SyntaxNodeExtensions.WithLeadingTrivia Method
Definition
Important
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Overloads
WithLeadingTrivia<TSyntax>(TSyntax, SyntaxTriviaList) |
Creates a new node from this node with the leading trivia replaced. |
WithLeadingTrivia<TSyntax>(TSyntax, IEnumerable<SyntaxTrivia>) |
Creates a new node from this node with the leading trivia replaced. |
WithLeadingTrivia<TSyntax>(TSyntax, SyntaxTrivia[]) |
Creates a new node from this node with the leading trivia replaced. |
WithLeadingTrivia<TSyntax>(TSyntax, SyntaxTriviaList)
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
Creates a new node from this node with the leading trivia replaced.
public:
generic <typename TSyntax>
where TSyntax : Microsoft::CodeAnalysis::SyntaxNode[System::Runtime::CompilerServices::Extension]
static TSyntax WithLeadingTrivia(TSyntax node, Microsoft::CodeAnalysis::SyntaxTriviaList trivia);
public static TSyntax WithLeadingTrivia<TSyntax> (this TSyntax node, Microsoft.CodeAnalysis.SyntaxTriviaList trivia) where TSyntax : Microsoft.CodeAnalysis.SyntaxNode;
static member WithLeadingTrivia : 'Syntax * Microsoft.CodeAnalysis.SyntaxTriviaList -> 'Syntax (requires 'Syntax :> Microsoft.CodeAnalysis.SyntaxNode)
<Extension()>
Public Function WithLeadingTrivia(Of TSyntax As SyntaxNode) (node As TSyntax, trivia As SyntaxTriviaList) As TSyntax
Type Parameters
- TSyntax
Parameters
- node
- TSyntax
- trivia
- SyntaxTriviaList
Returns
Applies to
WithLeadingTrivia<TSyntax>(TSyntax, IEnumerable<SyntaxTrivia>)
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
Creates a new node from this node with the leading trivia replaced.
public:
generic <typename TSyntax>
where TSyntax : Microsoft::CodeAnalysis::SyntaxNode[System::Runtime::CompilerServices::Extension]
static TSyntax WithLeadingTrivia(TSyntax node, System::Collections::Generic::IEnumerable<Microsoft::CodeAnalysis::SyntaxTrivia> ^ trivia);
public static TSyntax WithLeadingTrivia<TSyntax> (this TSyntax node, System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxTrivia> trivia) where TSyntax : Microsoft.CodeAnalysis.SyntaxNode;
public static TSyntax WithLeadingTrivia<TSyntax> (this TSyntax node, System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxTrivia>? trivia) where TSyntax : Microsoft.CodeAnalysis.SyntaxNode;
static member WithLeadingTrivia : 'Syntax * seq<Microsoft.CodeAnalysis.SyntaxTrivia> -> 'Syntax (requires 'Syntax :> Microsoft.CodeAnalysis.SyntaxNode)
<Extension()>
Public Function WithLeadingTrivia(Of TSyntax As SyntaxNode) (node As TSyntax, trivia As IEnumerable(Of SyntaxTrivia)) As TSyntax
Type Parameters
- TSyntax
Parameters
- node
- TSyntax
- trivia
- IEnumerable<SyntaxTrivia>
Returns
Applies to
WithLeadingTrivia<TSyntax>(TSyntax, SyntaxTrivia[])
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
- Source:
- SyntaxNodeExtensions.cs
Creates a new node from this node with the leading trivia replaced.
public:
generic <typename TSyntax>
where TSyntax : Microsoft::CodeAnalysis::SyntaxNode[System::Runtime::CompilerServices::Extension]
static TSyntax WithLeadingTrivia(TSyntax node, ... cli::array <Microsoft::CodeAnalysis::SyntaxTrivia> ^ trivia);
public static TSyntax WithLeadingTrivia<TSyntax> (this TSyntax node, params Microsoft.CodeAnalysis.SyntaxTrivia[] trivia) where TSyntax : Microsoft.CodeAnalysis.SyntaxNode;
public static TSyntax WithLeadingTrivia<TSyntax> (this TSyntax node, params Microsoft.CodeAnalysis.SyntaxTrivia[]? trivia) where TSyntax : Microsoft.CodeAnalysis.SyntaxNode;
static member WithLeadingTrivia : 'Syntax * Microsoft.CodeAnalysis.SyntaxTrivia[] -> 'Syntax (requires 'Syntax :> Microsoft.CodeAnalysis.SyntaxNode)
<Extension()>
Public Function WithLeadingTrivia(Of TSyntax As SyntaxNode) (node As TSyntax, ParamArray trivia As SyntaxTrivia()) As TSyntax
Type Parameters
- TSyntax
Parameters
- node
- TSyntax
- trivia
- SyntaxTrivia[]