Vector<T>.BitwiseAnd(Vector<T>, Vector<T>) Operator
Definition
Important
Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
Returns a new vector by performing a bitwise And
operation on each of the elements in two vectors.
public:
static System::Numerics::Vector<T> operator &(System::Numerics::Vector<T> left, System::Numerics::Vector<T> right);
public static System.Numerics.Vector<T> operator & (System.Numerics.Vector<T> left, System.Numerics.Vector<T> right);
static member ( &&& ) : System.Numerics.Vector<'T (requires 'T : struct)> * System.Numerics.Vector<'T (requires 'T : struct)> -> System.Numerics.Vector<'T (requires 'T : struct)>
static member ( &&& ) : System.Numerics.Vector<'T> * System.Numerics.Vector<'T> -> System.Numerics.Vector<'T>
Public Shared Operator And (left As Vector(Of T), right As Vector(Of T)) As Vector(Of T)
Parameters
- left
- Vector<T>
The first vector.
- right
- Vector<T>
The second vector.
Returns
The vector that results from the bitwise And
of left
and right
.
Exceptions
.NET 5 and later: Type T
is not supported.
Remarks
The BitwiseAnd method defines the bitwise And
operation for Vector<T> objects.
Applies to
反馈
https://aka.ms/ContentUserFeedback。
即将发布:在整个 2024 年,我们将逐步淘汰作为内容反馈机制的“GitHub 问题”,并将其取代为新的反馈系统。 有关详细信息,请参阅:提交和查看相关反馈