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Type.IsAutoLayout Property

  • Reference

Definition

Namespace:
System
Assembly:
System.Runtime.dll
Assembly:
mscorlib.dll
Assembly:
netstandard.dll
Source:
Type.cs
Source:
Type.cs
Source:
Type.cs

Gets a value indicating whether the fields of the current type are laid out automatically by the common language runtime.

public:
 property bool IsAutoLayout { bool get(); };
public bool IsAutoLayout { get; }
member this.IsAutoLayout : bool
Public ReadOnly Property IsAutoLayout As Boolean

Property Value

Boolean

true if the Attributes property of the current type includes AutoLayout; otherwise, false.

Implements

IsAutoLayout

Examples

The following example creates an instance of the type and displays the IsAutoLayout property.

#using <System.dll>

using namespace System;
using namespace System::Reflection;
using namespace System::ComponentModel;
using namespace System::Runtime::InteropServices;

// The MyDemoAttribute class is selected as AutoLayout.

[StructLayoutAttribute(LayoutKind::Auto)]
public ref class MyDemoAttribute{};

void MyAutoLayoutMethod( String^ typeName )
{
   try
   {
      
      // Create an instance of the Type class using the GetType method.
      Type^ myType = Type::GetType( typeName );
      
      // Get and display the IsAutoLayout property of the
      // MyDemoAttribute instance.
      Console::WriteLine( "\nThe AutoLayout property for the MyDemoAttribute is {0}.", myType->IsAutoLayout );
   }
   catch ( Exception^ e ) 
   {
      Console::WriteLine( "\nAn exception occurred: {0}.", e->Message );
   }

}

int main()
{
   MyAutoLayoutMethod( "MyDemoAttribute" );
}

using System;
using System.Runtime.InteropServices;

// The Demo class is attributed as AutoLayout.
[StructLayoutAttribute(LayoutKind.Auto)]
public class Demo
{
}

public class Example
{
    public static void Main()
    {
        // Create an instance of the Type class using the GetType method.
        Type  myType=typeof(Demo);
        // Get and display the IsAutoLayout property of the
        // Demoinstance.
        Console.WriteLine("\nThe AutoLayout property for the Demo class is {0}.",
            myType.IsAutoLayout);
    }
}

open System.Runtime.InteropServices

// The Demo class is attributed as AutoLayout.
[<StructLayoutAttribute(LayoutKind.Auto)>]
type Demo = class end

// Create an instance of the Type class using the GetType method.
let myType = typeof<Demo>
// Get and display the IsAutoLayout property of the
// Demoinstance.
printfn $"\nThe AutoLayout property for the Demo class is {myType.IsAutoLayout}."

Imports System.Runtime.InteropServices

' The Demo class is has the AutoLayout attribute.
<StructLayoutAttribute(LayoutKind.Auto)> _
Public Class Demo
End Class 

Public Class Example
    Public Shared Sub Main()
        ' Get the Type object for the Demo class.
        Dim myType As Type = GetType(Demo)
        ' Get and display the IsAutoLayout property of the 
        ' Demo class.
        Console.WriteLine("The AutoLayout property for the Demo class is '{0}'.", _
            myType.IsAutoLayout.ToString())
    End Sub 
End Class

Remarks

This property is provided as a convenience. Alternatively, you can use the TypeAttributes.LayoutMask enumeration value to select the type layout attributes, and then test whether TypeAttributes.AutoLayout is set. The TypeAttributes.AutoLayout,TypeAttributes.ExplicitLayout, and TypeAttributes.SequentialLayout enumeration values indicate the way the fields of the type are laid out in memory.

For dynamic types, you can specify TypeAttributes.AutoLayout when you create the type. In code, apply the StructLayoutAttribute attribute with the LayoutKind.Auto enumeration value to the type, to let the runtime determine the appropriate way to lay out the class.

Note

You cannot use the GetCustomAttributes method to determine whether the StructLayoutAttribute has been applied to a type.

If the current Type represents a constructed generic type, this property applies to the generic type definition from which the type was constructed. For example, if the current Type represents MyGenericType<int> (MyGenericType(Of Integer) in Visual Basic), the value of this property is determined by MyGenericType<T>.

If the current Type represents a type parameter in the definition of a generic type or generic method, this property always returns false.

Applies to

See also