Semaphore.Release Método
Definição
Importante
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O semáforo é encerrado.
Sobrecargas
Release() |
Sai do sinal e retorna à contagem anterior. |
Release(Int32) |
Sai do sinal de um número de vezes especificado e retorna à contagem anterior. |
Release()
Sai do sinal e retorna à contagem anterior.
public:
int Release();
public int Release ();
member this.Release : unit -> int
Public Function Release () As Integer
Retornos
A contagem no sinal antes do método Release ser chamado.
Exceções
A contagem de semáforo já está no valor máximo.
Ocorreu um erro de Win32 com um semáforo nomeado.
O semáforo atual representa um semáforo de sistema nomeado, mas o usuário não tem Modify.
- ou - O sinal do atual representa um sinal de sistema nomeado, mas não foi aberto com Modify.
Exemplos
O exemplo de código a seguir cria um semáforo com uma contagem máxima de três e uma contagem inicial de zero. O exemplo inicia cinco threads, que bloqueiam a espera pelo semáforo. O thread principal usa a sobrecarga do Release(Int32) método para aumentar a contagem de semáforos para o máximo, permitindo que três threads insiram o semáforo. Cada thread usa o Thread.Sleep método para aguardar um segundo, para simular o trabalho e, em seguida, chama a sobrecarga do Release() método para liberar o semáforo.
Cada vez que o semáforo é liberado, a contagem de semáforos anterior é exibida. As mensagens do console rastreiam o uso de semáforo. O intervalo de trabalho simulado é ligeiramente aumentado para cada thread, para facilitar a leitura da saída.
#using <System.dll>
using namespace System;
using namespace System::Threading;
public ref class Example
{
private:
// A semaphore that simulates a limited resource pool.
//
static Semaphore^ _pool;
// A padding interval to make the output more orderly.
static int _padding;
public:
static void Main()
{
// Create a semaphore that can satisfy up to three
// concurrent requests. Use an initial count of zero,
// so that the entire semaphore count is initially
// owned by the main program thread.
//
_pool = gcnew Semaphore( 0,3 );
// Create and start five numbered threads.
//
for ( int i = 1; i <= 5; i++ )
{
Thread^ t = gcnew Thread(
gcnew ParameterizedThreadStart( Worker ) );
// Start the thread, passing the number.
//
t->Start( i );
}
// Wait for half a second, to allow all the
// threads to start and to block on the semaphore.
//
Thread::Sleep( 500 );
// The main thread starts out holding the entire
// semaphore count. Calling Release(3) brings the
// semaphore count back to its maximum value, and
// allows the waiting threads to enter the semaphore,
// up to three at a time.
//
Console::WriteLine( L"Main thread calls Release(3)." );
_pool->Release( 3 );
Console::WriteLine( L"Main thread exits." );
}
private:
static void Worker( Object^ num )
{
// Each worker thread begins by requesting the
// semaphore.
Console::WriteLine( L"Thread {0} begins and waits for the semaphore.", num );
_pool->WaitOne();
// A padding interval to make the output more orderly.
int padding = Interlocked::Add( _padding, 100 );
Console::WriteLine( L"Thread {0} enters the semaphore.", num );
// The thread's "work" consists of sleeping for
// about a second. Each thread "works" a little
// longer, just to make the output more orderly.
//
Thread::Sleep( 1000 + padding );
Console::WriteLine( L"Thread {0} releases the semaphore.", num );
Console::WriteLine( L"Thread {0} previous semaphore count: {1}",
num, _pool->Release() );
}
};
using System;
using System.Threading;
public class Example
{
// A semaphore that simulates a limited resource pool.
//
private static Semaphore _pool;
// A padding interval to make the output more orderly.
private static int _padding;
public static void Main()
{
// Create a semaphore that can satisfy up to three
// concurrent requests. Use an initial count of zero,
// so that the entire semaphore count is initially
// owned by the main program thread.
//
_pool = new Semaphore(initialCount: 0, maximumCount: 3);
// Create and start five numbered threads.
//
for(int i = 1; i <= 5; i++)
{
Thread t = new Thread(new ParameterizedThreadStart(Worker));
// Start the thread, passing the number.
//
t.Start(i);
}
// Wait for half a second, to allow all the
// threads to start and to block on the semaphore.
//
Thread.Sleep(500);
// The main thread starts out holding the entire
// semaphore count. Calling Release(3) brings the
// semaphore count back to its maximum value, and
// allows the waiting threads to enter the semaphore,
// up to three at a time.
//
Console.WriteLine("Main thread calls Release(3).");
_pool.Release(releaseCount: 3);
Console.WriteLine("Main thread exits.");
}
private static void Worker(object num)
{
// Each worker thread begins by requesting the
// semaphore.
Console.WriteLine("Thread {0} begins " +
"and waits for the semaphore.", num);
_pool.WaitOne();
// A padding interval to make the output more orderly.
int padding = Interlocked.Add(ref _padding, 100);
Console.WriteLine("Thread {0} enters the semaphore.", num);
// The thread's "work" consists of sleeping for
// about a second. Each thread "works" a little
// longer, just to make the output more orderly.
//
Thread.Sleep(1000 + padding);
Console.WriteLine("Thread {0} releases the semaphore.", num);
Console.WriteLine("Thread {0} previous semaphore count: {1}",
num, _pool.Release());
}
}
Imports System.Threading
Public Class Example
' A semaphore that simulates a limited resource pool.
'
Private Shared _pool As Semaphore
' A padding interval to make the output more orderly.
Private Shared _padding As Integer
<MTAThread> _
Public Shared Sub Main()
' Create a semaphore that can satisfy up to three
' concurrent requests. Use an initial count of zero,
' so that the entire semaphore count is initially
' owned by the main program thread.
'
_pool = New Semaphore(0, 3)
' Create and start five numbered threads.
'
For i As Integer = 1 To 5
Dim t As New Thread(New ParameterizedThreadStart(AddressOf Worker))
'Dim t As New Thread(AddressOf Worker)
' Start the thread, passing the number.
'
t.Start(i)
Next i
' Wait for half a second, to allow all the
' threads to start and to block on the semaphore.
'
Thread.Sleep(500)
' The main thread starts out holding the entire
' semaphore count. Calling Release(3) brings the
' semaphore count back to its maximum value, and
' allows the waiting threads to enter the semaphore,
' up to three at a time.
'
Console.WriteLine("Main thread calls Release(3).")
_pool.Release(3)
Console.WriteLine("Main thread exits.")
End Sub
Private Shared Sub Worker(ByVal num As Object)
' Each worker thread begins by requesting the
' semaphore.
Console.WriteLine("Thread {0} begins " _
& "and waits for the semaphore.", num)
_pool.WaitOne()
' A padding interval to make the output more orderly.
Dim padding As Integer = Interlocked.Add(_padding, 100)
Console.WriteLine("Thread {0} enters the semaphore.", num)
' The thread's "work" consists of sleeping for
' about a second. Each thread "works" a little
' longer, just to make the output more orderly.
'
Thread.Sleep(1000 + padding)
Console.WriteLine("Thread {0} releases the semaphore.", num)
Console.WriteLine("Thread {0} previous semaphore count: {1}", _
num, _
_pool.Release())
End Sub
End Class
Comentários
Normalmente, os threads usam o WaitOne método para inserir o semáforo e normalmente usam essa sobrecarga de método para sair.
Se um SemaphoreFullException for gerado pelo Release método, ele não indicará necessariamente um problema com o thread de chamada. Um erro de programação em outro thread pode ter feito com que esse thread saísse do semáforo mais vezes do que ele inseriu.
Se o objeto atual Semaphore representa um semáforo do sistema nomeado, o usuário deve ter SemaphoreRights.Modify direitos e o semáforo deve ter sido aberto com SemaphoreRights.Modify direitos.
Confira também
Aplica-se a
Release(Int32)
Sai do sinal de um número de vezes especificado e retorna à contagem anterior.
public:
int Release(int releaseCount);
public int Release (int releaseCount);
member this.Release : int -> int
Public Function Release (releaseCount As Integer) As Integer
Parâmetros
- releaseCount
- Int32
O número de vezes para sair do sinal.
Retornos
A contagem no sinal antes do método Release ser chamado.
Exceções
releaseCount
é menor que 1.
A contagem de semáforo já está no valor máximo.
Ocorreu um erro de Win32 com um semáforo nomeado.
O semáforo atual representa um semáforo de sistema nomeado, mas o usuário não tem direitos de Modify.
- ou - O sinal atual representa um sinal de sistema nomeado, mas não foi aberto com direitos de Modify.
Exemplos
O exemplo de código a seguir cria um semáforo com uma contagem máxima de três e uma contagem inicial de zero. O exemplo inicia cinco threads, que bloqueiam a espera pelo semáforo. O thread principal usa a sobrecarga do Release(Int32) método para aumentar a contagem de semáforos para o máximo, permitindo que três threads insiram o semáforo. Cada thread usa o Thread.Sleep método para aguardar um segundo, para simular o trabalho e, em seguida, chama a sobrecarga do Release() método para liberar o semáforo.
Cada vez que o semáforo é liberado, a contagem de semáforos anterior é exibida. As mensagens do console rastreiam o uso de semáforo. O intervalo de trabalho simulado é ligeiramente aumentado para cada thread, para facilitar a leitura da saída.
#using <System.dll>
using namespace System;
using namespace System::Threading;
public ref class Example
{
private:
// A semaphore that simulates a limited resource pool.
//
static Semaphore^ _pool;
// A padding interval to make the output more orderly.
static int _padding;
public:
static void Main()
{
// Create a semaphore that can satisfy up to three
// concurrent requests. Use an initial count of zero,
// so that the entire semaphore count is initially
// owned by the main program thread.
//
_pool = gcnew Semaphore( 0,3 );
// Create and start five numbered threads.
//
for ( int i = 1; i <= 5; i++ )
{
Thread^ t = gcnew Thread(
gcnew ParameterizedThreadStart( Worker ) );
// Start the thread, passing the number.
//
t->Start( i );
}
// Wait for half a second, to allow all the
// threads to start and to block on the semaphore.
//
Thread::Sleep( 500 );
// The main thread starts out holding the entire
// semaphore count. Calling Release(3) brings the
// semaphore count back to its maximum value, and
// allows the waiting threads to enter the semaphore,
// up to three at a time.
//
Console::WriteLine( L"Main thread calls Release(3)." );
_pool->Release( 3 );
Console::WriteLine( L"Main thread exits." );
}
private:
static void Worker( Object^ num )
{
// Each worker thread begins by requesting the
// semaphore.
Console::WriteLine( L"Thread {0} begins and waits for the semaphore.", num );
_pool->WaitOne();
// A padding interval to make the output more orderly.
int padding = Interlocked::Add( _padding, 100 );
Console::WriteLine( L"Thread {0} enters the semaphore.", num );
// The thread's "work" consists of sleeping for
// about a second. Each thread "works" a little
// longer, just to make the output more orderly.
//
Thread::Sleep( 1000 + padding );
Console::WriteLine( L"Thread {0} releases the semaphore.", num );
Console::WriteLine( L"Thread {0} previous semaphore count: {1}",
num, _pool->Release() );
}
};
using System;
using System.Threading;
public class Example
{
// A semaphore that simulates a limited resource pool.
//
private static Semaphore _pool;
// A padding interval to make the output more orderly.
private static int _padding;
public static void Main()
{
// Create a semaphore that can satisfy up to three
// concurrent requests. Use an initial count of zero,
// so that the entire semaphore count is initially
// owned by the main program thread.
//
_pool = new Semaphore(initialCount: 0, maximumCount: 3);
// Create and start five numbered threads.
//
for(int i = 1; i <= 5; i++)
{
Thread t = new Thread(new ParameterizedThreadStart(Worker));
// Start the thread, passing the number.
//
t.Start(i);
}
// Wait for half a second, to allow all the
// threads to start and to block on the semaphore.
//
Thread.Sleep(500);
// The main thread starts out holding the entire
// semaphore count. Calling Release(3) brings the
// semaphore count back to its maximum value, and
// allows the waiting threads to enter the semaphore,
// up to three at a time.
//
Console.WriteLine("Main thread calls Release(3).");
_pool.Release(releaseCount: 3);
Console.WriteLine("Main thread exits.");
}
private static void Worker(object num)
{
// Each worker thread begins by requesting the
// semaphore.
Console.WriteLine("Thread {0} begins " +
"and waits for the semaphore.", num);
_pool.WaitOne();
// A padding interval to make the output more orderly.
int padding = Interlocked.Add(ref _padding, 100);
Console.WriteLine("Thread {0} enters the semaphore.", num);
// The thread's "work" consists of sleeping for
// about a second. Each thread "works" a little
// longer, just to make the output more orderly.
//
Thread.Sleep(1000 + padding);
Console.WriteLine("Thread {0} releases the semaphore.", num);
Console.WriteLine("Thread {0} previous semaphore count: {1}",
num, _pool.Release());
}
}
Imports System.Threading
Public Class Example
' A semaphore that simulates a limited resource pool.
'
Private Shared _pool As Semaphore
' A padding interval to make the output more orderly.
Private Shared _padding As Integer
<MTAThread> _
Public Shared Sub Main()
' Create a semaphore that can satisfy up to three
' concurrent requests. Use an initial count of zero,
' so that the entire semaphore count is initially
' owned by the main program thread.
'
_pool = New Semaphore(0, 3)
' Create and start five numbered threads.
'
For i As Integer = 1 To 5
Dim t As New Thread(New ParameterizedThreadStart(AddressOf Worker))
'Dim t As New Thread(AddressOf Worker)
' Start the thread, passing the number.
'
t.Start(i)
Next i
' Wait for half a second, to allow all the
' threads to start and to block on the semaphore.
'
Thread.Sleep(500)
' The main thread starts out holding the entire
' semaphore count. Calling Release(3) brings the
' semaphore count back to its maximum value, and
' allows the waiting threads to enter the semaphore,
' up to three at a time.
'
Console.WriteLine("Main thread calls Release(3).")
_pool.Release(3)
Console.WriteLine("Main thread exits.")
End Sub
Private Shared Sub Worker(ByVal num As Object)
' Each worker thread begins by requesting the
' semaphore.
Console.WriteLine("Thread {0} begins " _
& "and waits for the semaphore.", num)
_pool.WaitOne()
' A padding interval to make the output more orderly.
Dim padding As Integer = Interlocked.Add(_padding, 100)
Console.WriteLine("Thread {0} enters the semaphore.", num)
' The thread's "work" consists of sleeping for
' about a second. Each thread "works" a little
' longer, just to make the output more orderly.
'
Thread.Sleep(1000 + padding)
Console.WriteLine("Thread {0} releases the semaphore.", num)
Console.WriteLine("Thread {0} previous semaphore count: {1}", _
num, _
_pool.Release())
End Sub
End Class
Comentários
Se um thread tiver inserido o semáforo várias vezes, essa sobrecarga de método permitirá que toda a contagem de semáforos seja restaurada com uma chamada.
Se um SemaphoreFullException for gerado pelo Release método, ele não indicará necessariamente um problema com o thread de chamada. Um erro de programação em outro thread pode ter feito com que esse thread saísse do semáforo mais vezes do que ele inseriu.
Se o objeto atual Semaphore representa um semáforo do sistema nomeado, o usuário deve ter SemaphoreRights.Modify direitos e o semáforo deve ter sido aberto com SemaphoreRights.Modify direitos.