XmlArrayItemAttribute Constructors

Definitie

Initialiseert een nieuw exemplaar van de XmlArrayItemAttribute klasse.

Overloads

Name Description
XmlArrayItemAttribute()

Initialiseert een nieuw exemplaar van de XmlArrayItemAttribute klasse.

XmlArrayItemAttribute(String)

Initialiseert een nieuw exemplaar van de XmlArrayItemAttribute klasse en geeft de naam op van het XML-element dat is gegenereerd in het XML-document.

XmlArrayItemAttribute(Type)

Initialiseert een nieuw exemplaar van de XmlArrayItemAttribute klasse en geeft aan welke Type kan worden ingevoegd in de geserialiseerde matrix.

XmlArrayItemAttribute(String, Type)

Initialiseert een nieuw exemplaar van de XmlArrayItemAttribute klasse en geeft de naam op van het XML-element dat is gegenereerd in het XML-document en de Type naam die kan worden ingevoegd in het gegenereerde XML-document.

XmlArrayItemAttribute()

Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs

Initialiseert een nieuw exemplaar van de XmlArrayItemAttribute klasse.

public:
 XmlArrayItemAttribute();
public XmlArrayItemAttribute();
Public Sub New ()

Voorbeelden

In het volgende voorbeeld wordt een klasse geserialiseerd Transportation die een veld bevat dat MyVehicles een matrix met Vehicle objecten retourneert. In het voorbeeld wordt het XmlArrayItemAttribute veld toegepast, zodat exemplaren XmlSerializer van de Car klasse, die zijn afgeleid van de Vehicle klasse, in de matrix kunnen worden ingevoegd.

using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

public class Vehicle
{
   public string id;
}
public class Car:Vehicle
{
   public string Maker;
}

public class Transportation
{
   [XmlArrayItem(),
   XmlArrayItem(typeof(Car), ElementName = "Automobile")]
   public Vehicle[] MyVehicles;
}

public class Run
{
   public static void Main()
   {
      Run test = new Run();
      test.SerializeObject("XmlArrayItem1.xml");
      test.DeserializeObject("XmlArrayItem1.xml");
   }

   private void SerializeObject(string filename){
      // Creates an XmlSerializer for the Transportation class.
      XmlSerializer MySerializer = new XmlSerializer(typeof(Transportation));

      // Writing the XML file to disk requires a TextWriter.
      TextWriter myTextWriter = new StreamWriter(filename);

      // Creates the object to serialize.
      Transportation myTransportation = new Transportation();

      // Creates objects to add to the array.
      Vehicle myVehicle= new Vehicle() ;
      myVehicle.id = "A12345";

      Car myCar = new Car();
      myCar.id = "Car 34";
      myCar.Maker = "FamousCarMaker";

      myTransportation.MyVehicles =
      new Vehicle[2] {myVehicle, myCar};

      // Serializes the object, and closes the StreamWriter.
      MySerializer.Serialize(myTextWriter, myTransportation);
      myTextWriter.Close();
   }

   private void DeserializeObject(string filename)
   {
      // Creates an XmlSerializer instance.
      XmlSerializer mySerializer = new XmlSerializer(typeof(Transportation));
      FileStream myFileStream = new FileStream(filename,FileMode.Open);
      Transportation myTransportation =
      (Transportation) mySerializer.Deserialize(myFileStream);

      for(int i = 0; i < myTransportation.MyVehicles.Length;i++)
      {
         Console.WriteLine(myTransportation.MyVehicles[i].id);
      }
   }
 }
Option Explicit
Option Strict

Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization


Public Class Vehicle
    Public id As String
End Class

Public Class Car
    Inherits Vehicle
    Public Maker As String
End Class

Public Class Transportation
    <XmlArrayItem(), _
     XmlArrayItem(GetType(Car), ElementName := "Automobile")> _
    Public MyVehicles() As Vehicle
End Class


Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.SerializeObject("XmlArrayItem1.xml")
        test.DeserializeObject("XmlArrayItem1.xml")
    End Sub
    
    
    Private Sub SerializeObject(ByVal filename As String)
        ' Creates an XmlSerializer for the Transportation class. 
        Dim MySerializer As New XmlSerializer(GetType(Transportation))
        
        ' Writing the XML file to disk requires a TextWriter.
        Dim myTextWriter As New StreamWriter(filename)
        
        ' Creates the object to serialize.
        Dim myTransportation As New Transportation()
        
        ' Creates objects to add to the array.
        Dim myVehicle As New Vehicle()
        myVehicle.id = "A12345"
        
        Dim myCar As New Car()
        myCar.id = "Car 34"
        myCar.Maker = "FamousCarMaker"
        
        myTransportation.MyVehicles = New Vehicle() {myVehicle, myCar}
        
        ' Serializes the object, and closes the StreamWriter.
        MySerializer.Serialize(myTextWriter, myTransportation)
        myTextWriter.Close()
    End Sub
    
    
    Private Sub DeserializeObject(ByVal filename As String)
        ' Create an XmlSerializer instance.
        Dim mySerializer As New XmlSerializer(GetType(Transportation))
        Dim myFileStream As New FileStream(filename, FileMode.Open)
        Dim myTransportation As Transportation = _
            CType(mySerializer.Deserialize(myFileStream), Transportation)
        
        Dim i As Integer
        For i = 0 To myTransportation.MyVehicles.Length - 1
            Console.WriteLine(myTransportation.MyVehicles(i).id)
        Next i
    End Sub
End Class

Van toepassing op

XmlArrayItemAttribute(String)

Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs

Initialiseert een nieuw exemplaar van de XmlArrayItemAttribute klasse en geeft de naam op van het XML-element dat is gegenereerd in het XML-document.

public:
 XmlArrayItemAttribute(System::String ^ elementName);
public XmlArrayItemAttribute(string elementName);
public XmlArrayItemAttribute(string? elementName);
new System.Xml.Serialization.XmlArrayItemAttribute : string -> System.Xml.Serialization.XmlArrayItemAttribute
Public Sub New (elementName As String)

Parameters

elementName
String

De naam van het XML-element.

Voorbeelden

In het volgende voorbeeld wordt een klasse geserialiseerd Transportation die een veld bevat dat MyVehicles een matrix met Vehicle objecten retourneert. In het voorbeeld wordt het XmlArrayItemAttribute veld toegepast, zodat exemplaren XmlSerializer van de Car klasse, die zijn afgeleid van de Vehicle klasse, in de matrix kunnen worden ingevoegd. Tijdens het toepassen van het kenmerk wordt in het voorbeeld de ElementName eigenschap ingesteld met behulp van de elementName parameter.

using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

public class Vehicle
{
   public string id;
}
public class Car:Vehicle
{
   public string Maker;
}

public class Transportation
{
   [XmlArrayItem(ElementName = "Transportation"),
   XmlArrayItem(typeof(Car), ElementName = "Automobile")]
   public Vehicle[] MyVehicles;
}

public class Run
{
   public static void Main()
   {
      Run test= new Run();
      test.SerializeObject("XmlArrayItem2.xml");
      test.DeserializeObject("XmlArrayItem2.xml");
   }

   private void SerializeObject(string filename)
   {
      // Creates an XmlSerializer for the Transportation class.
      XmlSerializer MySerializer =
      new XmlSerializer(typeof(Transportation));

      // Writing the XML file to disk requires a TextWriter.
      TextWriter myTextWriter = new StreamWriter(filename);

      Transportation myTransportation = new Transportation();

      Vehicle myVehicle= new Vehicle() ;
      myVehicle.id = "A12345";

      Car myCar = new Car();
      myCar.id = "Car 34";
      myCar.Maker = "FamousCarMaker";

      Vehicle [] myVehicles = {myVehicle, myCar};
      myTransportation.MyVehicles = myVehicles;

      // Serializes the object, and closes the StreamWriter.
      MySerializer.Serialize(myTextWriter, myTransportation);
      myTextWriter.Close();
   }

   private void DeserializeObject(string filename)
   {
      // Creates the serializer with the type to deserialize.
      XmlSerializer mySerializer =
      new XmlSerializer(typeof(Transportation));
      FileStream myFileStream = new FileStream(filename,FileMode.Open);
      Transportation myTransportation =
      (Transportation) mySerializer.Deserialize(myFileStream);

      for(int i = 0;i < myTransportation.MyVehicles.Length;i++)
      {
         Console.WriteLine(myTransportation.MyVehicles[i].id);
      }
   }
}
Option Explicit
Option Strict

Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization


Public Class Vehicle
    Public id As String
End Class

Public Class Car
    Inherits Vehicle
    Public Maker As String
End Class

Public Class Transportation
    <XmlArrayItem(ElementName := "Transportation"), _
     XmlArrayItem(GetType(Car), ElementName := "Automobile")> _
    Public MyVehicles() As Vehicle
End Class

Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.SerializeObject("XmlArrayItem2.xml")
        test.DeserializeObject("XmlArrayItem2.xml")
    End Sub    
    
    Private Sub SerializeObject(ByVal filename As String)
        ' Creates an XmlSerializer for the Transportation class.
        Dim MySerializer As New XmlSerializer(GetType(Transportation))
        
        ' Writing the XML file to disk requires a TextWriter.
        Dim myTextWriter As New StreamWriter(filename)
        
        Dim myTransportation As New Transportation()
        
        Dim myVehicle As New Vehicle()
        myVehicle.id = "A12345"
        
        Dim myCar As New Car()
        myCar.id = "Car 34"
        myCar.Maker = "FamousCarMaker"
        
        Dim myVehicles() As Vehicle = {myVehicle, myCar}
        myTransportation.MyVehicles = myVehicles
        
        ' Serializes the object, and closes the StreamWriter.
        MySerializer.Serialize(myTextWriter, myTransportation)
        myTextWriter.Close()
    End Sub
        
    Private Sub DeserializeObject(ByVal filename As String)
        ' Create the serializer with the type to deserialize.
        Dim mySerializer As New XmlSerializer(GetType(Transportation))
        Dim myFileStream As New FileStream(filename, FileMode.Open)
        Dim myTransportation As Transportation = _
            CType(mySerializer.Deserialize(myFileStream), Transportation)
        
        Dim i As Integer
        For i = 0 To myTransportation.MyVehicles.Length - 1
            Console.WriteLine(myTransportation.MyVehicles(i).id)
        Next i
    End Sub
End Class

Opmerkingen

Met deze overbelasting wordt de ElementName eigenschap ingesteld.

Gebruik deze overbelasting als u wilt dat de naam van het gegenereerde XML-element verschilt van de id van het lid.

Een XML-document met naamruimten kan meer dan één versie van een elementnaam bevatten. Zie de ElementName eigenschap voor meer informatie.

Van toepassing op

XmlArrayItemAttribute(Type)

Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs

Initialiseert een nieuw exemplaar van de XmlArrayItemAttribute klasse en geeft aan welke Type kan worden ingevoegd in de geserialiseerde matrix.

public:
 XmlArrayItemAttribute(Type ^ type);
public XmlArrayItemAttribute(Type type);
public XmlArrayItemAttribute(Type? type);
new System.Xml.Serialization.XmlArrayItemAttribute : Type -> System.Xml.Serialization.XmlArrayItemAttribute
Public Sub New (type As Type)

Parameters

type
Type

Het Type object dat moet worden geserialiseerd.

Voorbeelden

In het volgende voorbeeld wordt een klasse geserialiseerd Transportation die een veld bevat dat MyVehicles een matrix met Vehicle objecten retourneert. In het voorbeeld wordt het XmlArrayItemAttribute veld toegepast, zodat exemplaren XmlSerializer van de Car klasse, die zijn afgeleid van de Vehicle klasse, in de matrix kunnen worden ingevoegd. Tijdens het toepassen van het kenmerk wordt in het voorbeeld de Type eigenschap ingesteld met behulp van de type parameter.

using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

public class Vehicle
{
   public string id;
}
public class Car:Vehicle
{
   public string Maker;
}

public class Transportation
{
   [XmlArrayItem(typeof(Vehicle)),
   XmlArrayItem(typeof(Car))]
   public Vehicle[] MyVehicles;
}

public class Run
{
   public static void Main()
   {
      Run test= new Run();
      test.SerializeObject("XmlArrayItem3.xml");
      test.DeserializeObject("XmlArrayItem3.xml");
   }

   private void SerializeObject(string filename)
   {
       // Creates an XmlSerializer.
      XmlSerializer MySerializer =
      new XmlSerializer(typeof(Transportation));

      // Writing the XML file to disk requires a TextWriter.
      TextWriter myTextWriter = new StreamWriter(filename);

      Transportation myTransportation = new Transportation();

      Vehicle myVehicle= new Vehicle() ;
      myVehicle.id = "A12345";

      Car myCar = new Car();
      myCar.id = "Car 34";
      myCar.Maker = "FamousCarMaker";

      Vehicle [] myVehicles = {myVehicle, myCar};
      myTransportation.MyVehicles = myVehicles;

      // Serializes the object, and closes the StreamWriter.
      MySerializer.Serialize(myTextWriter, myTransportation);
      myTextWriter.Close();
   }

   private void DeserializeObject(string filename)
   {
      // Creates the serializer with the type to deserialize.
      XmlSerializer mySerializer =
      new XmlSerializer(typeof(Transportation));
      FileStream myFileStream = new FileStream(filename,FileMode.Open);
      Transportation myTransportation =
      (Transportation) mySerializer.Deserialize(myFileStream);

      for(int i = 0;i < myTransportation.MyVehicles.Length;i++)
      {
         Console.WriteLine(myTransportation.MyVehicles[i].id);
      }
   }
}
Option Explicit
Option Strict

Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization


Public Class Vehicle
    Public id As String
End Class

Public Class Car
    Inherits Vehicle
    Public Maker As String
End Class

Public Class Transportation
    <XmlArrayItem(GetType(Vehicle)), _
     XmlArrayItem(GetType(Car))> _
    Public MyVehicles() As Vehicle
End Class


Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.SerializeObject("XmlArrayItem3.xml")
        test.DeserializeObject("XmlArrayItem3.xml")
    End Sub    
    
    Private Sub SerializeObject(ByVal filename As String)
        ' Creates an XmlSerializer object. 
        Dim MySerializer As New XmlSerializer(GetType(Transportation))
        
        ' Writing the XML file to disk requires a TextWriter.
        Dim myTextWriter As New StreamWriter(filename)
        
        Dim myTransportation As New Transportation()
        
        Dim myVehicle As New Vehicle()
        myVehicle.id = "A12345"
        
        Dim myCar As New Car()
        myCar.id = "Car 34"
        myCar.Maker = "FamousCarMaker"
        
        Dim myVehicles() As Vehicle =  {myVehicle, myCar}
        myTransportation.MyVehicles = myVehicles
        
        ' Serializes the object, and closes the StreamWriter.
        MySerializer.Serialize(myTextWriter, myTransportation)
        myTextWriter.Close()
    End Sub    
    
    Private Sub DeserializeObject(ByVal filename As String)
        ' Creates the serializer with the type to deserialize.
        Dim mySerializer As New XmlSerializer(GetType(Transportation))
        Dim myFileStream As New FileStream(filename, FileMode.Open)
        Dim myTransportation As Transportation = _
            CType(mySerializer.Deserialize(myFileStream), Transportation)
        
        Dim i As Integer
        For i = 0 To myTransportation.MyVehicles.Length - 1
            Console.WriteLine(myTransportation.MyVehicles(i).id)
        Next i
    End Sub
End Class

Van toepassing op

XmlArrayItemAttribute(String, Type)

Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs
Bron:
XmlArrayItemAttribute.cs

Initialiseert een nieuw exemplaar van de XmlArrayItemAttribute klasse en geeft de naam op van het XML-element dat is gegenereerd in het XML-document en de Type naam die kan worden ingevoegd in het gegenereerde XML-document.

public:
 XmlArrayItemAttribute(System::String ^ elementName, Type ^ type);
public XmlArrayItemAttribute(string elementName, Type type);
public XmlArrayItemAttribute(string? elementName, Type? type);
new System.Xml.Serialization.XmlArrayItemAttribute : string * Type -> System.Xml.Serialization.XmlArrayItemAttribute
Public Sub New (elementName As String, type As Type)

Parameters

elementName
String

De naam van het XML-element.

type
Type

Het Type object dat moet worden geserialiseerd.

Voorbeelden

In het volgende voorbeeld wordt een klasse geserialiseerd Transportation die een veld bevat dat MyVehicles een matrix met Vehicle objecten retourneert. In het voorbeeld wordt het XmlArrayItemAttribute veld toegepast, zodat exemplaren XmlSerializer van de Car klasse, die zijn afgeleid van de Vehicle klasse, in de matrix kunnen worden ingevoegd. Tijdens het toepassen van het kenmerk stelt het voorbeeld de ElementName eigenschap in met behulp van de elementName parameter en de Type eigenschap met behulp van de type parameter.

using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

public class Vehicle
{
   public string id;
}
public class Car:Vehicle
{
   public string Maker;
}

public class Transportation
{
   [XmlArray]
   [XmlArrayItem("Transport", typeof(Vehicle)),
   XmlArrayItem("Automobile", typeof(Car))]
   public Vehicle[] MyVehicles;
}

public class Run
{
   public static void Main()
   {
      Run test= new Run();
      test.SerializeObject("XmlArrayItem4.xml");
      test.DeserializeObject("XmlArrayItem4.xml");
   }

   private void SerializeObject(string filename)
   {
       // Creates an XmlSerializer for the Transportation class.
      XmlSerializer MySerializer =
      new XmlSerializer(typeof(Transportation));

      // Writing the XML file to disk requires a TextWriter.
      TextWriter myTextWriter = new StreamWriter(filename);

      Transportation myTransportation = new Transportation();

      Vehicle myVehicle= new Vehicle() ;
      myVehicle.id = "A12345";

      Car myCar = new Car();
      myCar.id = "Car 34";
      myCar.Maker = "FamousCarMaker";

      Vehicle [] myVehicles = {myVehicle, myCar};
      myTransportation.MyVehicles = myVehicles;

      // Serializes the object, and closes the StreamWriter.
      MySerializer.Serialize(myTextWriter, myTransportation);
      myTextWriter.Close();
   }

   private void DeserializeObject(string filename)
   {
      // Creates an XmlSerializer.
      XmlSerializer mySerializer =
      new XmlSerializer(typeof(Transportation));
      FileStream myFileStream = new FileStream(filename,FileMode.Open);
      Transportation myTransportation =
      (Transportation) mySerializer.Deserialize(myFileStream);

      for(int i = 0;i < myTransportation.MyVehicles.Length;i++)
      {
         Console.WriteLine(myTransportation.MyVehicles[i].id);
      }
   }
}
Option Explicit
Option Strict

Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization


Public Class Vehicle
    Public id As String
End Class

Public Class Car
    Inherits Vehicle
    Public Maker As String
End Class

Public Class Transportation
    <XmlArray(), _
     XmlArrayItem("Transport", GetType(Vehicle)), _
     XmlArrayItem("Automobile", GetType(Car))> _
    Public MyVehicles() As Vehicle
End Class


Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.SerializeObject("XmlArrayItem4.xml")
        test.DeserializeObject("XmlArrayItem4.xml")
    End Sub    
    
    Private Sub SerializeObject(ByVal filename As String)
        ' Creates an XmlSerializer for the Transportation class.
        Dim MySerializer As New XmlSerializer(GetType(Transportation))
        
        ' Writing the XML file to disk requires a TextWriter.
        Dim myTextWriter As New StreamWriter(filename)
        
        Dim myTransportation As New Transportation()
        
        Dim myVehicle As New Vehicle()
        myVehicle.id = "A12345"
        
        Dim myCar As New Car()
        myCar.id = "Car 34"
        myCar.Maker = "FamousCarMaker"
        
        Dim myVehicles() As Vehicle =  {myVehicle, myCar}
        myTransportation.MyVehicles = myVehicles
        
        ' Serializes the object, and closes the StreamWriter.
        MySerializer.Serialize(myTextWriter, myTransportation)
        myTextWriter.Close()
    End Sub    
    
    Private Sub DeserializeObject(ByVal filename As String)
        ' Creates an XmlSerializer.
        Dim mySerializer As New XmlSerializer(GetType(Transportation))
        Dim myFileStream As New FileStream(filename, FileMode.Open)
        Dim myTransportation As Transportation = _
            CType(mySerializer.Deserialize(myFileStream), Transportation)
        
        Dim i As Integer
        For i = 0 To myTransportation.MyVehicles.Length - 1
            Console.WriteLine(myTransportation.MyVehicles(i).id)
        Next i
    End Sub
End Class

Opmerkingen

Met deze overbelasting worden de ElementName en de Type eigenschappen ingesteld.

Gebruik deze overbelasting als u wilt dat de naam van het gegenereerde XML-element verschilt van de id van het lid.

Een XML-document met naamruimten kan meer dan één versie van een elementnaam bevatten. Zie de ElementName eigenschap voor meer informatie.

Van toepassing op