TableLayoutPanel.GetColumn(Control) Method
Important
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Returns the column position of the specified child control.
public:
int GetColumn(System::Windows::Forms::Control ^ control);
public int GetColumn (System.Windows.Forms.Control control);
member this.GetColumn : System.Windows.Forms.Control -> int
Public Function GetColumn (control As Control) As Integer
- control
- Control
A child control of the TableLayoutPanel.
The column position of the specified child control, or -1 if the position of control
is determined by LayoutEngine.
control
is null
.
control
is not a type that can be arranged by this LayoutEngine.
The following code example enumerates all the child controls in the TableLayoutPanel and finds the column index for each control using the GetColumn method.
private void getColumnBtn_Click(
System.Object sender,
System.EventArgs e)
{
foreach ( Control c in this.TableLayoutPanel1.Controls )
{
Trace.WriteLine(this.TableLayoutPanel1.GetColumn(c));
}
}
Private Sub getColumnBtn_Click( _
ByVal sender As System.Object, _
ByVal e As System.EventArgs) _
Handles getColumnBtn.Click
Dim c As Control
For Each c In Me.TableLayoutPanel1.Controls
Trace.WriteLine(Me.TableLayoutPanel1.GetColumn(c))
Next
End Sub
If control
spans two or more columns, the GetColumn method will return the lowest column index.
The column position value is zero based, so you can use it as an index for the array returned by GetColumnWidths.
This method is called by the Column
property, which the panel adds to its child controls at design time.
To get the actual position of control
, even when its position is determined by LayoutEngine, call the GetPositionFromControl method.
Өнім | Нұсқалар |
---|---|
.NET Framework | 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1 |
Windows Desktop | 3.0, 3.1, 5, 6, 7, 8, 9 |
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