Vector<T>.BitwiseAnd(Vector<T>, Vector<T>) Operator
Definition
Important
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Returns a new vector by performing a bitwise And
operation on each of the elements in two vectors.
public:
static System::Numerics::Vector<T> operator &(System::Numerics::Vector<T> left, System::Numerics::Vector<T> right);
public static System.Numerics.Vector<T> operator & (System.Numerics.Vector<T> left, System.Numerics.Vector<T> right);
static member ( &&& ) : System.Numerics.Vector<'T (requires 'T : struct)> * System.Numerics.Vector<'T (requires 'T : struct)> -> System.Numerics.Vector<'T (requires 'T : struct)>
static member ( &&& ) : System.Numerics.Vector<'T> * System.Numerics.Vector<'T> -> System.Numerics.Vector<'T>
Public Shared Operator And (left As Vector(Of T), right As Vector(Of T)) As Vector(Of T)
Parameters
- left
- Vector<T>
The first vector.
- right
- Vector<T>
The second vector.
Returns
The vector that results from the bitwise And
of left
and right
.
Exceptions
.NET 5 and later: Type T
is not supported.
Remarks
The BitwiseAnd method defines the bitwise And
operation for Vector<T> objects.
Applies to
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