TimeOnly.AddHours Method

Definition

Overloads

AddHours(Double, Int32)

Returns a new TimeOnly that adds the specified number of hours to the value of this instance. If the result wraps past the end of the day, this method returns the number of excess days as an out parameter.

AddHours(Double)

Returns a new TimeOnly that adds the specified number of hours to the value of this instance.

AddHours(Double, Int32)

Source:
TimeOnly.cs
Source:
TimeOnly.cs
Source:
TimeOnly.cs

Returns a new TimeOnly that adds the specified number of hours to the value of this instance. If the result wraps past the end of the day, this method returns the number of excess days as an out parameter.

C#
public TimeOnly AddHours(double value, out int wrappedDays);

Parameters

value
Double

A number of whole and fractional hours. The value parameter can be negative or positive.

wrappedDays
Int32

When this method returns, contains the number of excess days, if any, that resulted from wrapping during this addition operation.

Returns

An object whose value is the sum of the time represented by this instance and the number of hours represented by value.

Applies to

.NET 10 a ďalšie verzie
Produkt Verzie
.NET 6, 7, 8, 9, 10

AddHours(Double)

Source:
TimeOnly.cs
Source:
TimeOnly.cs
Source:
TimeOnly.cs

Returns a new TimeOnly that adds the specified number of hours to the value of this instance.

C#
public TimeOnly AddHours(double value);

Parameters

value
Double

A number of whole and fractional hours. The value parameter can be negative or positive.

Returns

An object whose value is the sum of the time represented by this instance and the number of hours represented by value.

Applies to

.NET 10 a ďalšie verzie
Produkt Verzie
.NET 6, 7, 8, 9, 10