() ;
      myVehicle.id = "A12345";

      Car myCar = new Car();
      myCar.id = "Car 34";
      myCar.Maker = "FamousCarMaker";

      myTransportation.MyVehicles =
      new Vehicle[2] {myVehicle, myCar};

      // Serializes the object, and closes the StreamWriter.
      MySerializer.Serialize(myTextWriter, myTransportation);
      myTextWriter.Close();
   }

   private void DeserializeObject(string filename)
   {
      // Creates an XmlSerializer instance.
      XmlSerializer mySerializer = new XmlSerializer(typeof(Transportation));
      FileStream myFileStream = new FileStream(filename,FileMode.Open);
      Transportation myTransportation =
      (Transportation) mySerializer.Deserialize(myFileStream);

      for(int i = 0; i < myTransportation.MyVehicles.Length;i++)
      {
         Console.WriteLine(myTransportation.MyVehicles[i].id);
      }
   }
 }

Option Explicit
Option Strict

Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization


Public Class Vehicle
    Public id As String
End Class

Public Class Car
    Inherits Vehicle
    Public Maker As String
End Class

Public Class Transportation
    <XmlArrayItem(), _
     XmlArrayItem(GetType(Car), ElementName := "Automobile")> _
    Public MyVehicles() As Vehicle
End Class


Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.SerializeObject("XmlArrayItem1.xml")
        test.DeserializeObject("XmlArrayItem1.xml")
    End Sub
    
    
    Private Sub SerializeObject(ByVal filename As String)
        ' Creates an XmlSerializer for the Transportation class. 
        Dim MySerializer As New XmlSerializer(GetType(Transportation))
        
        ' Writing the XML file to disk requires a TextWriter.
        Dim myTextWriter As New StreamWriter(filename)
        
        ' Creates the object to serialize.
        Dim myTransportation As New Transportation()
        
        ' Creates objects to add to the array.
        Dim myVehicle As New Vehicle()
        myVehicle.id = "A12345"
        
        Dim myCar As New Car()
        myCar.id = "Car 34"
        myCar.Maker = "FamousCarMaker"
        
        myTransportation.MyVehicles = New Vehicle() {myVehicle, myCar}
        
        ' Serializes the object, and closes the StreamWriter.
        MySerializer.Serialize(myTextWriter, myTransportation)
        myTextWriter.Close()
    End Sub
    
    
    Private Sub DeserializeObject(ByVal filename As String)
        ' Create an XmlSerializer instance.
        Dim mySerializer As New XmlSerializer(GetType(Transportation))
        Dim myFileStream As New FileStream(filename, FileMode.Open)
        Dim myTransportation As Transportation = _
            CType(mySerializer.Deserialize(myFileStream), Transportation)
        
        Dim i As Integer
        For i = 0 To myTransportation.MyVehicles.Length - 1
            Console.WriteLine(myTransportation.MyVehicles(i).id)
        Next i
    End Sub
End Class

適用対象

XmlArrayItemAttribute(String)

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

XmlArrayItemAttribute クラスの新しいインスタンスを初期化し、XML ドキュメントで生成される XML 要素の名前を指定します。

public:
 XmlArrayItemAttribute(System::String ^ elementName);

public XmlArrayItemAttribute(string elementName);

public XmlArrayItemAttribute(string? elementName);

new System.Xml.Serialization.XmlArrayItemAttribute : string -> System.Xml.Serialization.XmlArrayItemAttribute

Public Sub New (elementName As String)

パラメーター

elementName: String

XML 要素の名前。

例

次の例では、オブジェクトの配列を返す MyVehicles という名前のフィールドを含む Transportation という名前のクラスVehicleシリアル化します。この例では、XmlArrayItemAttributeをフィールドに適用し、XmlSerializerがVehicle クラスから派生したCar クラスのインスタンスを配列に挿入できるようにします。この例では、属性の適用中に、elementName パラメーターを使用して ElementName プロパティを設定します。

using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

public class Vehicle
{
   public string id;
}
public class Car:Vehicle
{
   public string Maker;
}

public class Transportation
{
   [XmlArrayItem(ElementName = "Transportation"),
   XmlArrayItem(typeof(Car), ElementName = "Automobile")]
   public Vehicle[] MyVehicles;
}

public class Run
{
   public static void Main()
   {
      Run test= new Run();
      test.SerializeObject("XmlArrayItem2.xml");
      test.DeserializeObject("XmlArrayItem2.xml");
   }

   private void SerializeObject(string filename)
   {
      // Creates an XmlSerializer for the Transportation class.
      XmlSerializer MySerializer =
      new XmlSerializer(typeof(Transportation));

      // Writing the XML file to disk requires a TextWriter.
      TextWriter myTextWriter = new StreamWriter(filename);

      Transportation myTransportation = new Transportation();

      Vehicle myVehicle= new Vehicle() ;
      myVehicle.id = "A12345";

      Car myCar = new Car();
      myCar.id = "Car 34";
      myCar.Maker = "FamousCarMaker";

      Vehicle [] myVehicles = {myVehicle, myCar};
      myTransportation.MyVehicles = myVehicles;

      // Serializes the object, and closes the StreamWriter.
      MySerializer.Serialize(myTextWriter, myTransportation);
      myTextWriter.Close();
   }

   private void DeserializeObject(string filename)
   {
      // Creates the serializer with the type to deserialize.
      XmlSerializer mySerializer =
      new XmlSerializer(typeof(Transportation));
      FileStream myFileStream = new FileStream(filename,FileMode.Open);
      Transportation myTransportation =
      (Transportation) mySerializer.Deserialize(myFileStream);

      for(int i = 0;i < myTransportation.MyVehicles.Length;i++)
      {
         Console.WriteLine(myTransportation.MyVehicles[i].id);
      }
   }
}

Option Explicit
Option Strict

Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization


Public Class Vehicle
    Public id As String
End Class

Public Class Car
    Inherits Vehicle
    Public Maker As String
End Class

Public Class Transportation
    <XmlArrayItem(ElementName := "Transportation"), _
     XmlArrayItem(GetType(Car), ElementName := "Automobile")> _
    Public MyVehicles() As Vehicle
End Class

Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.SerializeObject("XmlArrayItem2.xml")
        test.DeserializeObject("XmlArrayItem2.xml")
    End Sub    
    
    Private Sub SerializeObject(ByVal filename As String)
        ' Creates an XmlSerializer for the Transportation class.
        Dim MySerializer As New XmlSerializer(GetType(Transportation))
        
        ' Writing the XML file to disk requires a TextWriter.
        Dim myTextWriter As New StreamWriter(filename)
        
        Dim myTransportation As New Transportation()
        
        Dim myVehicle As New Vehicle()
        myVehicle.id = "A12345"
        
        Dim myCar As New Car()
        myCar.id = "Car 34"
        myCar.Maker = "FamousCarMaker"
        
        Dim myVehicles() As Vehicle = {myVehicle, myCar}
        myTransportation.MyVehicles = myVehicles
        
        ' Serializes the object, and closes the StreamWriter.
        MySerializer.Serialize(myTextWriter, myTransportation)
        myTextWriter.Close()
    End Sub
        
    Private Sub DeserializeObject(ByVal filename As String)
        ' Create the serializer with the type to deserialize.
        Dim mySerializer As New XmlSerializer(GetType(Transportation))
        Dim myFileStream As New FileStream(filename, FileMode.Open)
        Dim myTransportation As Transportation = _
            CType(mySerializer.Deserialize(myFileStream), Transportation)
        
        Dim i As Integer
        For i = 0 To myTransportation.MyVehicles.Length - 1
            Console.WriteLine(myTransportation.MyVehicles(i).id)
        Next i
    End Sub
End Class

注釈

このオーバーロードは、 ElementName プロパティを設定します。

生成された XML 要素の名前がメンバーの識別子と異なる場合は、このオーバーロードを使用します。

名前空間を含む XML ドキュメントには、複数のバージョンの要素名を含めることができます。詳細については、 ElementName プロパティを参照してください。

適用対象

XmlArrayItemAttribute(Type)

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

XmlArrayItemAttribute クラスの新しいインスタンスを初期化し、シリアル化された配列に挿入できるTypeを指定します。

public:
 XmlArrayItemAttribute(Type ^ type);

public XmlArrayItemAttribute(Type type);

public XmlArrayItemAttribute(Type? type);

new System.Xml.Serialization.XmlArrayItemAttribute : Type -> System.Xml.Serialization.XmlArrayItemAttribute

Public Sub New (type As Type)

パラメーター

type: Type

シリアル化するオブジェクトの Type 。

例

次の例では、オブジェクトの配列を返す MyVehicles という名前のフィールドを含む Transportation という名前のクラスVehicleシリアル化します。この例では、XmlArrayItemAttributeをフィールドに適用し、XmlSerializerがVehicle クラスから派生したCar クラスのインスタンスを配列に挿入できるようにします。この例では、属性の適用中に、type パラメーターを使用して Type プロパティを設定します。

using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

public class Vehicle
{
   public string id;
}
public class Car:Vehicle
{
   public string Maker;
}

public class Transportation
{
   [XmlArrayItem(typeof(Vehicle)),
   XmlArrayItem(typeof(Car))]
   public Vehicle[] MyVehicles;
}

public class Run
{
   public static void Main()
   {
      Run test= new Run();
      test.SerializeObject("XmlArrayItem3.xml");
      test.DeserializeObject("XmlArrayItem3.xml");
   }

   private void SerializeObject(string filename)
   {
       // Creates an XmlSerializer.
      XmlSerializer MySerializer =
      new XmlSerializer(typeof(Transportation));

      // Writing the XML file to disk requires a TextWriter.
      TextWriter myTextWriter = new StreamWriter(filename);

      Transportation myTransportation = new Transportation();

      Vehicle myVehicle= new Vehicle() ;
      myVehicle.id = "A12345";

      Car myCar = new Car();
      myCar.id = "Car 34";
      myCar.Maker = "FamousCarMaker";

      Vehicle [] myVehicles = {myVehicle, myCar};
      myTransportation.MyVehicles = myVehicles;

      // Serializes the object, and closes the StreamWriter.
      MySerializer.Serialize(myTextWriter, myTransportation);
      myTextWriter.Close();
   }

   private void DeserializeObject(string filename)
   {
      // Creates the serializer with the type to deserialize.
      XmlSerializer mySerializer =
      new XmlSerializer(typeof(Transportation));
      FileStream myFileStream = new FileStream(filename,FileMode.Open);
      Transportation myTransportation =
      (Transportation) mySerializer.Deserialize(myFileStream);

      for(int i = 0;i < myTransportation.MyVehicles.Length;i++)
      {
         Console.WriteLine(myTransportation.MyVehicles[i].id);
      }
   }
}

Option Explicit
Option Strict

Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization


Public Class Vehicle
    Public id As String
End Class

Public Class Car
    Inherits Vehicle
    Public Maker As String
End Class

Public Class Transportation
    <XmlArrayItem(GetType(Vehicle)), _
     XmlArrayItem(GetType(Car))> _
    Public MyVehicles() As Vehicle
End Class


Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.SerializeObject("XmlArrayItem3.xml")
        test.DeserializeObject("XmlArrayItem3.xml")
    End Sub    
    
    Private Sub SerializeObject(ByVal filename As String)
        ' Creates an XmlSerializer object. 
        Dim MySerializer As New XmlSerializer(GetType(Transportation))
        
        ' Writing the XML file to disk requires a TextWriter.
        Dim myTextWriter As New StreamWriter(filename)
        
        Dim myTransportation As New Transportation()
        
        Dim myVehicle As New Vehicle()
        myVehicle.id = "A12345"
        
        Dim myCar As New Car()
        myCar.id = "Car 34"
        myCar.Maker = "FamousCarMaker"
        
        Dim myVehicles() As Vehicle =  {myVehicle, myCar}
        myTransportation.MyVehicles = myVehicles
        
        ' Serializes the object, and closes the StreamWriter.
        MySerializer.Serialize(myTextWriter, myTransportation)
        myTextWriter.Close()
    End Sub    
    
    Private Sub DeserializeObject(ByVal filename As String)
        ' Creates the serializer with the type to deserialize.
        Dim mySerializer As New XmlSerializer(GetType(Transportation))
        Dim myFileStream As New FileStream(filename, FileMode.Open)
        Dim myTransportation As Transportation = _
            CType(mySerializer.Deserialize(myFileStream), Transportation)
        
        Dim i As Integer
        For i = 0 To myTransportation.MyVehicles.Length - 1
            Console.WriteLine(myTransportation.MyVehicles(i).id)
        Next i
    End Sub
End Class

適用対象

XmlArrayItemAttribute(String, Type)

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

ソース:: XmlArrayItemAttribute.cs

XmlArrayItemAttribute クラスの新しいインスタンスを初期化し、XML ドキュメントで生成された XML 要素の名前と、生成された XML ドキュメントに挿入できるTypeを指定します。

public:
 XmlArrayItemAttribute(System::String ^ elementName, Type ^ type);

public XmlArrayItemAttribute(string elementName, Type type);

public XmlArrayItemAttribute(string? elementName, Type? type);

new System.Xml.Serialization.XmlArrayItemAttribute : string * Type -> System.Xml.Serialization.XmlArrayItemAttribute

Public Sub New (elementName As String, type As Type)

パラメーター

elementName: String

XML 要素の名前。

type: Type

シリアル化するオブジェクトの Type 。

例

using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

public class Vehicle
{
   public string id;
}
public class Car:Vehicle
{
   public string Maker;
}

public class Transportation
{
   [XmlArray]
   [XmlArrayItem("Transport", typeof(Vehicle)),
   XmlArrayItem("Automobile", typeof(Car))]
   public Vehicle[] MyVehicles;
}

public class Run
{
   public static void Main()
   {
      Run test= new Run();
      test.SerializeObject("XmlArrayItem4.xml");
      test.DeserializeObject("XmlArrayItem4.xml");
   }

   private void SerializeObject(string filename)
   {
       // Creates an XmlSerializer for the Transportation class.
      XmlSerializer MySerializer =
      new XmlSerializer(typeof(Transportation));

      // Writing the XML file to disk requires a TextWriter.
      TextWriter myTextWriter = new StreamWriter(filename);

      Transportation myTransportation = new Transportation();

      Vehicle myVehicle= new Vehicle() ;
      myVehicle.id = "A12345";

      Car myCar = new Car();
      myCar.id = "Car 34";
      myCar.Maker = "FamousCarMaker";

      Vehicle [] myVehicles = {myVehicle, myCar};
      myTransportation.MyVehicles = myVehicles;

      // Serializes the object, and closes the StreamWriter.
      MySerializer.Serialize(myTextWriter, myTransportation);
      myTextWriter.Close();
   }

   private void DeserializeObject(string filename)
   {
      // Creates an XmlSerializer.
      XmlSerializer mySerializer =
      new XmlSerializer(typeof(Transportation));
      FileStream myFileStream = new FileStream(filename,FileMode.Open);
      Transportation myTransportation =
      (Transportation) mySerializer.Deserialize(myFileStream);

      for(int i = 0;i < myTransportation.MyVehicles.Length;i++)
      {
         Console.WriteLine(myTransportation.MyVehicles[i].id);
      }
   }
}

Option Explicit
Option Strict

Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization


Public Class Vehicle
    Public id As String
End Class

Public Class Car
    Inherits Vehicle
    Public Maker As String
End Class

Public Class Transportation
    <XmlArray(), _
     XmlArrayItem("Transport", GetType(Vehicle)), _
     XmlArrayItem("Automobile", GetType(Car))> _
    Public MyVehicles() As Vehicle
End Class


Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.SerializeObject("XmlArrayItem4.xml")
        test.DeserializeObject("XmlArrayItem4.xml")
    End Sub    
    
    Private Sub SerializeObject(ByVal filename As String)
        ' Creates an XmlSerializer for the Transportation class.
        Dim MySerializer As New XmlSerializer(GetType(Transportation))
        
        ' Writing the XML file to disk requires a TextWriter.
        Dim myTextWriter As New StreamWriter(filename)
        
        Dim myTransportation As New Transportation()
        
        Dim myVehicle As New Vehicle()
        myVehicle.id = "A12345"
        
        Dim myCar As New Car()
        myCar.id = "Car 34"
        myCar.Maker = "FamousCarMaker"
        
        Dim myVehicles() As Vehicle =  {myVehicle, myCar}
        myTransportation.MyVehicles = myVehicles
        
        ' Serializes the object, and closes the StreamWriter.
        MySerializer.Serialize(myTextWriter, myTransportation)
        myTextWriter.Close()
    End Sub    
    
    Private Sub DeserializeObject(ByVal filename As String)
        ' Creates an XmlSerializer.
        Dim mySerializer As New XmlSerializer(GetType(Transportation))
        Dim myFileStream As New FileStream(filename, FileMode.Open)
        Dim myTransportation As Transportation = _
            CType(mySerializer.Deserialize(myFileStream), Transportation)
        
        Dim i As Integer
        For i = 0 To myTransportation.MyVehicles.Length - 1
            Console.WriteLine(myTransportation.MyVehicles(i).id)
        Next i
    End Sub
End Class

注釈

このオーバーロードは、 ElementName と Type のプロパティを設定します。

生成された XML 要素の名前がメンバーの識別子と異なる場合は、このオーバーロードを使用します。

適用対象

フィードバック

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次の方法で共有

XmlArrayItemAttribute コンストラクター

定義

オーバーロード

XmlArrayItemAttribute()

例

適用対象

XmlArrayItemAttribute(String)

パラメーター

例

注釈

適用対象

XmlArrayItemAttribute(Type)

パラメーター

例

適用対象

XmlArrayItemAttribute(String, Type)

パラメーター

例

注釈

適用対象

フィードバック