Udostępnij za pośrednictwem


Type.GenericParameterPosition Właściwość

Definicja

Pobiera pozycję parametru typu na liście parametrów typu typu lub metody, która zadeklarowała parametr, gdy Type obiekt reprezentuje parametr typu typu lub metodę ogólną.

public:
 abstract property int GenericParameterPosition { int get(); };
public:
 virtual property int GenericParameterPosition { int get(); };
public abstract int GenericParameterPosition { get; }
public virtual int GenericParameterPosition { get; }
member this.GenericParameterPosition : int
Public MustOverride ReadOnly Property GenericParameterPosition As Integer
Public Overridable ReadOnly Property GenericParameterPosition As Integer

Wartość właściwości

Pozycja parametru typu na liście parametrów typu typu lub metody definiującej parametr. Liczby pozycji zaczynają się od 0.

Wyjątki

Bieżący typ nie reprezentuje parametru typu. Oznacza to, IsGenericParameter że zwraca wartość false.

Przykłady

W poniższym przykładzie zdefiniowano klasę ogólną z dwoma parametrami typu i zdefiniowano drugą klasę ogólną, która pochodzi od pierwszej klasy. Klasa bazowa klasy pochodnej ma dwa argumenty typu: pierwszy to Int32, a drugi jest parametrem typu pochodnego typu. W przykładzie są wyświetlane informacje o tych klasach ogólnych, w tym pozycje zgłaszane przez GenericParameterPosition właściwość .

using namespace System;
using namespace System::Reflection;
using namespace System::Collections::Generic;

// Define a base class with two type parameters.
generic< class T,class U >
public ref class Base {};

// Define a derived class. The derived class inherits from a constructed
// class that meets the following criteria:
//   (1) Its generic type definition is Base<T, U>.
//   (2) It specifies int for the first type parameter.
//   (3) For the second type parameter, it uses the same type that is used
//       for the type parameter of the derived class.
// Thus, the derived class is a generic type with one type parameter, but
// its base class is an open constructed type with one type argument and
// one type parameter.
generic<class V>
public ref class Derived : Base<int,V> {};

public ref class Test
{
public:
    static void Main()
    {
        Console::WriteLine( 
            L"\r\n--- Display a generic type and the open constructed");
        Console::WriteLine(L"    type from which it is derived.");
      
        // Create a Type object representing the generic type definition
        // for the Derived type. Note the absence of type arguments.
        //
        Type^ derivedType = Derived::typeid;
        DisplayGenericTypeInfo(derivedType);
      
        // Display its open constructed base type.
        DisplayGenericTypeInfo(derivedType->BaseType);
    }


private:
    static void DisplayGenericTypeInfo(Type^ t)
    {
        Console::WriteLine(L"\r\n{0}", t);
        Console::WriteLine(L"\tIs this a generic type definition? {0}",
            t->IsGenericTypeDefinition);
        Console::WriteLine(L"\tIs it a generic type? {0}", t->IsGenericType);
        Console::WriteLine(L"\tDoes it have unassigned generic parameters? {0}",
            t->ContainsGenericParameters);
        if (t->IsGenericType)
        {
         
            // If this is a generic type, display the type arguments.
            //
            array<Type^>^typeArguments = t->GetGenericArguments();
            Console::WriteLine(L"\tList type arguments ({0}):",
                typeArguments->Length);
            System::Collections::IEnumerator^ myEnum = 
                typeArguments->GetEnumerator();
            while (myEnum->MoveNext())
            {
                Type^ tParam = safe_cast<Type^>(myEnum->Current);
            
                // IsGenericParameter is true only for generic type
                // parameters.
                //
                if (tParam->IsGenericParameter)
                {
                    Console::WriteLine( 
                        L"\t\t{0}  (unassigned - parameter position {1})", 
                        tParam, tParam->GenericParameterPosition);
                }
                else
                {
                    Console::WriteLine(L"\t\t{0}", tParam);
                }
            }
        }
    }
};

int main()
{
    Test::Main();
}

/* This example produces the following output:

--- Display a generic type and the open constructed
    type from which it is derived.

Derived`1[V]
        Is this a generic type definition? True
        Is it a generic type? True
        Does it have unassigned generic parameters? True
        List type arguments (1):
                V  (unassigned - parameter position 0)

Base`2[System.Int32,V]
        Is this a generic type definition? False
        Is it a generic type? True
        Does it have unassigned generic parameters? True
        List type arguments (2):
                System.Int32
                V  (unassigned - parameter position 0)
 */
using System;
using System.Reflection;
using System.Collections.Generic;

// Define a base class with two type parameters.
public class Base<T, U> { }

// Define a derived class. The derived class inherits from a constructed
// class that meets the following criteria:
//   (1) Its generic type definition is Base<T, U>.
//   (2) It specifies int for the first type parameter.
//   (3) For the second type parameter, it uses the same type that is used
//       for the type parameter of the derived class.
// Thus, the derived class is a generic type with one type parameter, but
// its base class is an open constructed type with one type argument and
// one type parameter.
public class Derived<V> : Base<int, V> { }

public class Test
{
    public static void Main()
    {
        Console.WriteLine(
            "\r\n--- Display a generic type and the open constructed");
        Console.WriteLine("    type from which it is derived.");

        // Create a Type object representing the generic type definition 
        // for the Derived type, by omitting the type argument. (For
        // types with multiple type parameters, supply the commas but
        // omit the type arguments.) 
        //
        Type derivedType = typeof(Derived<>);
        DisplayGenericTypeInfo(derivedType);

        // Display its open constructed base type.
        DisplayGenericTypeInfo(derivedType.BaseType);
    }

    private static void DisplayGenericTypeInfo(Type t)
    {
        Console.WriteLine("\r\n{0}", t);

        Console.WriteLine("\tIs this a generic type definition? {0}", 
            t.IsGenericTypeDefinition);

        Console.WriteLine("\tIs it a generic type? {0}", 
            t.IsGenericType);

        Console.WriteLine("\tDoes it have unassigned generic parameters? {0}", 
            t.ContainsGenericParameters);

        if (t.IsGenericType)
        {
            // If this is a generic type, display the type arguments.
            //
            Type[] typeArguments = t.GetGenericArguments();

            Console.WriteLine("\tList type arguments ({0}):", 
                typeArguments.Length);

            foreach (Type tParam in typeArguments)
            {
                // IsGenericParameter is true only for generic type
                // parameters.
                //
                if (tParam.IsGenericParameter)
                {
                    Console.WriteLine(
                        "\t\t{0}  (unassigned - parameter position {1})",
                        tParam,
                        tParam.GenericParameterPosition);
                }
                else
                {
                    Console.WriteLine("\t\t{0}", tParam);
                }
            }
        }
    }
}

/* This example produces the following output:

--- Display a generic type and the open constructed
    type from which it is derived.

Derived`1[V]
        Is this a generic type definition? True
        Is it a generic type? True
        Does it have unassigned generic parameters? True
        List type arguments (1):
                V  (unassigned - parameter position 0)

Base`2[System.Int32,V]
        Is this a generic type definition? False
        Is it a generic type? True
        Does it have unassigned generic parameters? True
        List type arguments (2):
                System.Int32
                V  (unassigned - parameter position 0)
 */
open System
open System.Reflection
open System.Collections.Generic

// Define a base class with two type parameters.
type Base<'T, 'U>() = class end

// Define a derived class. The derived class inherits from a constructed
// class that meets the following criteria:
//   (1) Its generic type definition is Base<T, U>.
//   (2) It specifies int for the first type parameter.
//   (3) For the second type parameter, it uses the same type that is used
//       for the type parameter of the derived class.
// Thus, the derived class is a generic type with one type parameter, but
// its base class is an open constructed type with one type argument and
// one type parameter.
type Derived<'V>() = inherit Base<int, 'V>()

let displayGenericTypeInfo (t: Type) =
    printfn $"\n{t}"
    printfn $"\tIs this a generic type definition? {t.IsGenericTypeDefinition}"
    printfn $"\tIs it a generic type? {t.IsGenericType}"
    printfn $"\tDoes it have unassigned generic parameters? {t.ContainsGenericParameters}"

    if t.IsGenericType then
        // If this is a generic type, display the type arguments.
        let typeArguments = t.GetGenericArguments()

        printfn $"\tList type arguments ({typeArguments.Length}):"

        for tParam in typeArguments do
            // IsGenericParameter is true only for generic type
            // parameters.
            if tParam.IsGenericParameter then
                printfn $"\t\t{tParam}  (unassigned - parameter position {tParam.GenericParameterPosition})"
            else
                printfn $"\t\t{tParam}"

printfn $"\r\n--- Display a generic type and the open constructed"
printfn $"    type from which it is derived."

// Create a Type object representing the generic type definition 
// for the Derived type, by omitting the type argument. (For
// types with multiple type parameters, supply the commas but
// omit the type arguments.) 
//
let derivedType = (typeof<Derived<_>>).GetGenericTypeDefinition()
displayGenericTypeInfo derivedType

// Display its open constructed base type.
displayGenericTypeInfo derivedType.BaseType

(* This example produces the following output:

--- Display a generic type and the open constructed
    type from which it is derived.

Derived`1[V]
        Is this a generic type definition? True
        Is it a generic type? True
        Does it have unassigned generic parameters? True
        List type arguments (1):
                V  (unassigned - parameter position 0)

Base`2[System.Int32,V]
        Is this a generic type definition? False
        Is it a generic type? True
        Does it have unassigned generic parameters? True
        List type arguments (2):
                System.Int32
                V  (unassigned - parameter position 0)
 *)
Imports System.Reflection
Imports System.Collections.Generic

' Define a base class with two type parameters.
Public Class Base(Of T, U)
End Class

' Define a derived class. The derived class inherits from a constructed
' class that meets the following criteria:
'   (1) Its generic type definition is Base<T, U>.
'   (2) It uses int for the first type parameter.
'   (3) For the second type parameter, it uses the same type that is used
'       for the type parameter of the derived class.
' Thus, the derived class is a generic type with one type parameter, but
' its base class is an open constructed type with one assigned type
' parameter and one unassigned type parameter.
Public Class Derived(Of V)
    Inherits Base(Of Integer, V)
End Class

Public Class Test
    
    Public Shared Sub Main() 
        Console.WriteLine(vbCrLf _
            & "--- Display a generic type and the open constructed")
        Console.WriteLine("    type from which it is derived.")
        
        ' Create a Type object representing the generic type definition 
        ' for the Derived type, by omitting the type argument. (For
        ' types with multiple type parameters, supply the commas but
        ' omit the type arguments.) 
        '
        Dim derivedType As Type = GetType(Derived(Of ))
        DisplayGenericTypeInfo(derivedType)
        
        ' Display its open constructed base type.
        DisplayGenericTypeInfo(derivedType.BaseType)
    
    End Sub
    
    Private Shared Sub DisplayGenericTypeInfo(ByVal t As Type) 
        Console.WriteLine(vbCrLf & "{0}", t)
        
        Console.WriteLine(vbTab & "Is this a generic type definition? " _
            & t.IsGenericTypeDefinition)
        
        Console.WriteLine(vbTab & "Is it a generic type? " _
            & t.IsGenericType)
        
        Console.WriteLine(vbTab _
            & "Does it have unassigned generic parameters? " _
            & t.ContainsGenericParameters)
        
        If t.IsGenericType Then
            ' If this is a generic type, display the type arguments.
            '
            Dim typeArguments As Type() = t.GetGenericArguments()
            
            Console.WriteLine(vbTab & "List type arguments (" _
                & typeArguments.Length & "):")
            
            For Each tParam As Type In typeArguments
                ' IsGenericParameter is true only for generic type
                ' parameters.
                '
                If tParam.IsGenericParameter Then
                    Console.WriteLine(vbTab & vbTab & tParam.ToString() _
                        & "  (unassigned - parameter position " _
                        & tParam.GenericParameterPosition & ")")
                Else
                    Console.WriteLine(vbTab & vbTab & tParam.ToString())
                End If
            Next tParam
        End If
    
    End Sub
End Class

' This example produces the following output:
'
'--- Display a generic type and the open constructed
'    type from which it is derived.
'
'Derived`1[V]
'        Is this a generic type definition? True
'        Is it a generic type? True
'        Does it have unassigned generic parameters? True
'        List type arguments (1):
'                V  (unassigned - parameter position 0)
'
'Base`2[System.Int32,V]
'        Is this a generic type definition? False
'        Is it a generic type? True
'        Does it have unassigned generic parameters? True
'        List type parameters (2):
'                System.Int32
'                V  (unassigned - parameter position 0)
'

Uwagi

Właściwość GenericParameterPosition zwraca pozycję parametru typu na liście parametrów definicji typu ogólnego lub definicji metody ogólnej, w której pierwotnie zdefiniowano parametr typu. Właściwości DeclaringType i DeclaringMethod identyfikują ogólny typ lub definicję metody:

  • DeclaringMethod Jeśli właściwość zwraca MethodInfowartość , która MethodInfo reprezentuje definicję metody ogólnej, a bieżący Type obiekt reprezentuje parametr typu tej definicji metody ogólnej.

  • DeclaringMethod Jeśli właściwość zwraca nullwartość , DeclaringType właściwość zawsze zwraca obiekt reprezentujący definicję Type typu ogólnego, a bieżący Type obiekt reprezentuje parametr typu tej definicji typu ogólnego.

Aby podać prawidłowy kontekst dla wartości GenericParameterPosition właściwości, należy zidentyfikować typ ogólny lub metodę, do którego należy parametr typu. Rozważmy na przykład wartość zwracaną metody GetSomething ogólnej w następującym kodzie:

generic<typename T, typename U> public ref class B { };
generic<typename V> public ref class A
{
public:
    generic<typename X> B<V, X>^ GetSomething()
    {
        return gcnew B<V, X>();
    }
};
public class B<T, U> { }
public class A<V>
{
    public B<V, X> GetSomething<X>()
    {
        return new B<V, X>();
    }
}
type B<'T, 'U>() = class end
type A<'V>() =
    member _.GetSomething<'X>() =
        B<'V, 'X>()
Public Class B(Of T, U)
End Class
Public Class A(Of V)
    Public Function GetSomething(Of X)() As B(Of V, X)
        Return New B(Of V, X)()
    End Function
End Class

Typ zwracany przez GetSomething element zależy od argumentów typu dostarczonych do klasy A i do GetSomething samego siebie. Możesz uzyskać element MethodInfo dla GetSomething, i , z którego można uzyskać typ zwracany. Podczas badania parametrów typu zwracanego typu GenericParameterPosition zwraca wartość 0 dla obu typów. Pozycja parametru V to 0, ponieważ V jest pierwszym parametrem typu na liście parametrów typu dla klasy A. Pozycja parametru X to 0, ponieważ X jest pierwszym parametrem typu na liście parametrów typu dla elementu GetSomething.

Uwaga

GenericParameterPosition Wywołanie właściwości powoduje wyjątek, jeśli bieżący Type nie reprezentuje parametru typu. Podczas badania argumentów typu otwartego typu typu należy użyć IsGenericParameter właściwości , aby określić, które parametry typu i które są typami. Właściwość IsGenericParameter zwraca true parametr typu. Następnie można użyć GenericParameterPosition metody , aby uzyskać jej pozycję i użyć DeclaringMethod właściwości i DeclaringType w celu określenia metody ogólnej lub definicji typu, która ją definiuje.

Dotyczy

Zobacz też