Color.FromArgb(Byte, Byte, Byte, Byte) Method

Reference

Definition

Namespace:: System.Windows.Media

Assembly:: PresentationCore.dll

Important

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Creates a new Color structure by using the specified sRGB alpha channel and color channel values.

public:
 static System::Windows::Media::Color FromArgb(System::Byte a, System::Byte r, System::Byte g, System::Byte b);

public static System.Windows.Media.Color FromArgb (byte a, byte r, byte g, byte b);

static member FromArgb : byte * byte * byte * byte -> System.Windows.Media.Color

Public Shared Function FromArgb (a As Byte, r As Byte, g As Byte, b As Byte) As Color

Parameters

a: Byte

The alpha channel, A, of the new color.

r: Byte

The red channel, R, of the new color.

g: Byte

The green channel, G, of the new color.

b: Byte

The blue channel, B, of the new color.

Returns

Color

A Color structure with the specified values.

Examples

private Color FromArgbExample()
{
    // Create a blue color using the FromArgb static method.
    Color myArgbColor = new Color();
    myArgbColor = Color.FromArgb(255, 0, 255, 0);
    return myArgbColor;
}

Private Function FromArgbExample() As Color
    ' Create a blue color using the FromArgb static method.
    Dim myArgbColor As New Color()
    myArgbColor = Color.FromArgb(255, 0, 255, 0)
    Return myArgbColor
End Function

Remarks

The FromArgb method allows you to specify the alpha channel; the FromRgb method uses a default value of 255 for the alpha channel.

The alpha channel of a color determines the amount of transparency of the color. An alpha value of 255 indicates that the color is completely opaque, and a value of 0 indicates that the color is completely transparent.

Applies to

Dela via