XmlArrayItemAttribute Konstruktory
Definicja
Ważne
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Inicjuje nowe wystąpienie klasy XmlArrayItemAttribute.
Przeciążenia
XmlArrayItemAttribute() |
Inicjuje nowe wystąpienie klasy XmlArrayItemAttribute. |
XmlArrayItemAttribute(String) |
Inicjuje XmlArrayItemAttribute nowe wystąpienie klasy i określa nazwę elementu XML wygenerowanego w dokumencie XML. |
XmlArrayItemAttribute(Type) |
Inicjuje XmlArrayItemAttribute nowe wystąpienie klasy i określa Type , które można wstawić do tablicy serializowanej. |
XmlArrayItemAttribute(String, Type) |
Inicjuje nowe wystąpienie XmlArrayItemAttribute klasy i określa nazwę elementu XML wygenerowanego w dokumencie XML i element Type , który można wstawić do wygenerowanego dokumentu XML. |
XmlArrayItemAttribute()
- Źródło:
- XmlArrayItemAttribute.cs
- Źródło:
- XmlArrayItemAttribute.cs
- Źródło:
- XmlArrayItemAttribute.cs
Inicjuje nowe wystąpienie klasy XmlArrayItemAttribute.
public:
XmlArrayItemAttribute();
public XmlArrayItemAttribute ();
Public Sub New ()
Przykłady
Poniższy przykład serializuje klasę o nazwie , która zawiera pole o nazwie Transportation
MyVehicles
, które zwraca tablicę Vehicle
obiektów. Przykład dotyczy XmlArrayItemAttribute pola, co umożliwia XmlSerializer wstawianie wystąpień Car
klasy, która pochodzi z Vehicle
klasy do tablicy.
#using <System.Xml.dll>
#using <System.dll>
using namespace System;
using namespace System::IO;
using namespace System::Xml;
using namespace System::Xml::Serialization;
public ref class Vehicle
{
public:
String^ id;
};
public ref class Car: public Vehicle
{
public:
String^ Maker;
};
public ref class Transportation
{
public:
[XmlArrayItem,
XmlArrayItem(Car::typeid,ElementName="Automobile")]
array<Vehicle^>^MyVehicles;
};
void SerializeObject( String^ filename )
{
// Creates an XmlSerializer for the Transportation class.
XmlSerializer^ MySerializer = gcnew XmlSerializer( Transportation::typeid );
// Writing the XML file to disk requires a TextWriter.
TextWriter^ myTextWriter = gcnew StreamWriter( filename );
// Creates the object to serialize.
Transportation^ myTransportation = gcnew Transportation;
// Creates objects to add to the array.
Vehicle^ myVehicle = gcnew Vehicle;
myVehicle->id = "A12345";
Car^ myCar = gcnew Car;
myCar->id = "Car 34";
myCar->Maker = "FamousCarMaker";
array<Vehicle^>^temp = {myVehicle,myCar};
myTransportation->MyVehicles = temp;
// Serializes the object, and closes the StreamWriter.
MySerializer->Serialize( myTextWriter, myTransportation );
myTextWriter->Close();
}
void DeserializeObject( String^ filename )
{
// Creates an XmlSerializer instance.
XmlSerializer^ mySerializer = gcnew XmlSerializer( Transportation::typeid );
FileStream^ myFileStream = gcnew FileStream( filename,FileMode::Open );
Transportation^ myTransportation = dynamic_cast<Transportation^>(mySerializer->Deserialize( myFileStream ));
for ( int i = 0; i < myTransportation->MyVehicles->Length; i++ )
{
Console::WriteLine( myTransportation->MyVehicles[ i ]->id );
}
}
int main()
{
SerializeObject( "XmlArrayItem1.xml" );
DeserializeObject( "XmlArrayItem1.xml" );
}
using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
public class Vehicle
{
public string id;
}
public class Car:Vehicle
{
public string Maker;
}
public class Transportation
{
[XmlArrayItem(),
XmlArrayItem(typeof(Car), ElementName = "Automobile")]
public Vehicle[] MyVehicles;
}
public class Run
{
public static void Main()
{
Run test = new Run();
test.SerializeObject("XmlArrayItem1.xml");
test.DeserializeObject("XmlArrayItem1.xml");
}
private void SerializeObject(string filename){
// Creates an XmlSerializer for the Transportation class.
XmlSerializer MySerializer = new XmlSerializer(typeof(Transportation));
// Writing the XML file to disk requires a TextWriter.
TextWriter myTextWriter = new StreamWriter(filename);
// Creates the object to serialize.
Transportation myTransportation = new Transportation();
// Creates objects to add to the array.
Vehicle myVehicle= new Vehicle() ;
myVehicle.id = "A12345";
Car myCar = new Car();
myCar.id = "Car 34";
myCar.Maker = "FamousCarMaker";
myTransportation.MyVehicles =
new Vehicle[2] {myVehicle, myCar};
// Serializes the object, and closes the StreamWriter.
MySerializer.Serialize(myTextWriter, myTransportation);
myTextWriter.Close();
}
private void DeserializeObject(string filename)
{
// Creates an XmlSerializer instance.
XmlSerializer mySerializer = new XmlSerializer(typeof(Transportation));
FileStream myFileStream = new FileStream(filename,FileMode.Open);
Transportation myTransportation =
(Transportation) mySerializer.Deserialize(myFileStream);
for(int i = 0; i < myTransportation.MyVehicles.Length;i++)
{
Console.WriteLine(myTransportation.MyVehicles[i].id);
}
}
}
Option Explicit
Option Strict
Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization
Public Class Vehicle
Public id As String
End Class
Public Class Car
Inherits Vehicle
Public Maker As String
End Class
Public Class Transportation
<XmlArrayItem(), _
XmlArrayItem(GetType(Car), ElementName := "Automobile")> _
Public MyVehicles() As Vehicle
End Class
Public Class Run
Public Shared Sub Main()
Dim test As New Run()
test.SerializeObject("XmlArrayItem1.xml")
test.DeserializeObject("XmlArrayItem1.xml")
End Sub
Private Sub SerializeObject(ByVal filename As String)
' Creates an XmlSerializer for the Transportation class.
Dim MySerializer As New XmlSerializer(GetType(Transportation))
' Writing the XML file to disk requires a TextWriter.
Dim myTextWriter As New StreamWriter(filename)
' Creates the object to serialize.
Dim myTransportation As New Transportation()
' Creates objects to add to the array.
Dim myVehicle As New Vehicle()
myVehicle.id = "A12345"
Dim myCar As New Car()
myCar.id = "Car 34"
myCar.Maker = "FamousCarMaker"
myTransportation.MyVehicles = New Vehicle() {myVehicle, myCar}
' Serializes the object, and closes the StreamWriter.
MySerializer.Serialize(myTextWriter, myTransportation)
myTextWriter.Close()
End Sub
Private Sub DeserializeObject(ByVal filename As String)
' Create an XmlSerializer instance.
Dim mySerializer As New XmlSerializer(GetType(Transportation))
Dim myFileStream As New FileStream(filename, FileMode.Open)
Dim myTransportation As Transportation = _
CType(mySerializer.Deserialize(myFileStream), Transportation)
Dim i As Integer
For i = 0 To myTransportation.MyVehicles.Length - 1
Console.WriteLine(myTransportation.MyVehicles(i).id)
Next i
End Sub
End Class
Dotyczy
XmlArrayItemAttribute(String)
- Źródło:
- XmlArrayItemAttribute.cs
- Źródło:
- XmlArrayItemAttribute.cs
- Źródło:
- XmlArrayItemAttribute.cs
Inicjuje XmlArrayItemAttribute nowe wystąpienie klasy i określa nazwę elementu XML wygenerowanego w dokumencie XML.
public:
XmlArrayItemAttribute(System::String ^ elementName);
public XmlArrayItemAttribute (string elementName);
public XmlArrayItemAttribute (string? elementName);
new System.Xml.Serialization.XmlArrayItemAttribute : string -> System.Xml.Serialization.XmlArrayItemAttribute
Public Sub New (elementName As String)
Parametry
- elementName
- String
Nazwa elementu XML.
Przykłady
Poniższy przykład serializuje klasę o nazwie , która zawiera pole o nazwie Transportation
MyVehicles
, które zwraca tablicę Vehicle
obiektów. Przykład dotyczy XmlArrayItemAttribute pola, co umożliwia XmlSerializer wstawianie wystąpień Car
klasy, która pochodzi z Vehicle
klasy do tablicy. Podczas stosowania atrybutu przykład ustawia ElementName właściwość przy użyciu parametru elementName
.
#using <System.Xml.dll>
#using <System.dll>
using namespace System;
using namespace System::IO;
using namespace System::Xml;
using namespace System::Xml::Serialization;
public ref class Vehicle
{
public:
String^ id;
};
public ref class Car: public Vehicle
{
public:
String^ Maker;
};
public ref class Transportation
{
public:
[XmlArrayItem(ElementName="Transportation"),
XmlArrayItem(Car::typeid,ElementName="Automobile")]
array<Vehicle^>^MyVehicles;
};
void SerializeObject( String^ filename )
{
// Creates an XmlSerializer for the Transportation class.
XmlSerializer^ MySerializer = gcnew XmlSerializer( Transportation::typeid );
// Writing the XML file to disk requires a TextWriter.
TextWriter^ myTextWriter = gcnew StreamWriter( filename );
Transportation^ myTransportation = gcnew Transportation;
Vehicle^ myVehicle = gcnew Vehicle;
myVehicle->id = "A12345";
Car^ myCar = gcnew Car;
myCar->id = "Car 34";
myCar->Maker = "FamousCarMaker";
array<Vehicle^>^myVehicles = {myVehicle,myCar};
myTransportation->MyVehicles = myVehicles;
// Serializes the object, and closes the StreamWriter.
MySerializer->Serialize( myTextWriter, myTransportation );
myTextWriter->Close();
}
void DeserializeObject( String^ filename )
{
// Creates the serializer with the type to deserialize.
XmlSerializer^ mySerializer = gcnew XmlSerializer( Transportation::typeid );
FileStream^ myFileStream = gcnew FileStream( filename,FileMode::Open );
Transportation^ myTransportation = dynamic_cast<Transportation^>(mySerializer->Deserialize( myFileStream ));
for ( int i = 0; i < myTransportation->MyVehicles->Length; i++ )
{
Console::WriteLine( myTransportation->MyVehicles[ i ]->id );
}
}
int main()
{
SerializeObject( "XmlArrayItem2.xml" );
DeserializeObject( "XmlArrayItem2.xml" );
}
using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
public class Vehicle
{
public string id;
}
public class Car:Vehicle
{
public string Maker;
}
public class Transportation
{
[XmlArrayItem(ElementName = "Transportation"),
XmlArrayItem(typeof(Car), ElementName = "Automobile")]
public Vehicle[] MyVehicles;
}
public class Run
{
public static void Main()
{
Run test= new Run();
test.SerializeObject("XmlArrayItem2.xml");
test.DeserializeObject("XmlArrayItem2.xml");
}
private void SerializeObject(string filename)
{
// Creates an XmlSerializer for the Transportation class.
XmlSerializer MySerializer =
new XmlSerializer(typeof(Transportation));
// Writing the XML file to disk requires a TextWriter.
TextWriter myTextWriter = new StreamWriter(filename);
Transportation myTransportation = new Transportation();
Vehicle myVehicle= new Vehicle() ;
myVehicle.id = "A12345";
Car myCar = new Car();
myCar.id = "Car 34";
myCar.Maker = "FamousCarMaker";
Vehicle [] myVehicles = {myVehicle, myCar};
myTransportation.MyVehicles = myVehicles;
// Serializes the object, and closes the StreamWriter.
MySerializer.Serialize(myTextWriter, myTransportation);
myTextWriter.Close();
}
private void DeserializeObject(string filename)
{
// Creates the serializer with the type to deserialize.
XmlSerializer mySerializer =
new XmlSerializer(typeof(Transportation));
FileStream myFileStream = new FileStream(filename,FileMode.Open);
Transportation myTransportation =
(Transportation) mySerializer.Deserialize(myFileStream);
for(int i = 0;i < myTransportation.MyVehicles.Length;i++)
{
Console.WriteLine(myTransportation.MyVehicles[i].id);
}
}
}
Option Explicit
Option Strict
Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization
Public Class Vehicle
Public id As String
End Class
Public Class Car
Inherits Vehicle
Public Maker As String
End Class
Public Class Transportation
<XmlArrayItem(ElementName := "Transportation"), _
XmlArrayItem(GetType(Car), ElementName := "Automobile")> _
Public MyVehicles() As Vehicle
End Class
Public Class Run
Public Shared Sub Main()
Dim test As New Run()
test.SerializeObject("XmlArrayItem2.xml")
test.DeserializeObject("XmlArrayItem2.xml")
End Sub
Private Sub SerializeObject(ByVal filename As String)
' Creates an XmlSerializer for the Transportation class.
Dim MySerializer As New XmlSerializer(GetType(Transportation))
' Writing the XML file to disk requires a TextWriter.
Dim myTextWriter As New StreamWriter(filename)
Dim myTransportation As New Transportation()
Dim myVehicle As New Vehicle()
myVehicle.id = "A12345"
Dim myCar As New Car()
myCar.id = "Car 34"
myCar.Maker = "FamousCarMaker"
Dim myVehicles() As Vehicle = {myVehicle, myCar}
myTransportation.MyVehicles = myVehicles
' Serializes the object, and closes the StreamWriter.
MySerializer.Serialize(myTextWriter, myTransportation)
myTextWriter.Close()
End Sub
Private Sub DeserializeObject(ByVal filename As String)
' Create the serializer with the type to deserialize.
Dim mySerializer As New XmlSerializer(GetType(Transportation))
Dim myFileStream As New FileStream(filename, FileMode.Open)
Dim myTransportation As Transportation = _
CType(mySerializer.Deserialize(myFileStream), Transportation)
Dim i As Integer
For i = 0 To myTransportation.MyVehicles.Length - 1
Console.WriteLine(myTransportation.MyVehicles(i).id)
Next i
End Sub
End Class
Uwagi
To przeciążenie ustawia ElementName właściwość .
Użyj tego przeciążenia, jeśli chcesz, aby nazwa wygenerowanego elementu XML różniła się od identyfikatora elementu członkowskiego.
Dokument XML zawierający przestrzenie nazw może zawierać więcej niż jedną wersję nazwy elementu. Aby uzyskać szczegółowe informacje, zobacz ElementName właściwość .
Dotyczy
XmlArrayItemAttribute(Type)
- Źródło:
- XmlArrayItemAttribute.cs
- Źródło:
- XmlArrayItemAttribute.cs
- Źródło:
- XmlArrayItemAttribute.cs
Inicjuje XmlArrayItemAttribute nowe wystąpienie klasy i określa Type , które można wstawić do tablicy serializowanej.
public:
XmlArrayItemAttribute(Type ^ type);
public XmlArrayItemAttribute (Type type);
public XmlArrayItemAttribute (Type? type);
new System.Xml.Serialization.XmlArrayItemAttribute : Type -> System.Xml.Serialization.XmlArrayItemAttribute
Public Sub New (type As Type)
Parametry
Przykłady
Poniższy przykład serializuje klasę o nazwie , która zawiera pole o nazwie Transportation
MyVehicles
, które zwraca tablicę Vehicle
obiektów. Przykład dotyczy XmlArrayItemAttribute pola, co umożliwia XmlSerializer wstawianie wystąpień Car
klasy, która pochodzi z Vehicle
klasy do tablicy. Podczas stosowania atrybutu przykład ustawia Type właściwość przy użyciu parametru type
.
#using <System.Xml.dll>
#using <System.dll>
using namespace System;
using namespace System::IO;
using namespace System::Xml;
using namespace System::Xml::Serialization;
public ref class Vehicle
{
public:
String^ id;
};
public ref class Car: public Vehicle
{
public:
String^ Maker;
};
public ref class Transportation
{
public:
[XmlArrayItem(Vehicle::typeid),
XmlArrayItem(Car::typeid)]
array<Vehicle^>^MyVehicles;
};
void SerializeObject( String^ filename )
{
// Creates an XmlSerializer.
XmlSerializer^ MySerializer = gcnew XmlSerializer( Transportation::typeid );
// Writing the XML file to disk requires a TextWriter.
TextWriter^ myTextWriter = gcnew StreamWriter( filename );
Transportation^ myTransportation = gcnew Transportation;
Vehicle^ myVehicle = gcnew Vehicle;
myVehicle->id = "A12345";
Car^ myCar = gcnew Car;
myCar->id = "Car 34";
myCar->Maker = "FamousCarMaker";
array<Vehicle^>^myVehicles = {myVehicle,myCar};
myTransportation->MyVehicles = myVehicles;
// Serializes the object, and closes the StreamWriter.
MySerializer->Serialize( myTextWriter, myTransportation );
myTextWriter->Close();
}
void DeserializeObject( String^ filename )
{
// Creates the serializer with the type to deserialize.
XmlSerializer^ mySerializer = gcnew XmlSerializer( Transportation::typeid );
FileStream^ myFileStream = gcnew FileStream( filename,FileMode::Open );
Transportation^ myTransportation = dynamic_cast<Transportation^>(mySerializer->Deserialize( myFileStream ));
for ( int i = 0; i < myTransportation->MyVehicles->Length; i++ )
{
Console::WriteLine( myTransportation->MyVehicles[ i ]->id );
}
}
int main()
{
SerializeObject( "XmlArrayItem3.xml" );
DeserializeObject( "XmlArrayItem3.xml" );
}
using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
public class Vehicle
{
public string id;
}
public class Car:Vehicle
{
public string Maker;
}
public class Transportation
{
[XmlArrayItem(typeof(Vehicle)),
XmlArrayItem(typeof(Car))]
public Vehicle[] MyVehicles;
}
public class Run
{
public static void Main()
{
Run test= new Run();
test.SerializeObject("XmlArrayItem3.xml");
test.DeserializeObject("XmlArrayItem3.xml");
}
private void SerializeObject(string filename)
{
// Creates an XmlSerializer.
XmlSerializer MySerializer =
new XmlSerializer(typeof(Transportation));
// Writing the XML file to disk requires a TextWriter.
TextWriter myTextWriter = new StreamWriter(filename);
Transportation myTransportation = new Transportation();
Vehicle myVehicle= new Vehicle() ;
myVehicle.id = "A12345";
Car myCar = new Car();
myCar.id = "Car 34";
myCar.Maker = "FamousCarMaker";
Vehicle [] myVehicles = {myVehicle, myCar};
myTransportation.MyVehicles = myVehicles;
// Serializes the object, and closes the StreamWriter.
MySerializer.Serialize(myTextWriter, myTransportation);
myTextWriter.Close();
}
private void DeserializeObject(string filename)
{
// Creates the serializer with the type to deserialize.
XmlSerializer mySerializer =
new XmlSerializer(typeof(Transportation));
FileStream myFileStream = new FileStream(filename,FileMode.Open);
Transportation myTransportation =
(Transportation) mySerializer.Deserialize(myFileStream);
for(int i = 0;i < myTransportation.MyVehicles.Length;i++)
{
Console.WriteLine(myTransportation.MyVehicles[i].id);
}
}
}
Option Explicit
Option Strict
Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization
Public Class Vehicle
Public id As String
End Class
Public Class Car
Inherits Vehicle
Public Maker As String
End Class
Public Class Transportation
<XmlArrayItem(GetType(Vehicle)), _
XmlArrayItem(GetType(Car))> _
Public MyVehicles() As Vehicle
End Class
Public Class Run
Public Shared Sub Main()
Dim test As New Run()
test.SerializeObject("XmlArrayItem3.xml")
test.DeserializeObject("XmlArrayItem3.xml")
End Sub
Private Sub SerializeObject(ByVal filename As String)
' Creates an XmlSerializer object.
Dim MySerializer As New XmlSerializer(GetType(Transportation))
' Writing the XML file to disk requires a TextWriter.
Dim myTextWriter As New StreamWriter(filename)
Dim myTransportation As New Transportation()
Dim myVehicle As New Vehicle()
myVehicle.id = "A12345"
Dim myCar As New Car()
myCar.id = "Car 34"
myCar.Maker = "FamousCarMaker"
Dim myVehicles() As Vehicle = {myVehicle, myCar}
myTransportation.MyVehicles = myVehicles
' Serializes the object, and closes the StreamWriter.
MySerializer.Serialize(myTextWriter, myTransportation)
myTextWriter.Close()
End Sub
Private Sub DeserializeObject(ByVal filename As String)
' Creates the serializer with the type to deserialize.
Dim mySerializer As New XmlSerializer(GetType(Transportation))
Dim myFileStream As New FileStream(filename, FileMode.Open)
Dim myTransportation As Transportation = _
CType(mySerializer.Deserialize(myFileStream), Transportation)
Dim i As Integer
For i = 0 To myTransportation.MyVehicles.Length - 1
Console.WriteLine(myTransportation.MyVehicles(i).id)
Next i
End Sub
End Class
Dotyczy
XmlArrayItemAttribute(String, Type)
- Źródło:
- XmlArrayItemAttribute.cs
- Źródło:
- XmlArrayItemAttribute.cs
- Źródło:
- XmlArrayItemAttribute.cs
Inicjuje nowe wystąpienie XmlArrayItemAttribute klasy i określa nazwę elementu XML wygenerowanego w dokumencie XML i element Type , który można wstawić do wygenerowanego dokumentu XML.
public:
XmlArrayItemAttribute(System::String ^ elementName, Type ^ type);
public XmlArrayItemAttribute (string elementName, Type type);
public XmlArrayItemAttribute (string? elementName, Type? type);
new System.Xml.Serialization.XmlArrayItemAttribute : string * Type -> System.Xml.Serialization.XmlArrayItemAttribute
Public Sub New (elementName As String, type As Type)
Parametry
- elementName
- String
Nazwa elementu XML.
Przykłady
Poniższy przykład serializuje klasę o nazwie , która zawiera pole o nazwie Transportation
MyVehicles
, które zwraca tablicę Vehicle
obiektów. Przykład dotyczy XmlArrayItemAttribute pola, co umożliwia XmlSerializer wstawianie wystąpień Car
klasy, która pochodzi z Vehicle
klasy do tablicy. Podczas stosowania atrybutu przykład ustawia ElementName właściwość przy użyciu parametru elementName
i Type właściwość przy użyciu parametru type
.
#using <System.Xml.dll>
#using <System.dll>
using namespace System;
using namespace System::IO;
using namespace System::Xml;
using namespace System::Xml::Serialization;
public ref class Vehicle
{
public:
String^ id;
};
public ref class Car: public Vehicle
{
public:
String^ Maker;
};
public ref class Transportation
{
public:
[XmlArray]
[XmlArrayItem("Transport",Vehicle::typeid),
XmlArrayItem("Automobile",Car::typeid)]
array<Vehicle^>^MyVehicles;
};
void SerializeObject( String^ filename )
{
// Creates an XmlSerializer for the Transportation class.
XmlSerializer^ MySerializer = gcnew XmlSerializer( Transportation::typeid );
// Writing the XML file to disk requires a TextWriter.
TextWriter^ myTextWriter = gcnew StreamWriter( filename );
Transportation^ myTransportation = gcnew Transportation;
Vehicle^ myVehicle = gcnew Vehicle;
myVehicle->id = "A12345";
Car^ myCar = gcnew Car;
myCar->id = "Car 34";
myCar->Maker = "FamousCarMaker";
array<Vehicle^>^myVehicles = {myVehicle,myCar};
myTransportation->MyVehicles = myVehicles;
// Serializes the object, and closes the StreamWriter.
MySerializer->Serialize( myTextWriter, myTransportation );
myTextWriter->Close();
}
void DeserializeObject( String^ filename )
{
// Creates an XmlSerializer.
XmlSerializer^ mySerializer = gcnew XmlSerializer( Transportation::typeid );
FileStream^ myFileStream = gcnew FileStream( filename,FileMode::Open );
Transportation^ myTransportation = dynamic_cast<Transportation^>(mySerializer->Deserialize( myFileStream ));
for ( int i = 0; i < myTransportation->MyVehicles->Length; i++ )
{
Console::WriteLine( myTransportation->MyVehicles[ i ]->id );
}
}
int main()
{
SerializeObject( "XmlArrayItem4.xml" );
DeserializeObject( "XmlArrayItem4.xml" );
}
using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
public class Vehicle
{
public string id;
}
public class Car:Vehicle
{
public string Maker;
}
public class Transportation
{
[XmlArray]
[XmlArrayItem("Transport", typeof(Vehicle)),
XmlArrayItem("Automobile", typeof(Car))]
public Vehicle[] MyVehicles;
}
public class Run
{
public static void Main()
{
Run test= new Run();
test.SerializeObject("XmlArrayItem4.xml");
test.DeserializeObject("XmlArrayItem4.xml");
}
private void SerializeObject(string filename)
{
// Creates an XmlSerializer for the Transportation class.
XmlSerializer MySerializer =
new XmlSerializer(typeof(Transportation));
// Writing the XML file to disk requires a TextWriter.
TextWriter myTextWriter = new StreamWriter(filename);
Transportation myTransportation = new Transportation();
Vehicle myVehicle= new Vehicle() ;
myVehicle.id = "A12345";
Car myCar = new Car();
myCar.id = "Car 34";
myCar.Maker = "FamousCarMaker";
Vehicle [] myVehicles = {myVehicle, myCar};
myTransportation.MyVehicles = myVehicles;
// Serializes the object, and closes the StreamWriter.
MySerializer.Serialize(myTextWriter, myTransportation);
myTextWriter.Close();
}
private void DeserializeObject(string filename)
{
// Creates an XmlSerializer.
XmlSerializer mySerializer =
new XmlSerializer(typeof(Transportation));
FileStream myFileStream = new FileStream(filename,FileMode.Open);
Transportation myTransportation =
(Transportation) mySerializer.Deserialize(myFileStream);
for(int i = 0;i < myTransportation.MyVehicles.Length;i++)
{
Console.WriteLine(myTransportation.MyVehicles[i].id);
}
}
}
Option Explicit
Option Strict
Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization
Public Class Vehicle
Public id As String
End Class
Public Class Car
Inherits Vehicle
Public Maker As String
End Class
Public Class Transportation
<XmlArray(), _
XmlArrayItem("Transport", GetType(Vehicle)), _
XmlArrayItem("Automobile", GetType(Car))> _
Public MyVehicles() As Vehicle
End Class
Public Class Run
Public Shared Sub Main()
Dim test As New Run()
test.SerializeObject("XmlArrayItem4.xml")
test.DeserializeObject("XmlArrayItem4.xml")
End Sub
Private Sub SerializeObject(ByVal filename As String)
' Creates an XmlSerializer for the Transportation class.
Dim MySerializer As New XmlSerializer(GetType(Transportation))
' Writing the XML file to disk requires a TextWriter.
Dim myTextWriter As New StreamWriter(filename)
Dim myTransportation As New Transportation()
Dim myVehicle As New Vehicle()
myVehicle.id = "A12345"
Dim myCar As New Car()
myCar.id = "Car 34"
myCar.Maker = "FamousCarMaker"
Dim myVehicles() As Vehicle = {myVehicle, myCar}
myTransportation.MyVehicles = myVehicles
' Serializes the object, and closes the StreamWriter.
MySerializer.Serialize(myTextWriter, myTransportation)
myTextWriter.Close()
End Sub
Private Sub DeserializeObject(ByVal filename As String)
' Creates an XmlSerializer.
Dim mySerializer As New XmlSerializer(GetType(Transportation))
Dim myFileStream As New FileStream(filename, FileMode.Open)
Dim myTransportation As Transportation = _
CType(mySerializer.Deserialize(myFileStream), Transportation)
Dim i As Integer
For i = 0 To myTransportation.MyVehicles.Length - 1
Console.WriteLine(myTransportation.MyVehicles(i).id)
Next i
End Sub
End Class
Uwagi
To przeciążenie ustawia ElementName właściwości i Type .
Użyj tego przeciążenia, jeśli chcesz, aby nazwa wygenerowanego elementu XML różniła się od identyfikatora elementu członkowskiego.
Dokument XML zawierający przestrzenie nazw może zawierać więcej niż jedną wersję nazwy elementu. Aby uzyskać szczegółowe informacje, zobacz ElementName właściwość .